Problem 19
Question
One card is randomly drawn from a deck of 52 playing cards. What is the probability that it is not an ace? \(\frac{12}{13}\)
Step-by-Step Solution
Verified Answer
The probability of drawing a card that is not an ace from a standard deck is \( \frac{12}{13} \).
1Step 1: Identify the Total Number of Cards
A standard deck of playing cards contains 52 cards in total. These include cards of four suits: hearts, diamonds, clubs, and spades.
2Step 2: Identify the Number of Aces
There are 4 aces in a standard deck of 52 cards. This includes one ace from each suit.
3Step 3: Calculate the Probability of Drawing an Ace
The probability of drawing an ace is calculated by dividing the number of aces by the total number of cards:\[ P(\text{Ace}) = \frac{4}{52} = \frac{1}{13} \]
4Step 4: Calculate the Probability of Not Drawing an Ace
The probability of an event not happening is 1 minus the probability that the event does happen. Thus, the probability of not drawing an ace is:\[ P(\text{Not Ace}) = 1 - \frac{1}{13} = \frac{12}{13} \]
Key Concepts
Probability CalculationPlaying Cards ProbabilityEvent Complement Rule
Probability Calculation
Probability is a measure of how likely an event is to occur. It ranges from 0 to 1, where 0 means the event is impossible, and 1 means it is certain. To calculate the probability of an event, you can use the formula:
With this calculation, you can determine the chance of drawing a specific card, winning a game, or predicting the weather. In our case, figuring out the probability of drawing an ace from a deck of cards involves counting the total favorable outcomes (aces) compared to the possible outcomes (all cards).
Mastering probability calculations will enhance your decision-making in situations involving chance.
- Probability (P) = (Number of Favorable Outcomes) / (Total Number of Possible Outcomes)
With this calculation, you can determine the chance of drawing a specific card, winning a game, or predicting the weather. In our case, figuring out the probability of drawing an ace from a deck of cards involves counting the total favorable outcomes (aces) compared to the possible outcomes (all cards).
Mastering probability calculations will enhance your decision-making in situations involving chance.
Playing Cards Probability
When it comes to calculating probability with playing cards, it's important to know some basic facts about a standard deck. A standard deck contains 52 cards, split into four suits: hearts, diamonds, clubs, and spades, each with 13 cards.
Understanding this simple, foundational math helps you estimate the outcomes of drawing any set of cards from a deck, making you a better strategist in card games.
- Each suit includes one ace, one king, one queen, and one jack, plus cards numbered 2 through 10.
- There are four aces in total in a standard deck.
Understanding this simple, foundational math helps you estimate the outcomes of drawing any set of cards from a deck, making you a better strategist in card games.
Event Complement Rule
The Event Complement Rule is a useful principle in probability. It revolves around finding the probability that an event does not happen. The complement of an event A is the event that A does not occur, denoted by \( A' \). Its probability is calculated using:
In our card example, we wanted to know the probability of not drawing an ace. First, calculate the probability of drawing an ace, \[P(\text{Ace}) = \frac{1}{13} \]Then, subtract this from 1 to find \[P(\text{Not Ace}) = 1 - \frac{1}{13} = \frac{12}{13} \]This concept is particularly handy when dealing with complex probability scenarios, as it often simplifies calculations.
- \( P(A') = 1 - P(A) \)
In our card example, we wanted to know the probability of not drawing an ace. First, calculate the probability of drawing an ace, \[P(\text{Ace}) = \frac{1}{13} \]Then, subtract this from 1 to find \[P(\text{Not Ace}) = 1 - \frac{1}{13} = \frac{12}{13} \]This concept is particularly handy when dealing with complex probability scenarios, as it often simplifies calculations.
Other exercises in this chapter
Problem 18
Find the probability of rolling each of the following events:A sum of \(11 \quad \frac{1}{18}\)
View solution Problem 19
Aimée, Brenda, Chuck, Dave, and Eli are randomly seated in a row of five seats. Find the probability that Aimée and Chuck are not seated side by side. \(\frac{3
View solution Problem 19
In how many ways can \(\mathrm{Al}, \mathrm{Bob}\), Carol, Dawn, and Ed be seated in a row of five chairs if \(\mathrm{Al}\) is to be seated in the middle chair
View solution Problem 19
Solve each problem.One card is randomly drawn from a deck of 52 playing cards. What is the probability that it is not an ace? \(\frac{12}{13}\)
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