Problem 19
Question
Suppose we wish to determine whether the set of column vectors $$ \begin{array}{r} \mathbf{v}_{1}=\left(\begin{array}{l} 4 \\ 3 \\ 2 \\ 1 \end{array}\right), \quad \mathbf{v}_{2}=\left(\begin{array}{l} 1 \\ 2 \\ 2 \\ 1 \end{array}\right), \quad \mathbf{v}_{3}=\left(\begin{array}{r} -1 \\ 1 \\ 1 \\ 1 \end{array}\right) \\ \mathbf{v}_{4}=\left(\begin{array}{l} 2 \\ 3 \\ 4 \\ 1 \end{array}\right), \quad \mathbf{v}_{5}=\left(\begin{array}{r} 1 \\ 7 \\ -5 \\ 1 \end{array}\right) \end{array} $$ is linearly dependent or linearly independent. By Definition \(7.6 .3\), if $$ c_{1} \mathbf{v}_{1}+c_{2} \mathbf{v}_{2}+c_{3} \mathbf{v}_{3}+c_{4} \mathbf{v}_{4}+c_{5} \mathbf{v}_{5}=\mathbf{0} $$ only for \(c_{1}=0, c_{2}=0, c_{3}=0, c_{4}=0, c_{5}=0\), then the set of vectors is linearly independent; otherwise the set is linearly dependent. But (4) is equivalent to the linear system $$ \begin{array}{r} 4 c_{1}+c_{2}-c_{3}+2 c_{4}+c_{5}=0 \\ 3 c_{1}+2 c_{2}+c_{3}+3 c_{4}+7 c_{5}=0 \\ 2 c_{1}+2 c_{2}+c_{3}+4 c_{4}-5 c_{5}=0 \\ c_{1}+c_{2}+c_{3}+c_{4}+c_{5}=0 \end{array} $$ Without doing any further work, explain why we can now conclude that the set of vectors is linearly dependent.
Step-by-Step Solution
VerifiedKey Concepts
Vector Spaces
In our given exercise, we deal with column vectors \( \mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3, \mathbf{v}_4, \mathbf{v}_5 \) within a vector space. Here, the addition and scaling of these vectors abide by the rules of the vector space framework. This guarantees standardized operations irrespective of the representation of vectors.
Understanding vector spaces is crucial because they provide the environment where vectors live and interact, essentially forming the foundation for concepts like linear dependence and independence as seen in our problem.
Linear Algebra
In the context of this exercise, linear algebra provides the tools to analyze and characterize the set of vectors \( \{ \mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3, \mathbf{v}_4, \mathbf{v}_5 \} \). By applying linear algebra techniques, we assess the relationships between vectors, such as determining if they form a linearly independent or dependent set.
- Linear Equations: Here, the system of equations derived from the vector set will help identify dependencies quickly.
- Matrix Representation: Vector sets can be transformed into a matrix form that organizes computation and eases the identification of dependencies.
Dimension Theory
In our exercise, each vector has four entries, hinting that they inhabit a four-dimensional space. According to the dimension theory, in a space of dimension \( n \), we can have at most \( n \) linearly independent vectors. This insight allows us to conclude quickly that a set of 5 vectors in a 4-dimensional space is surely dependent. An extra vector implies some redundancy or overlap, establishing a dependency.
The beauty of dimension theory lies in its ability to simplify complex vector relationships, aiding in the quick assessment of vector dependencies without delving into solving linear systems extensively.
Linear Independence
Vectors are said to be linearly independent if the only way they sum to the zero vector is by each vector being multiplied by zero. If even one vector can be written as a combination of others, the set is dependent.
In our case, the solution signifies that the set of vectors is dependent. This is because five vectors in a four-dimensional space imply linear dependence - by definition, you cannot have more independent directions than the space's dimension allows. The linear equations formed by the vectors affirm this dependency without needing full computation.
- An understanding of linear independence helps pinpoint redundancy, ensuring maximum efficiency in vector representation.