Problem 19
Question
Show that the functions that have exactly one zero in the given interval. $$f(x)=x^{4}+3 x+1, \quad[-2,-1]$$
Step-by-Step Solution
Verified Answer
The function has exactly one zero in the interval \([-2, -1]\).
1Step 1: Verify the continuity of the function
The function \( f(x) = x^4 + 3x + 1 \) is a polynomial function, which is continuous everywhere. Hence, it is continuous in the interval \([-2, -1]\).
2Step 2: Evaluate the function at the interval boundaries
Calculate \( f(-2) \) and \( f(-1) \).\[ f(-2) = (-2)^4 + 3(-2) + 1 = 16 - 6 + 1 = 11 \]\[ f(-1) = (-1)^4 + 3(-1) + 1 = 1 - 3 + 1 = -1 \]Thus, \( f(-2) = 11 \) and \( f(-1) = -1 \).
3Step 3: Apply the Intermediate Value Theorem (IVT)
Since \( f(x) \) is continuous and \( f(-2) > 0 \) while \( f(-1) < 0 \), the Intermediate Value Theorem tells us there must be at least one zero in \((-2, -1)\) where the function changes sign.
4Step 4: Check the uniqueness of the zero
To confirm uniqueness, let's examine the function's behaviour.Calculate the derivative: \[ f'(x) = 4x^3 + 3 \]The derivative is always positive for \( x \in [-2, -1] \) because \( 4x^3 + 3 > 0 \) due to the dominant \( +3 \). Therefore, \( f(x) \) is strictly increasing on \([-2, -1]\).Since the function is strictly increasing and crosses the x-axis only once, it has exactly one zero in the interval.
Key Concepts
Polynomial FunctionContinuityStrictly Increasing Function
Polynomial Function
A polynomial function is a type of mathematical expression that involves sums of powers of variables, each multiplied by coefficients. The general form of a polynomial function is:
In our exercise, the given function \(f(x) = x^4 + 3x + 1\) is a polynomial function with a degree of 4, since the highest power of \(x\) is 4. It is continuous by nature, which is crucial for applying the Intermediate Value Theorem later.
- a_n \cdot x^n + a_{n-1} \cdot x^{n-1} + ... + a_1 \cdot x + a_0
- \(x\) is the variable,
- \(a_n, a_{n-1}, ..., a_0\) are the coefficients, and
- \(n\) is the highest power, known as the degree of the polynomial.
In our exercise, the given function \(f(x) = x^4 + 3x + 1\) is a polynomial function with a degree of 4, since the highest power of \(x\) is 4. It is continuous by nature, which is crucial for applying the Intermediate Value Theorem later.
Continuity
Continuity is a fundamental concept in mathematics, especially when dealing with functions like polynomials. In simple terms, a function is said to be continuous on an interval if you can draw it without taking your pen off the paper.
Mathematically, for a function to be continuous at a point \(c\), it must satisfy three conditions:
In the given exercise, the function \(f(x) = x^4 + 3x + 1\) is continuous on the interval \([-2, -1]\) without any interruptions. This property is crucial when applying the Intermediate Value Theorem to show that the function has at least one zero in the interval.
Mathematically, for a function to be continuous at a point \(c\), it must satisfy three conditions:
- The function \(f(x)\) must be defined at \(x = c\).
- The limit of \(f(x)\) as \(x\) approaches \(c\) from both sides must exist.
- The limit must equal \(f(c)\).
In the given exercise, the function \(f(x) = x^4 + 3x + 1\) is continuous on the interval \([-2, -1]\) without any interruptions. This property is crucial when applying the Intermediate Value Theorem to show that the function has at least one zero in the interval.
Strictly Increasing Function
A strictly increasing function is a type of function where the output value increases as the input value increases across a certain interval.
Formally, if \(f(x)\) is strictly increasing on an interval, then for any two numbers \(x_1\) and \(x_2\) in that interval, if \(x_1 < x_2\), it must be that \(f(x_1) < f(x_2)\). This means the function never dips or flattens out; it steadily climbs as you move from left to right on the graph.
This characteristic helps assert that the function crosses the x-axis only once, verifying that it has exactly one zero, which is especially useful for determining the uniqueness of the zero in the specified interval.
Formally, if \(f(x)\) is strictly increasing on an interval, then for any two numbers \(x_1\) and \(x_2\) in that interval, if \(x_1 < x_2\), it must be that \(f(x_1) < f(x_2)\). This means the function never dips or flattens out; it steadily climbs as you move from left to right on the graph.
- The derivative of the function, when positive, is a strong indicator of a strictly increasing function.
This characteristic helps assert that the function crosses the x-axis only once, verifying that it has exactly one zero, which is especially useful for determining the uniqueness of the zero in the specified interval.
Other exercises in this chapter
Problem 19
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