Problem 19
Question
Simplify the trigonometric expression. $$\frac{1+\csc x}{\cos x+\cot x}$$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(\sec x\).
1Step 1: Express in terms of basic trigonometric functions
We begin by rewriting the expression using basic trigonometric functions. Recall that \(\csc x = \frac{1}{\sin x}\) and \(\cot x = \frac{\cos x}{\sin x}\). Substitute these into the original expression:\[\frac{1+\csc x}{\cos x + \cot x} = \frac{1 + \frac{1}{\sin x}}{\cos x + \frac{\cos x}{\sin x}}.\]
2Step 2: Combine fractions in the numerator
Combine the terms in the numerator. To combine \(1\) and \(\frac{1}{\sin x}\), we use a common denominator:\[1 + \frac{1}{\sin x} = \frac{\sin x}{\sin x} + \frac{1}{\sin x} = \frac{\sin x + 1}{\sin x}.\]
3Step 3: Combine fractions in the denominator
Now, combine the terms in the denominator. We have \(\cos x + \frac{\cos x}{\sin x}\). Using a common denominator gives us:\[\cos x + \frac{\cos x}{\sin x} = \frac{\cos x \cdot \sin x}{\sin x} + \frac{\cos x}{\sin x} = \frac{\cos x \cdot \sin x + \cos x}{\sin x} = \frac{\cos x(\sin x + 1)}{\sin x}.\]
4Step 4: Simplify the expression
Now that we have common denominators, we can rewrite the expression:\[\frac{\sin x + 1}{\sin x} \div \frac{\cos x(\sin x + 1)}{\sin x}.\]When we divide fractions, we multiply by the reciprocal:\[\frac{\sin x + 1}{\sin x} \times \frac{\sin x}{\cos x(\sin x + 1)} = \frac{(\sin x + 1) \cdot \sin x}{\cos x (\sin x + 1) \cdot \sin x}.\]The \(\sin x\) in the numerator and denominator cancel, and so do \(\sin x + 1\), leaving:\[\frac{1}{\cos x} = \sec x.\]
5Step 5: Conclusion
The given trigonometric expression simplifies to \(\sec x\). Thus, the original expression reduces to the secant function of \(\cos x\).
Key Concepts
Basic Trigonometric IdentitiesTrigonometric FunctionsSecant Function
Basic Trigonometric Identities
Trigonometric identities are like a toolkit for working with angles and sides in a triangle, particularly in the context of a right triangle. These identities help us understand the relationships between the different trigonometric functions. Some of the most common identities are:
- Sine and cosine are fundamental, defining relationships between the angles and sides of a triangle.
- The reciprocal identities present another layer: for example, \( \csc x = \frac{1}{\sin x} \) and \( \sec x = \frac{1}{\cos x} \).
- Other helpful identities include tangent and cotangent, where \( \tan x = \frac{\sin x}{\cos x} \) and \( \cot x = \frac{\cos x}{\sin x} \).
Trigonometric Functions
Trigonometric functions are essential in understanding angles and their relationships in various fields, from physics to geometry. These functions—sine, cosine, tangent, cosecant, secant, and cotangent—are ratios of different sides of a right triangle.
- Sine (\( \sin \)): the ratio of the opposite side to the hypotenuse.
- Cosine (\( \cos \)): the ratio of the adjacent side to the hypotenuse.
- Tangent (\( \tan \)): the ratio of the opposite side to the adjacent side.
- Cosecant (\( \csc \)): the reciprocal of sine.
- Secant (\( \sec \)): the reciprocal of cosine.
- Cotangent (\( \cot \)): the reciprocal of tangent.
Secant Function
The secant function, denoted as \( \sec x \), is one of the reciprocal trigonometric functions. It's defined as the reciprocal of the cosine function: \( \sec x = \frac{1}{\cos x} \).
The significance of the secant function emerges in various practical applications. It's particularly useful when dealing with angles greater than 90 degrees, where cosine and other functions might be less intuitive to work with.
The significance of the secant function emerges in various practical applications. It's particularly useful when dealing with angles greater than 90 degrees, where cosine and other functions might be less intuitive to work with.
- In many instances, such as simplifying expressions, introducing \( \sec x \) provides a simpler or more coherent result.
- Knowing how to switch between \( \cos x \) and \( \sec x \) enhances our problem-solving abilities, enabling more streamlined solutions.
Other exercises in this chapter
Problem 19
Solve the given equation, and list six specific solutions. $$\sin \theta=\frac{\sqrt{2}}{2}$$
View solution Problem 19
Use an Addition or Subtraction Formula to write the expression as a trigonometric function of one number, and then find its exact value. $$\frac{\tan 73^{\circ}
View solution Problem 20
Use an appropriate Half-Angle Formula to find the exact value of the expression. $$\sin 75^{\circ}$$
View solution Problem 20
Solve the given equation, and list six specific solutions. $$\sin \theta=-\frac{\sqrt{3}}{2}$$
View solution