Problem 19
Question
Suppose that \(G\) is a solvable group with order \(n \geq 2\). Show that \(G\) contains a normal nontrivial abelian subgroup.
Step-by-Step Solution
Verified Answer
Question: Show that a solvable group of order \(n\geq 2\) contains a normal nontrivial abelian subgroup.
Answer: If the given group \(G\) is solvable, there exists a subnormal series {\(G_0, G_1, ... G_n\)} where each factor group \(G_{i}/G_{i-1}\) is abelian. Either \(G_1\) is a proper normal subgroup of \(G\) and serves as a normal nontrivial abelian subgroup, or \(G_1=G\), in which case the commutator subgroup of \(G\) must be a normal nontrivial abelian subgroup. Hence, \(G\) contains a normal nontrivial abelian subgroup.
1Step 1: Define a solvable group
A solvable group is a group \(G\) for which there exists a subnormal series such that each factor group (quotient group) is abelian. A subnormal series is a sequence of subgroups {\(G_0, G_1, ... G_n\)} such that \(G_0 \triangleleft G_1 \triangleleft \cdots \triangleleft G_n = G\) and \(G_{i-1} \triangleleft G_i\).
2Step 2: Utilize the solvable group definition
Since \(G\) is solvable, there exists a subnormal series {\(G_0, G_1, ... G_n\)} with \(G_0 \triangleleft G_1 \triangleleft \cdots \triangleleft G_n = G\) and \(G_{i}/G_{i-1}\) is abelian for all \(1\leq i\leq n\). Let \(G_1\) be the first nontrivial subgroup in this series, i.e., \(|G_1| > 1\). Now, either \(G_1\) is a proper normal subgroup of \(G\), or \(G_1 = G\).
3Step 3: Identify the normal nontrivial abelian subgroup
If \(G_1\) is a proper normal subgroup of \(G\), then \(G_0\) is a normal subgroup of \(G_1\) with \(G_1/G_0\) abelian. In this case, \(G_1\) is a normal nontrivial abelian subgroup of \(G\).
4Step 4: Handle the case when \(G_1 = G\)
If \(G_1 = G\), then \(G/G_0\) is an abelian group. Let \(H\) denote the commutator subgroup of \(G\). For any \(g, h \in G\), we have \(ghg^{-1}h^{-1} \in H\), and thus the quotient group \(G/H\) is abelian. Furthermore, since \(G\) is nontrivial, there exist elements \(g, h \in G\) such that their commutator is nontrivial, which means \(H \neq G\). As \(H\) is a proper nontrivial subgroup of \(G\), it follows that it must be a normal nontrivial abelian subgroup of \(G\) as required.
In conclusion, \(G\) contains a normal nontrivial abelian subgroup in either case.
Key Concepts
Subnormal SeriesNormal SubgroupAbelian Subgroup
Subnormal Series
A subnormal series provides a structured way to break down a group into simpler pieces. It's akin to peeling an onion, where each layer reveals a subgroup more straightforward than the last.
A subnormal series is a chain of subgroups of the original group, each one nestled within the next. Mathematically, it's expressed as a sequence \(G_0, G_1, ..., G_n\) such that \(G_0 \triangleleft G_1 \triangleleft ... \triangleleft G_n = G\). Each subgroup \(G_i\) is a normal subgroup of \(G_{i+1}\), and this sequence ends with the group itself, \(G\). What makes a subnormal series exciting is the way it interacts with group operations. For the group \(G\), you can consider the quotient groups \(G_{i+1} / G_i\), which reveal even more about the group's structure.
In the context of solvable groups, a subnormal series is crucial because the solvability is defined by the condition that each quotient \(G_{i+1} / G_i\) should be an abelian subgroup—commutative, allowing us to simplify and solve problems within the group.
