Problem 19
Question
Sketch the graph of the four-cusped hypocycloid \(x=a \sin ^{3} t, y=a \cos ^{3} t, 0 \leq t \leq 2 \pi\), and find its length. Hint: By symmetry, you can quadruple the length of the first quadrant portion.
Step-by-Step Solution
Verified Answer
The length of the four-cusped hypocycloid is \(3a\).
1Step 1: Understand Hypocycloid Parameters
We are given the parametric equations for a four-cusped hypocycloid: \(x=a \sin^3 t\) and \(y=a \cos^3 t\). The parameter \(t\) varies from \(0\) to \(2\pi\). The parameter \(a\) is the scaling factor for the curve.
2Step 2: Plotting the Curve
To sketch the hypocycloid, evaluate the parametric equations at specific values of \(t\) within \([0, 2\pi]\). First, use values like \(t = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi\). These give points: \((0, a), (a, 0), (0, -a), (-a, 0), (0, a)\) which outline the cusp locations. You can then sketch smooth curves connecting these points symmetrically.
3Step 3: Compute Derivative for Arc Length
The length of the curve from \(t_1\) to \(t_2\) can be given by the integral \(\int_{t_1}^{t_2} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt\). First, compute \(\frac{dx}{dt} = 3a \sin^2 t \cos t\) and \(\frac{dy}{dt} = -3a \cos^2 t \sin t\).
4Step 4: Simplify and Integrate for Length of Curve
Substitute these derivatives into the arc length formula to get \(\int_0^{2\pi} 3a |\sin t \cos t| \, dt\). Recognize the function is symmetric; find the length from \(0\) to \(\frac{\pi}{2}\), then multiply by 4 for the complete curve using symmetry.
5Step 5: Evaluate the Integral
The integral over one quadrant is \(\int_0^{\frac{\pi}{2}} 3a \sin t \cos t \, dt\). Use the identity \(\sin t \cos t = \frac{1}{2} \sin 2t\) to transform: \(\int_0^{\frac{\pi}{2}} \frac{3a}{2} \sin 2t \, dt\). The integral of \(\sin 2t\) is \(-\frac{1}{2} \cos 2t\), giving \(-\frac{3a}{4} [\cos 2t]_0^{\frac{\pi}{2}} = \frac{3a}{4} (1)\).
6Step 6: Compute Total Arc Length of Hypocycloid
The length from \(0\) to \(\frac{\pi}{2}\) is \(\frac{3a}{4}\). Multiply by 4 to account for all four quadrants: final arc length is \(3a\). This is the total length of the hypocycloid.
Key Concepts
Parametric EquationsArc LengthCurve Symmetry
Parametric Equations
Parametric equations are an important tool in mathematics, especially for defining curves. Instead of using a single equation like \( y = f(x) \), parametric equations describe a set of related points with two separate equations, one for each coordinate, related by a third variable, often \( t \).
This third variable is called a parameter. For the hypocycloid, the parameter \( t \) allows us to smoothly draw the curve as \( t \) varies from 0 to \( 2\pi \).
This third variable is called a parameter. For the hypocycloid, the parameter \( t \) allows us to smoothly draw the curve as \( t \) varies from 0 to \( 2\pi \).
- **Equation for \( x \)**: \( x = a \sin^3 t \)
- **Equation for \( y \)**: \( y = a \cos^3 t \)
Arc Length
Calculating the arc length of a parametric curve involves understanding the distance along the curve from one point to another. This involves a bit of calculus.
To find the total length of a curve, you essentially 'walk' along it and measure the distance you have traveled. For parametric equations, this is done with an integral that takes into account how both \( x \) and \( y \) change as \( t \) changes.The arc length \( L \) is given by: \[L = \int_{t_1}^{t_2} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt\]For our hypocycloid, we need to calculate \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \):
To find the total length of a curve, you essentially 'walk' along it and measure the distance you have traveled. For parametric equations, this is done with an integral that takes into account how both \( x \) and \( y \) change as \( t \) changes.The arc length \( L \) is given by: \[L = \int_{t_1}^{t_2} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt\]For our hypocycloid, we need to calculate \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \):
- \( \frac{dx}{dt} = 3a \sin^2 t \cos t \)
- \( \frac{dy}{dt} = -3a \cos^2 t \sin t \)
Curve Symmetry
The symmetry of a curve is a beautiful aspect that often simplifies calculations. Symmetry implies that the curve repeats its pattern in a regular way.
In the case of the four-cusped hypocycloid, the curve is symmetric about both the x and y axes, as well as the origin. This means each quadrant of the curve is a mirror image of the others.This property greatly simplifies the calculation of the arc length. Instead of directly computing the entire length from \( t = 0 \) to \( t = 2\pi \), we take advantage of the symmetry:
In the case of the four-cusped hypocycloid, the curve is symmetric about both the x and y axes, as well as the origin. This means each quadrant of the curve is a mirror image of the others.This property greatly simplifies the calculation of the arc length. Instead of directly computing the entire length from \( t = 0 \) to \( t = 2\pi \), we take advantage of the symmetry:
- Find the arc length from \( 0 \) to \( \pi/2 \) (first quadrant).
- Multiply the result by 4 to acquire the full length, since all quadrants are identical.
Other exercises in this chapter
Problem 19
A round hole of radius \(a\) is drilled through the center of a solid sphere of radius \(b\) (assume that \(b>a\) ). Find the volume of the solid that remains.
View solution Problem 19
In Problems 11-30, sketch the region bounded by the graphs of the given equations, show a typical slice, approximate its area, set up an integral, and calculate
View solution Problem 19
Find the volume of the solid generated by revolving about the \(x\)-axis the region bounded by the line \(x-2 y=0\) and the parabola \(y^{2}=4 x\).
View solution Problem 19
A cable weighing 2 pounds per foot is used to haul a 200 pound load to the top of a shaft that is 500 feet deep. How much work is done?
View solution