Problem 19
Question
In Exercises 17–30, write an equation for each line described. Passes through \((3,4)\) and \((-2,5)\)
Step-by-Step Solution
Verified Answer
Equation: \( y = -\frac{1}{5}x + \frac{23}{5} \)
1Step 1: Identify the Formula for the Line
To find the equation of a line given two points, we use the formula for the slope-intercept form of a line, which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
2Step 2: Calculate the Slope (m)
The slope \( m \) can be calculated using the formula:\[m = \frac{y_2 - y_1}{x_2 - x_1}\]Substituting the given points \((3,4)\) and \((-2,5)\), we have:\[m = \frac{5 - 4}{-2 - 3} = \frac{1}{-5} = -\frac{1}{5}\]
3Step 3: Use the Point-Slope Form of a Line
With the slope \( m = -\frac{1}{5} \) and one of the points, say \((3,4)\), we can find the equation using the point-slope form:\[y - y_1 = m(x - x_1)\]Plugging in the values, we get:\[y - 4 = -\frac{1}{5}(x - 3)\]
4Step 4: Convert to Slope-Intercept Form
To convert the point-slope equation to slope-intercept form, simplify and solve for \( y \):\[y - 4 = -\frac{1}{5}x + \frac{3}{5}\]\[y = -\frac{1}{5}x + \frac{3}{5} + 4\]Convert \( 4 \) to a fraction with the same denominator:\[y = -\frac{1}{5}x + \frac{3}{5} + \frac{20}{5}\]\[y = -\frac{1}{5}x + \frac{23}{5}\]
5Step 5: Write the Final Equation
The equation of the line in slope-intercept form is:\[y = -\frac{1}{5}x + \frac{23}{5}\]
Key Concepts
Slope-Intercept FormPoint-Slope FormSlope Calculation
Slope-Intercept Form
The slope-intercept form is a straightforward method to express the equation of a line. This form is helpful because it directly displays the slope and y-intercept, making it easy to graph the line or understand its basic properties. The slope-intercept form is written as:
Here, m represents the slope of the line, which shows how steep the line is. Meanwhile, b describes the y-intercept, which is the point where the line crosses the y-axis.
Using this form, finding how a line behaves just takes seconds. You first determine the slope and y-intercept from a given equation, and you're ready to plot.
If you're given a point and a slope, you can also convert from the point-slope form to the slope-intercept form to make identifying the y-intercept easier. This conversion involves solving for y and rearranging terms to match the slope-intercept format. Understanding and using this form is essential for mastering linear equations.
- y = mx + b
Here, m represents the slope of the line, which shows how steep the line is. Meanwhile, b describes the y-intercept, which is the point where the line crosses the y-axis.
Using this form, finding how a line behaves just takes seconds. You first determine the slope and y-intercept from a given equation, and you're ready to plot.
If you're given a point and a slope, you can also convert from the point-slope form to the slope-intercept form to make identifying the y-intercept easier. This conversion involves solving for y and rearranging terms to match the slope-intercept format. Understanding and using this form is essential for mastering linear equations.
Point-Slope Form
When you have a line passing through a specific point and know the slope, the point-slope form is your go-to equation. This form comes in handy when you don't immediately have the y-intercept. Instead, it focuses on a given point on the line defined by its coordinates \(x_1, y_1\) and the slope \(m\).
For example, if a line passes through the point \(3, 4\) with a slope of \(-\frac{1}{5}\), the equation would be \(y - 4 = -\frac{1}{5}(x - 3)\).
From there, you can solve for other variables or convert to slope-intercept form if needed.
The point-slope form is crucial for situations requiring quick graphing of a line given only partial information. It's particularly useful in exercises where you need to write equations quickly or understand the relationship between a specific set of coordinates and the slope.
- The equation is written as: \(y - y_1 = m(x - x_1)\)
For example, if a line passes through the point \(3, 4\) with a slope of \(-\frac{1}{5}\), the equation would be \(y - 4 = -\frac{1}{5}(x - 3)\).
From there, you can solve for other variables or convert to slope-intercept form if needed.
The point-slope form is crucial for situations requiring quick graphing of a line given only partial information. It's particularly useful in exercises where you need to write equations quickly or understand the relationship between a specific set of coordinates and the slope.
Slope Calculation
Calculating the slope of a line is an essential skill in understanding linear relationships. The slope indicates the direction and steepness of a line, which tells us how much the line rises or falls as we move along it.
For instance, given the points \((3, 4)\) and \((-2, 5)\), the slope would be calculated as \(-\frac{1}{5}\). This negative value illustrates that for every 5 units you move horizontally, the line descends 1 unit vertically.
Understanding slope helps predict how a line behaves and is an integral part of forming equations, regardless if it's the slope-intercept or point-slope form.
- The formula to find the slope between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is: \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
For instance, given the points \((3, 4)\) and \((-2, 5)\), the slope would be calculated as \(-\frac{1}{5}\). This negative value illustrates that for every 5 units you move horizontally, the line descends 1 unit vertically.
Understanding slope helps predict how a line behaves and is an integral part of forming equations, regardless if it's the slope-intercept or point-slope form.
Other exercises in this chapter
Problem 19
In Exercises \(19-30,\) say whether the function is even, odd, or neither. Give reasons for your answer. $$ f(x)=3 $$
View solution Problem 19
Solve the inequalities in Exercises \(19-34,\) expressing the solution sets as intervals or unions of intervals. Also, show each solution set on the real line.
View solution Problem 20
Exercises \(19-28\) tell how many units and in what directions the graphs of the given equations are to be shifted. Give an equation for the shifted graph. Then
View solution Problem 20
In Exercises \(19-30,\) say whether the function is even, odd, or neither. Give reasons for your answer. $$ f(x)=x^{-5} $$
View solution