Problem 19
Question
In Exercises 19-22, graphically estimate the \( x \)- and \( y \)-intercepts of the graph. Verify your results algebraically. \( y = (x-3)^2 \)
Step-by-Step Solution
Verified Answer
The x-intercept of the function \( y = (x-3)^2 \) is 3 and the y-intercept is 9. This solution was both graphically estimated and algebraically verified.
1Step 1: Estimate graphically
Begin by sketching a graph of the function \( y = (x-3)^2 \). The graph is a parabola that opens upwards with its vertex at the point (3,0). From the graph, it may be estimated that the x-intercept is 3 and the y-intercept is 9.
2Step 2: Verify algebraically: x-intercept
To find the x-intercept, the equation \( y = (x-3)^2 \) is set to be equal to zero:0 = (x-3)^2. Solving this, we find x-3 = 0, which implies x = 3. Thus, the x-intercept of the function is 3 as estimated from the graph.
3Step 3: Verify algebraically: y-intercept
To find the y-intercept of the function, the value of y is determined when x=0. Substituting x = 0 into the equation \( y = (x-3)^2 \) gives:y = (0-3)^2 = 9.Hence, the y-intercept is 9. This confirms the graphical estimate.
Key Concepts
Graphing FunctionsAlgebraic VerificationParabolas
Graphing Functions
Graphing functions is a foundational math skill that helps visualize equations. When graphing a function, like the parabola described by \( y = (x-3)^2 \), plot enough points to capture its shape. For parabolas, identify key features such as:
- The vertex: the top or bottom point of the parabola. In this case, it's (3,0).
- The axis of symmetry: a vertical line through the vertex, guiding the parabola's balance. Here, it's \( x = 3 \).
- Intercepts: points where the graph crosses the axes. Estimate these carefully on your sketched graph.
Algebraic Verification
Algebraic verification is a powerful method to confirm graphical estimates. This involves using algebraic techniques to validate features like intercepts. For instance:
- Finding x-intercepts involves setting \( y = 0 \). For \( y = (x-3)^2 \), solving \( 0 = (x-3)^2 \) confirms the x-intercept is \( x = 3 \).
- Finding y-intercepts requires setting \( x = 0 \). For our function, substituting \( x = 0 \) yields \( y = 9 \), confirming the y-intercept.
Parabolas
Parabolas are U-shaped graphs representing quadratic functions, common in algebra and graphing exercises. The standard form \( y = ax^2 + bx + c \) highlights parabolas' distinctive features:
- A vertex that represents the parabola's highest or lowest point.
- An axis of symmetry, which helps in drawing the parabola mirror-like around it.
- Intercepts, where the parabola meets the x-axis and y-axis. These points are crucial for fully understanding the graph's position.
Other exercises in this chapter
Problem 19
In Exercises 19-36, determine whether the equation represents \(y\) as a function of \(x\). \(x^2 + y^2 = 4\)
View solution Problem 19
In Exercises 17-28, find the slope and \(y\)-intercept (if possible) of the equation of the line. Sketch the line. \( y = -\frac{1}{2}x + 4 \)
View solution Problem 19
In Exercises \(15-24,\) determine the quadrant(s) in which \((x, y)\) is located so that the condition(s) is (are) satisfied. $$ y
View solution Problem 20
In Exercises 19-22, verify that \(f\) and \(g\) are inverse functions. \(f(x) = \frac{x-9}{4} - 3\), \(g(x) = 4x + 9\)
View solution