Problem 19
Question
Simplify each complex rational expression. In each case, list any values of the variables for which the fractions are not defined. \(\frac{\frac{1}{a}-1}{1-\frac{1}{a}}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(-1\), undefined for \(a = 0\) and \(a = 1\).
1Step 1: Understand the Expression
The expression given is a complex rational expression, which has a fraction in both the numerator and the denominator: \(\frac{\frac{1}{a} - 1}{1 - \frac{1}{a}}\). We want to simplify this expression.
2Step 2: Find a Common Denominator
The key to simplifying a complex fraction is to find a common denominator for the fractions in both the numerator and the denominator. In this case, both the terms \(\frac{1}{a} - 1\) and \(1 - \frac{1}{a}\) have a common denominator \(a\).
3Step 3: Rewrite Fractions Over a Common Denominator
Rewrite the expression so that each part of the numerator and denominator has the common denominator \(a\): - Numerator: \( \frac{1}{a} - 1 = \frac{1 - a}{a} \)- Denominator: \( 1 - \frac{1}{a} = \frac{a - 1}{a} \)
4Step 4: Simplify the Complex Fraction
Using the common denominator structure, we can rewrite the original expression as a division of two fractions: \[\frac{\frac{1-a}{a}}{\frac{a-1}{a}}\]. This simplifies to: \[\frac{1-a}{a} \div \frac{a-1}{a} = \frac{1-a}{a-1}\times\frac{a}{a} = \frac{1-a}{a-1}.\]
5Step 5: Simplify the Expression Further
Notice that \(1-a\) can be rewritten as \(-(a-1)\). Thus, \[\frac{1-a}{a-1} = \frac{-(a-1)}{a-1} = -1.\] The expression simplifies to \(-1\) as long as \(1-a eq 0 \rightarrow a eq 1\).
6Step 6: Determine Undefined Values
For the original expression, factors like \(a-1=0\) or \(a=0\) make the denominators zero. Therefore, the values of \(a\) for which the expression is undefined are \(a = 1\) and \(a = 0\).
Key Concepts
Common DenominatorUndefined ValuesSimplification Steps
Common Denominator
When dealing with complex rational expressions, one of the initial and crucial steps is finding a common denominator.
This process is essential because it allows us to work with equivalent fractions, making them easier to combine or compare. In the given expression, we have
This process is essential because it allows us to work with equivalent fractions, making them easier to combine or compare. In the given expression, we have
- Numerator: \( \frac{1}{a} - 1 \)
- Denominator: \( 1 - \frac{1}{a} \)
- Numerator: \( \frac{1-a}{a} \)
- Denominator: \( \frac{a-1}{a} \)
Undefined Values
Understanding where an expression becomes undefined is crucial in mathematics, especially with rational expressions. For the expression \( \frac{\frac{1}{a} - 1}{1 - \frac{1}{a}} \), undefined values occur when either the original or rewritten denominator equals zero.
For the given expression:
For the given expression:
- \( 1 - \frac{1}{a} = \frac{a-1}{a} \)
- The expression \( \frac{1-a}{a-1} \) becomes undefined when \( a - 1 = 0 \), which implies \( a = 1 \).
- Additionally, \( a = 0 \) also makes the expression undefined because of the division by zero in the rewriting steps.
Simplification Steps
Simplifying complex rational expressions involves a clear, ordered set of steps to transform the expression into a more manageable form. Starting from our complex fraction:1. **Rewrite the expression with a common denominator.**
Both numerator and denominator of the larger fraction adopt their common form, \( \frac{1-a}{a} \) over \( \frac{a-1}{a} \).2. **Simplify using division of fractions.**
With a common denominator in place, the division of fractions now transforms into a multiplication problem: \[\frac{\frac{1-a}{a}}{\frac{a-1}{a}} = \frac{1-a}{a-1} \]3. **Further reduce by recognizing equivalent forms.**
Notice that \(1-a\) is equivalent to \(-(a-1)\). Using this identity allows us to rewrite: \[\frac{-(a-1)}{a-1} = -1\] Remember to check for cases where \(1-a eq 0\), ensuring \(a eq 1\).Going through these simplification steps with care and precision reveals that our complex expression ultimately simplifies to simply \(-1\), based on the conditions discussed earlier.
Both numerator and denominator of the larger fraction adopt their common form, \( \frac{1-a}{a} \) over \( \frac{a-1}{a} \).2. **Simplify using division of fractions.**
With a common denominator in place, the division of fractions now transforms into a multiplication problem: \[\frac{\frac{1-a}{a}}{\frac{a-1}{a}} = \frac{1-a}{a-1} \]3. **Further reduce by recognizing equivalent forms.**
Notice that \(1-a\) is equivalent to \(-(a-1)\). Using this identity allows us to rewrite: \[\frac{-(a-1)}{a-1} = -1\] Remember to check for cases where \(1-a eq 0\), ensuring \(a eq 1\).Going through these simplification steps with care and precision reveals that our complex expression ultimately simplifies to simply \(-1\), based on the conditions discussed earlier.
Other exercises in this chapter
Problem 18
Write each rational expression in simplest form and list the values of the variables for which the fraction is undefined. \(\frac{8 a b-4 b^{2}}{6 a b}\)
View solution Problem 18
In \(13-22,\) write each decimal as a common fraction. $$ 0.15 \overline{6} $$
View solution Problem 19
In \(3-20\) , perform the indicated additions or subtractions and write the result in simplest form. In each case, list any values of the variables for which th
View solution Problem 19
In \(3-20,\) solve each equation and check. $$ \frac{4}{y+2}=1-\frac{8}{y(y+2)} $$
View solution