Problem 19
Question
Simplify each expression. Assume that all variables represent positive real numbers. $$\left(\frac{27}{64}\right)^{-4 / 3}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{256}{81} \).
1Step 1: Apply the Negative Exponent Rule
The Negative Exponent Rule states that for any non-zero number \( a \), \( a^{-m} = \frac{1}{a^m} \). Applying this to our expression, we get: \[ \left( \frac{27}{64} \right)^{-\frac{4}{3}} = \frac{1}{\left( \frac{27}{64} \right)^{\frac{4}{3}}} \]
2Step 2: Simplify Inside the Exponent
To simplify \( \left( \frac{27}{64} \right)^{\frac{4}{3}} \), we first find the cube root of the base fraction and then raise it to the fourth power. Begin by evaluating the cube roots: \[ \sqrt[3]{\frac{27}{64}} = \frac{\sqrt[3]{27}}{\sqrt[3]{64}} = \frac{3}{4} \]
3Step 3: Raise the Result to the Fourth Power
Now, raise the result from Step 2 to the fourth power: \(\left(\frac{3}{4}\right)^{4}=\frac{3^4}{4^4}\) Calculate this: \[\frac{3^4}{4^4} = \frac{81}{256}\]
4Step 4: Invert the Result from Step 3
Since we initially applied the negative exponent rule in Step 1, we now take the reciprocal of our result from Step 3: \[ \frac{1}{\left( \frac{81}{256} \right)} = \frac{256}{81} \]
Key Concepts
Simplifying FractionsCube RootRaising to a PowerExponentiation Steps
Simplifying Fractions
Simplifying fractions involves reducing a fraction to its simplest form so that the numerator and denominator have no common factors other than 1. To do this, follow a few simple steps:
Additionally, operating with simpler numbers generally makes the processes like finding roots or powers easier to handle.
- Find the greatest common divisor (GCD) of the numerator and the denominator.
- Divide both the numerator and the denominator by the GCD.
- The result is your simplified fraction.
Additionally, operating with simpler numbers generally makes the processes like finding roots or powers easier to handle.
Cube Root
The cube root is used to determine which number multiplied by itself three times will give the original number. Basically, for a number \( a \), its cube root is \( a^{1/3} \). Assuming we have a fraction, like \( \frac{27}{64} \), we can find its cube root by separately taking the cube root of the numerator and the cube root of the denominator:
- The cube root of 27 is 3, because \( 3^3 = 27 \).
- The cube root of 64 is 4, because \( 4^3 = 64 \).
Raising to a Power
Raising a number to a power involves multiplying the number by itself a specified number of times, noted as an exponent. For example, raising \( \frac{3}{4} \) to the fourth power means multiplying \( \frac{3}{4} \) by itself four times:
- \( \frac{3}{4} \times \frac{3}{4} \times \frac{3}{4} \times \frac{3}{4} \)
- \( 3^4 = 81 \)
- \( 4^4 = 256 \)
Exponentiation Steps
Exponentiation processes require a few logical steps to ease understanding and correctness, particularly when dealing with fractions and complicated exponents. In the expression \( \left(\frac{27}{64}\right)^{-\frac{4}{3}} \), these steps follow a systematic approach:
- First, apply the negative exponent rule: converting \( a^{-m} \) to \( \frac{1}{a^m} \).
- Next, simplify where possible. In our case, start with finding the cube root of the fraction.
- Then, raise the simplified base to the indicated power. This means handling exponents like \( \left(\frac{3}{4}\right)^4 \).
- Finally, apply any inverses as required by negative exponents initially set in the expression.
Other exercises in this chapter
Problem 18
Identify each expression as a polynomial or not a polynomial. For each polynomial, give the degree and identify it as a monomial, binomial, trinomial, or none o
View solution Problem 19
Answer each question. For what values of \(x\) is \(\sqrt{9 a x^{2}}=3 x \sqrt{a}\) a true statement? Assume that \(a \geq 0\)
View solution Problem 19
Layla factored \(16 a^{2}-40 a-6 a+15\) by grouping and got an answer of \((8 a-3)(2 a-5) .\) Jamal factored the same polynomial and obtained \((3-8 a)(5-2 a) .
View solution Problem 19
Write each rational expression in lowest terms. $$\frac{8 m^{2}+6 m-9}{16 m^{2}-9}$$
View solution