A subnormal series is a chain of subgroups of the original group, each one nestled within the next. Mathematically, it's expressed as a sequence \(G_0, G_1, ..., G_n\) such that \(G_0 \triangleleft G_1 \triangleleft ... \triangleleft G_n = G\). Each subgroup \(G_i\) is a normal subgroup of \(G_{i+1}\), and this sequence ends with the group itself, \(G\). What makes a subnormal series exciting is the way it interacts with group operations. For the group \(G\), you can consider the quotient groups \(G_{i+1} / G_i\), which reveal even more about the group's structure.
In the context of solvable groups, a subnormal series is crucial because the solvability is defined by the condition that each quotient \(G_{i+1} / G_i\) should be an abelian subgroup—commutative, allowing us to simplify and solve problems within the group.
Normal Subgroup
A normal subgroup is the core concept that stabilizes group theory, creating a stable base from which other properties can be understood. Imagine a spinning top: no matter how it twirls, its center remains at the same point. Similarly, for any element \(g\) in the group \(G\), a normal subgroup \(N\) stays 'fixed' under the action of \(g\), such that \(gNg^{-1} = N\).
This quality means you can multiply every element of \(N\) by \(g\), and when you multiply them again by \(g^{-1}\), you'll land back in \(N\). It is the 'normality' of \(N\) that allows for the creation of well-defined quotient groups, which are fundamental when analyzing group properties. In terms of our original group \(G\), normal subgroups like \(G_0\) and \(G_1\) play instrumental roles because they make the structure of the entire group more accessible and navigable—providing stepping stones toward unraveling the group's deeper qualities.
This quality means you can multiply every element of \(N\) by \(g\), and when you multiply them again by \(g^{-1}\), you'll land back in \(N\). It is the 'normality' of \(N\) that allows for the creation of well-defined quotient groups, which are fundamental when analyzing group properties. In terms of our original group \(G\), normal subgroups like \(G_0\) and \(G_1\) play instrumental roles because they make the structure of the entire group more accessible and navigable—providing stepping stones toward unraveling the group's deeper qualities.
Abelian Subgroup
The notion of an abelian subgroup lies at the heart of group theory, where the dynamics of group elements simplify to resemble a peaceful conversation rather than a heated debate. In an abelian subgroup, the order of members in a group operation doesn't cause any ruckus; it’s a harmonious world where for any two elements \(a, b\), the equation \(ab = ba\) holds true.
Abelian subgroups are categorically crucial because of their propensity to play well together, allowing simplifications that more complex, non-abelian groups may not permit. They are the building blocks for constructing complex group structures, thanks to their well-behaved nature. When examining our group \(G\) from the exercise, finding an abelian subgroup is like discovering a tranquil core within a possibly chaotic system. The presence of such a subgroup, as showcased in steps 2 and 3 of the solution, is a testament to \(G\)'s solvability—showcasing its underlying orderliness despite any initial complexity.
Abelian subgroups are categorically crucial because of their propensity to play well together, allowing simplifications that more complex, non-abelian groups may not permit. They are the building blocks for constructing complex group structures, thanks to their well-behaved nature. When examining our group \(G\) from the exercise, finding an abelian subgroup is like discovering a tranquil core within a possibly chaotic system. The presence of such a subgroup, as showcased in steps 2 and 3 of the solution, is a testament to \(G\)'s solvability—showcasing its underlying orderliness despite any initial complexity.
Other exercises in this chapter
Problem 17
Suppose that \(G\) has a composition series. If \(N\) is a normal subgroup of \(G,\) show that \(N\) and \(G / N\) also have composition series.
View solution Problem 18
Let \(G\) be a cyclic \(p\) -group with subgroups \(H\) and \(K\). Prove that either \(H\) is contained in \(K\) or \(K\) is contained in \(H\).
View solution Problem 21
Suppose that \(G\) is a solvable group with order \(n \geq 2 .\) Show that \(G\) contains a normal nontrivial abelian factor group.
View solution Problem 22
Zassenhaus Lemma. \(\quad\) Let \(H\) and \(K\) be subgroups of a group \(G\). Suppose also that \(H^{*}\) and \(K^{*}\) are normal subgroups of \(H\) and \(K\)
View solution