Problem 19
Question
Solve. $$ x^{2}-13 x+36=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 4\) and \(x = 9\).
1Step 1: Identify the Quadratic Equation Structure
The equation given is \(x^2 - 13x + 36 = 0\). It is in the standard form of a quadratic equation \(ax^2 + bx + c = 0\) where \(a = 1\), \(b = -13\), and \(c = 36\).
2Step 2: Determine Factors of the Constant Term
To solve by factoring, look for two numbers that multiply to the constant term \(c = 36\) and add to the coefficient of the linear term \(b = -13\).
3Step 3: Find the Pair of Numbers
The numbers that multiply to 36 and add to -13 are -4 and -9. That is because \((-4) \times (-9) = 36\) and \((-4) + (-9) = -13\).
4Step 4: Use the Factors to Break Down the Quadratic
Rewrite the quadratic equation using the factors found: \((x - 4)(x - 9) = 0\).
5Step 5: Solve for the Roots
Set each factor equal to zero: \(x - 4 = 0\) and \(x - 9 = 0\). Solve these equations to get \(x = 4\) and \(x = 9\).
Key Concepts
Factoring MethodRoots of EquationStandard Form
Factoring Method
The factoring method is one of the key techniques to solve quadratic equations. It transforms a quadratic expression into a product of two simpler expressions. This method involves writing the quadratic equation in the form of \( ax^2 + bx + c = (x + p)(x + q) \). Here, the challenge is to find two numbers \( p \) and \( q \) that fulfill two conditions:
Once the equation is factored, each separate factor can be set to zero, giving simple equations to solve. The solutions to these simpler equations are the roots of the original quadratic equation.
- Their product must equal the constant term \( c \).
- Their sum must equal the linear coefficient \( b \).
Once the equation is factored, each separate factor can be set to zero, giving simple equations to solve. The solutions to these simpler equations are the roots of the original quadratic equation.
Roots of Equation
The roots of a quadratic equation are the values of \( x \) that satisfy the equation. Finding these roots essentially means solving the equation to find where it equals zero.
For the factored equation \( (x - 4)(x - 9) = 0 \), each factor represents a potential root. You set each to zero and solve:
For the factored equation \( (x - 4)(x - 9) = 0 \), each factor represents a potential root. You set each to zero and solve:
- \( x - 4 = 0 \) leads to the root \( x = 4 \)
- \( x - 9 = 0 \) gives the root \( x = 9 \)
Standard Form
A quadratic equation is generally expressed in its standard form as \( ax^2 + bx + c = 0 \). This format makes it easy to identify the coefficients \( a \), \( b \), and \( c \), which play crucial roles in various algebraic operations. In this standard form:
- \( a \) is the coefficient of \( x^2 \), indicating the equation's "shape" or "width."
- \( b \) is the coefficient of \( x \), influencing the equation's horizontal position.
- \( c \) is the constant term, determining the y-intercept when graphed.
Other exercises in this chapter
Problem 19
Factor each trinomial completely. If a polynomial can't be factored, write "prime." $$ 10 t-24+t^{2} $$
View solution Problem 19
Factor each trinomial completely. See Examples 1 through 5 . \(6 x^{2}-13 x y+5 y^{2}\)
View solution Problem 20
Factor each trinomial completely. $$ 4 x^{2} y^{2}-28 x y+49 $$
View solution Problem 20
The equation \(D=\frac{1}{2} n(n-3)\) gives the number of diagonals \(D\) for a polygon with \(n\) sides. For example, a polygon with 6 sides has \(D=\frac{1}{2
View solution