Problem 19
Question
Perform the indicated operations and simplify. \((3 x-9)(2 x+1)\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(6x^2 - 15x - 9\).
1Step 1: Apply the Distributive Property
To solve the expression \((3x - 9)(2x + 1)\), we start by applying the distributive property: Multiply each term in the first binomial by each term in the second binomial. This will give us four separate products. Let's perform these multiplications:1. \((3x) \cdot (2x) = 6x^2\)2. \((3x) \cdot 1 = 3x\)3. \(-9 \cdot (2x) = -18x\)4. \(-9 \cdot 1 = -9\)So, the expression now becomes \(6x^2 + 3x - 18x - 9\).
2Step 2: Combine Like Terms
Now, we need to simplify the expression \(6x^2 + 3x - 18x - 9\) by combining like terms. The like terms here are the ones with the variable \(x\) : \(3x\) and \(-18x\).Combine them as follows:\(3x - 18x = -15x\)Thus, the expression simplifies to: \(6x^2 - 15x - 9\).
3Step 3: State the Final Simplified Expression
After combining like terms, we arrive at the final simplified expression:\[6x^2 - 15x - 9\]
Key Concepts
Distributive PropertyCombining Like TermsSimplifying Expressions
Distributive Property
The distributive property is a fundamental algebraic principle used especially in polynomial multiplication. It allows one to multiply a single term across a sum or a difference within parentheses. When you have an expression like \(a (b + c)\), you apply the distributive property by multiplying \(a\) with \(b\) and \(c\) separately. This results in the expression \(ab + ac\).
In the example exercise, we use this property to multiply each term in the first binomial \(3x - 9\) by each term in the second binomial \(2x + 1\). This operation generates individual products:
In the example exercise, we use this property to multiply each term in the first binomial \(3x - 9\) by each term in the second binomial \(2x + 1\). This operation generates individual products:
- expressing \(3x \cdot 2x = 6x^2\)
- expressing \(3x \cdot 1 = 3x\)
- expressing \(-9 \cdot 2x = -18x\)
- expressing \(-9 \cdot 1 = -9\)
Combining Like Terms
Combining like terms is a technique used to simplify expressions by consolidating terms that have the same variable components. In a polynomial expression, like terms contain the same variable raised to the same power.
From our previous steps, we obtain the expression \(6x^2 + 3x - 18x - 9\). Here, the like terms involving the variable \(x\) are \(3x\) and \(-18x\). When you combine them, you simply add or subtract the coefficients. The process is as follows:
From our previous steps, we obtain the expression \(6x^2 + 3x - 18x - 9\). Here, the like terms involving the variable \(x\) are \(3x\) and \(-18x\). When you combine them, you simply add or subtract the coefficients. The process is as follows:
- expressing \(3x\) and \(-18x\)
- Combine: \(3x - 18x = -15x\)
- After combining, our expression becomes: \(6x^2 - 15x - 9\)
Simplifying Expressions
Once all possible combinations of like terms have been made, the final step is to simplify the expression. A simplified expression is one that is concise and easy to interpret, containing no further possible reductions.
Taking our combined expression \(6x^2 - 15x - 9\), there are no more like terms to combine. The expression now consists of terms each with different powers: \(6x^2\) for the quadratic term, \(-15x\) for the linear term, and \(-9\) as the constant.
At this stage:
Taking our combined expression \(6x^2 - 15x - 9\), there are no more like terms to combine. The expression now consists of terms each with different powers: \(6x^2\) for the quadratic term, \(-15x\) for the linear term, and \(-9\) as the constant.
At this stage:
- Verify each term is fully simplified and distinct
- Ensure no further distributive actions or combinations can be made
- Look for any opportunities to factor further, though in this case, none are applicable beyond the simplest form
Other exercises in this chapter
Problem 19
In Problems 15-30, specify whether the given function is even, odd, or neither, and then sketch its graph. \(g(x)=3 x^{2}+2 x-1\)
View solution Problem 19
Express the solution set of the given inequality in interval notation and sketch its graph. $$ \frac{1}{3 x-2} \leq 4 $$
View solution Problem 20
in Problems 17-22, find the center and radius of the circle with the given equation. \(x^{2}+y^{2}-10 x+10 y=0\)
View solution Problem 20
$$ \text { In Problems 17-24, solve for } x . \text { Hint: } \log _{a} b=c \Leftrightarrow a^{c}=b \text {. } $$ $$ \log _{x} 64=4 $$
View solution