Problem 19
Question
Solve the equation. $$(5 x-7)(2 x+1)-10 x(x-4)=0$$
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{7}{31}\).
1Step 1: Expand the Expressions
First, we need to expand the two expressions in the given equation. Expand \((5x-7)(2x+1)\) and \(-10x(x-4)\).
2Step 2: Apply the Distributive Property
Apply the distributive property to expand \((5x-7)(2x+1)\). Multiply each term in the first parenthesis by each term in the second:\[5x \cdot 2x + 5x \cdot 1 - 7 \cdot 2x - 7 \cdot 1 = 10x^2 + 5x - 14x - 7.\]
3Step 3: Simplify the First Expansion
Combine like terms in the expanded expression:\[10x^2 + 5x - 14x - 7 = 10x^2 - 9x - 7.\]
4Step 4: Expand and Simplify the Second Term
Expand and simplify \(-10x(x-4)\) using the distributive property:\[-10x \cdot x + 10x \cdot 4 = -10x^2 + 40x.\]
5Step 5: Combine Both Parts and Simplify
Now, combine the simplified expressions from Steps 3 and 4:\[(10x^2 - 9x - 7) - (10x^2 - 40x) = 0.\]Simplify by combining like terms:\[10x^2 - 9x - 7 - 10x^2 + 40x = 31x - 7.\]Thus, the equation simplifies to:\[31x - 7 = 0.\]
6Step 6: Solve for x
To find \(x\), solve the equation:\[31x - 7 = 0.\]Add 7 to both sides:\[31x = 7.\]Divide both sides by 31:\[x = \frac{7}{31}.\]
Key Concepts
Equation solvingDistributive propertySimplifying expressions
Equation solving
Solving equations is like finding the missing piece of a puzzle. An equation tells us that two expressions are equal. To solve it, we need to manipulate the equation to isolate the unknown variable, usually referred to as \(x\). This process involves a series of logical steps that simplify the equation until the variable stands alone on one side of the equation.
For instance, take this step-by-step approach:
For instance, take this step-by-step approach:
- Identify the operations used in the equation, such as addition, subtraction, multiplication, and division.
- Work with inverse operations to reverse these actions. This helps to isolate the variable.
- Maintain balance by performing any operation on both sides of the equation.
Distributive property
The distributive property is a fundamental principle in algebra that helps in breaking down expressions with parentheses. When you see an expression like \((a + b)(c + d)\), the distributive property lets us multiply each term in the first parenthesis by each term in the second parenthesis.
Here's how it works:
Here's how it works:
- Multiply each term inside one parenthesis by every term in the other parenthesis. This can be remembered as the distributive law: \(a(b + c) = ab + ac\).
- Ensure every term is multiplied correctly to avoid mistakes in the simplification process.
Simplifying expressions
Simplifying expressions is essential to make an equation easier to solve. It involves combining like terms and reducing expressions to their simplest form. Like terms are terms that have the same variables raised to the same power.
For example:
Effective simplification ensures the equation is manageable and ready to be solved, as seen when we arrive at \(31x - 7 = 0\) after combining all parts of the expanded expressions.
For example:
- In the expression \(10x^2 + 5x - 14x - 7\), \(5x\) and \(-14x\) are like terms.
- Combine these like terms to simplify: \(5x - 14x = -9x\), leading to \(10x^2 - 9x - 7\).
Effective simplification ensures the equation is manageable and ready to be solved, as seen when we arrive at \(31x - 7 = 0\) after combining all parts of the expanded expressions.
Other exercises in this chapter
Problem 18
Exer. 1-34: Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. (a) \(i^{66}\) (b) \(i^{-55}\)
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At 6 A.M. a snowplow, traveling at a constant speed, begins to clear a highway leading out of town. At \(8 \mathrm{~A} . \mathrm{M}\). an automobile begins trav
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Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ x^{4}+5 x^{2} \geq 36 $$
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Exer. 13-20: Express the interval as an inequality in the variable \(x\). $$ (-\infty,-5) $$
View solution