Problem 19
Question
Mortgage Dr. Gupta is considering a 30 -year mortgage at 6\(\%\) interest. She can make payments of \(\$ 3500\) a month. What size loan can she afford?
Step-by-Step Solution
Verified Answer
Dr. Gupta can afford a loan of approximately \(\$583,800\).
1Step 1: Understanding the Problem
Dr. Gupta wants to know how much she can borrow given a monthly payment, interest rate, and loan length. The formula to use is for monthly mortgage payments.
2Step 2: Set Up the Formula
The mortgage payment formula is: \[P = \frac{M \times (1 - (1 + r)^{-n})}{r}\]where \( P \) is the principal loan amount, \( M \) is the monthly payment, \( r \) is the monthly interest rate, and \( n \) is the total number of payments.
3Step 3: Convert Terms to Formula Compatible Units
The annual interest rate is 6\(\%\), so the monthly interest rate \( r \) is \(\frac{6}{100 \times 12}\). The loan term is 30 years, so the number of monthly payments \( n \) is \(30 \times 12\).
4Step 4: Calculate the Monthly Interest Rate
Convert the annual interest rate to a monthly rate: \[r = \frac{0.06}{12} = 0.005\]
5Step 5: Calculate Total Number of Payments
Calculate the total number of payments for the 30-year loan: \[n = 30 \times 12 = 360\]
6Step 6: Plug Values into the Formula
Substitute the known values into the mortgage payment formula: \[P = \frac{3500 \times (1 - (1 + 0.005)^{-360})}{0.005}\]
7Step 7: Perform the Calculations
First, calculate the term inside the parentheses: \[(1 + 0.005)^{-360} \approx 0.1660\]This gives \[P = \frac{3500 \times (1 - 0.1660)}{0.005} \approx \frac{3500 \times 0.8340}{0.005}\] \ Solve for \(P\): \[P \approx \frac{2919}{0.005} = 583,800\]
8Step 8: Interpretation
Dr. Gupta can afford a loan of approximately \(\$583,800\) with her monthly payment and interest rate.
Key Concepts
Interest RateMonthly PaymentLoan TermPrincipal Loan Amount
Interest Rate
Interest rate is a crucial part of mortgage calculations. It represents the cost of borrowing money. In simple terms, when a bank loans you money, they charge interest for lending it to you. This interest is usually given as an annual percentage rate (APR), which shows what percentage of the loan amount you need to pay back each year as interest.
In the case of Dr. Gupta's mortgage, the interest rate is 6\(\%\), which is an annual rate. To calculate the monthly interest rate, we need to divide the annual rate by 12 months. This gives us 0.5\(\%\) per month, or in decimal form:
In the case of Dr. Gupta's mortgage, the interest rate is 6\(\%\), which is an annual rate. To calculate the monthly interest rate, we need to divide the annual rate by 12 months. This gives us 0.5\(\%\) per month, or in decimal form:
- Monthly Interest Rate, \(r\) = \( \frac{6}{100 \times 12} = 0.005\)
Monthly Payment
Monthly payment is the fixed amount paid by the borrower each month to repay the loan. It includes both interest and a portion of the principal loan amount. For a mortgage, this is often set at a consistent rate for the life of the loan, making budgeting easier.
To calculate what loan size is affordable, the monthly payment amount is used alongside the interest rate and the loan term in the mortgage payment formula.
- In Dr. Gupta's situation, her monthly payment is \(\$3500\).
To calculate what loan size is affordable, the monthly payment amount is used alongside the interest rate and the loan term in the mortgage payment formula.
Loan Term
The loan term is the amount of time over which you will repay the loan. It is usually presented in years, and common terms for mortgages range from 15 to 30 years. The loan term influences both the amount you can borrow and your monthly payment.
A longer loan term typically means:
A longer loan term typically means:
- Lower monthly payments because the repayment is spread over many years.
- More interest paid over the life of the loan since interest accumulates over a more extended period.
Principal Loan Amount
The principal loan amount is the total amount borrowed at the beginning of the mortgage. It is the initial amount you receive from the lender, not including interest. This is essentially the part of the mortgage that needs to be paid back, with interest being the cost of borrowing it.
To calculate the maximum principal loan amount Dr. Gupta can afford, we use a specific formula taking into account her monthly payment, interest rate, and total number of payments.
To calculate the maximum principal loan amount Dr. Gupta can afford, we use a specific formula taking into account her monthly payment, interest rate, and total number of payments.
- Using the mortgage payment formula, she can afford a principal amount, \(P\), approximated as \(\$583,800\).
Other exercises in this chapter
Problem 19
Evaluate the expression. $$ \left(\begin{array}{c}{100} \\ {98}\end{array}\right) $$
View solution Problem 19
Show that \(8^{n}-3^{n}\) is divisible by 5 for all natural numbers \(n\)
View solution Problem 20
\(13-20\) . Determine whether the sequence is arithmetic. If is arithmetic, find the common difference. $$ \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \
View solution Problem 20
Determine whether the sequence is geometric. If is geometric, find the common ratio. $$ \frac{1}{2}, \frac{1}{4}, \frac{1}{6}, \frac{1}{8}, \dots $$
View solution