Problem 19
Question
Solve each radical equation in Exercises 11–30. Check all proposed solutions. $$\sqrt{2 x+19}-8=x$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(\sqrt{2 x+19}-8=x\) is \(x = -5\).
1Step 1: Isolate the radical
Add 8 to both sides of the equation to move 8 from the right hand side, so we get \(\sqrt{2 x+19}=x+8\)
2Step 2: Square both sides to remove the square root
This gives \((\sqrt{2x+19})^2=(x+8)^2\). When we simplify it we get \(2x+19 = x^2 + 16x +64\).
3Step 3: Rearrange the equation
Get rid of x on the left and move the constant to the other side. Therefore the equation look like this: \(x^2 +16x -2x +64 -19 =0\). Then simplify and we get \(x^2 +14x +45 =0\)
4Step 4: Solve for x
Solve this quadratic equation by factorising. Therefore the factors of 45 that add up to 14 are 9 and 5. So this becomes \((x+9)(x+5)=0\). This give us \(x_1 =-9\) and \(x_2 = -5\) as potential solutions to the equation.
5Step 5: Substitute the solutions
Let's check each potential solution by plugging it into the original equation. After substituting the values it's clear that -9 is not a solution because the result inside the square root would be negative. Plugging in -5 we get that the left-hand side equals the right-hand side, hence \(-5\) is a solution to the equation.
Key Concepts
Isolate the RadicalQuadratic EquationFactorizationCheck Solutions
Isolate the Radical
When solving radical equations, the first important step is to isolate the radical expression. This means getting the term with the square root by itself on one side of the equation. For instance, in the given equation \(\sqrt{2x+19} - 8 = x\), the radical is \(\sqrt{2x+19}\). To isolate it, we need to move the -8 to the other side.
This is done by adding 8 to both sides of the equation, resulting in:
This is done by adding 8 to both sides of the equation, resulting in:
- \(\sqrt{2x+19} = x + 8\)
Quadratic Equation
Once the radical is isolated, the next step involves removing the square root. We do this by squaring both sides of the equation, aiming to eliminate the square root and deal with a simpler form. With the isolated radical \(\sqrt{2x+19} = x + 8\), squaring both sides gives us:
Now, this is a standard quadratic equation form, which can be solved using methods like factoring, completing the square, or applying the quadratic formula. Here, we choose to factor for simplicity.
- \((\sqrt{2x+19})^2 = (x + 8)^2\)
- This simplifies to: \(2x + 19 = x^2 + 16x + 64\)
Now, this is a standard quadratic equation form, which can be solved using methods like factoring, completing the square, or applying the quadratic formula. Here, we choose to factor for simplicity.
Factorization
Factorization is a method used to solve quadratic equations by expressing the quadratic as a product of two binomials. In the quadratic equation \(x^2 + 14x + 45 = 0\), our goal is to find two numbers that multiply to 45 (the constant term) and add up to 14 (the coefficient of the linear term).
The numbers 9 and 5 satisfy these conditions, so we write the quadratic as:
The numbers 9 and 5 satisfy these conditions, so we write the quadratic as:
- \((x+9)(x+5)=0\)
- \(x+9=0\) gives \(x=-9\)
- \(x+5=0\) gives \(x=-5\)
Check Solutions
After solving a radical equation, it's crucial to check the solutions because squaring both sides can introduce extraneous solutions—solutions that don't actually satisfy the original equation. We substitute each found solution back into the initial equation to verify its validity.
For our solutions, \(x = -9\) and \(x = -5\), plug them back into the original radical equation \(\sqrt{2x+19} - 8 = x\):
For our solutions, \(x = -9\) and \(x = -5\), plug them back into the original radical equation \(\sqrt{2x+19} - 8 = x\):
- For \(x = -9\): Plugging it in gives a negative value under the square root, which is not possible. So, \(-9\) is not a valid solution.
- For \(x = -5\): Substitution shows that both sides of the equation equal, confirming \(-5\) as a valid solution.
Other exercises in this chapter
Problem 18
Find each product and write the result in standard form. $$ (-7-i)(-7+i) $$
View solution Problem 18
Graph each equation in Exercises \(13-28 .\) Let \(x=-3,-2,-1,0\) \(1,2,\) and 3. $$ y=2 x-4 $$
View solution Problem 19
In Exercises 15–26, use graphs to find each set. $$ (-\infty, 5) \cap[1,8) $$
View solution Problem 19
Solve equation by the square root property. $$ 2 x^{2}-5=-55 $$
View solution