Problem 19
Question
The cofactor of the elements of the second row in determinant \(\left|\begin{array}{ccc}1 & 2 & 3 \\ -4 & 3 & 6 \\ 2 & -7 & 9\end{array}\right|\) is: (a) \(-39,3,11\) (b) \(-39,3,-11\) (c) \(39,3,11\) (d) \(39,-3,11\)
Step-by-Step Solution
Verified Answer
The cofactors are \(-39, 3, 11\), answer (b).
1Step 1: Understand the Determinant Layout
The determinant given is a 3x3 matrix: \[\left|\begin{array}{ccc}1 & 2 & 3 \ -4 & 3 & 6 \ 2 & -7 & 9\end{array}\right|.\] We are asked to find the cofactors of each element in the second row, which is \(-4, 3, 6\).
2Step 2: Find the Minor of -4
The minor of an element is the determinant formed by deleting the row and column of that element. For -4 (in the second row and first column), delete the first column and second row: \[\left|\begin{array}{cc}2 & 3 \ -7 & 9\end{array}\right|.\] The determinant of this 2x2 matrix is calculated as \(2 \times 9 - 3 \times (-7) = 18 + 21 = 39\).
3Step 3: Find the Cofactor of -4
The cofactor of an element is given by \((-1)^{i+j}\) times the minor of the element, where \(i\) and \(j\) refer to the row and column indices of the element. For \(-4\) at position \((2,1)\), the sign \((-1)^{2+1} = -1\). Thus, the cofactor of \(-4\) is \(-1 \times 39 = -39\).
4Step 4: Find the Minor of 3
For 3 (second row, second column), delete the second row and column: \[\left|\begin{array}{cc}1 & 3 \ 2 & 9\end{array}\right|.\] Calculate the determinant as \(1 \times 9 - 3 \times 2 = 9 - 6 = 3\).
5Step 5: Find the Cofactor of 3
For 3 at position \((2,2)\), use the sign \((-1)^{2+2} = 1\). Thus, the cofactor of 3 is \(1 \times 3 = 3\).
6Step 6: Find the Minor of 6
For 6 (second row, third column), delete the third column and second row: \[\left|\begin{array}{cc}1 & 2 \ 2 & -7\end{array}\right|.\] Calculate the determinant as \(1 \times (-7) - 2 \times 2 = -7 - 4 = -11\).
7Step 7: Find the Cofactor of 6
For 6 at position \((2,3)\), use the sign \((-1)^{2+3} = -1\). Thus, the cofactor of 6 is \(-1 \times -11 = 11\).
Key Concepts
3x3 DeterminantMatrix MinorsDeterminant Calculation
3x3 Determinant
Understanding the concept of a 3x3 determinant can initially seem challenging, yet it is quite manageable with an organized approach. A 3x3 determinant is essentially a square matrix with three rows and three columns.
Each element in this matrix is used to perform calculations in a structured way to arrive at a specific numerical value known as the determinant. This value is crucial in various areas of linear algebra and can determine whether a matrix is invertible.
Each element in this matrix is used to perform calculations in a structured way to arrive at a specific numerical value known as the determinant. This value is crucial in various areas of linear algebra and can determine whether a matrix is invertible.
- The general form of a 3x3 matrix looks like this: \[\left|\begin{array}{ccc}a & b & c \d & e & f \g & h & i \end{array}\right|.\]
Matrix Minors
Matrix minors play a fundamental role in the calculation of determinants and cofactors. The minor of a particular element in a matrix is found by deleting the row and column that intersect at that element. This omission creates a smaller matrix, usually a 2x2 matrix for a 3x3 determinant.
For example, consider the element -4 in the second row and first column of a matrix.
Removing its row and column, we derive the minor matrix: \[\left|\begin{array}{cc}2 & 3 \-7 & 9\end{array}\right|.\]
For example, consider the element -4 in the second row and first column of a matrix.
Removing its row and column, we derive the minor matrix: \[\left|\begin{array}{cc}2 & 3 \-7 & 9\end{array}\right|.\]
- To obtain the minor, calculate the determinant of this reduced matrix, which is simplified as multiplying diagonals and subtracting the products: \[2 \times 9 - 3 \times (-7) = 18 + 21 = 39.\]
Determinant Calculation
Determinant calculation is key when working with matrices, particularly for solving equations and understanding matrix properties. For a 3x3 matrix, the determinant is calculated using a specific rule involving elements and their corresponding cofactors.
In essence, the determinant of a 3x3 matrix can be found by choosing a row or column, and then summing the products of each element with its cofactor. For instance, using elements from the first row, the determinant is:
\[ a(ei - fh) - b(di - fg) + c(dh - eg). \]
In essence, the determinant of a 3x3 matrix can be found by choosing a row or column, and then summing the products of each element with its cofactor. For instance, using elements from the first row, the determinant is:
\[ a(ei - fh) - b(di - fg) + c(dh - eg). \]
- The step-by-step approach includes:
- Selecting an element and calculating its minor.
- Determining its cofactor by considering the sign \((-1)^{i+j}\).
- Repeating for each element of a chosen row or column and summing the terms.
Other exercises in this chapter
Problem 18
Without expanding the determinant at any stage, show that $$ \left|\begin{array}{ccc} x^{2}+x & x+1 & x-2 \\ 2 x^{2}+3 x-1 & 3 x & 3 x-3 \\ x^{2}+2 x+3 & 2 x-1
View solution Problem 18
The value of determinant $$ \left|\begin{array}{ccc} 1+a & 1 & 1 \\ 1 & 1+a & 1 \\ 1 & 1 & 1+a \end{array}\right| \text { is: } $$ (a) \(a^{3}\left(1-\frac{2}{a
View solution Problem 20
If \(x^{2}+y^{2}+z^{2}=1\), then what is the value of \(\left|\begin{array}{ccc}1 & z & -y \\ -z & 1 & x \\ y & -x & 1\end{array}\right|\) is: (a) 0 (b) 1 (c) 2
View solution Problem 17
\- If \(a^{2}+b^{2}+c^{2}=-2\) and \(f(x)=\left|\begin{array}{ccc}1+a^{2} x & \left(1+b^{2}\right) x & \left(1+c^{2}\right) x \\ \left(1+a^{2}\right) x & 1+b^{2
View solution