Problem 19
Question
In \(9-26,\) solve each quadratic equation by completing the square. Express the answer in simplest radical form. $$ x^{2}-6 x+2=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 3 + \sqrt{7}\) and \(x = 3 - \sqrt{7}\).
1Step 1: Move the constant term to the other side
Start with the equation \(x^2 - 6x + 2 = 0\). Move the constant term, 2, to the other side of the equation by subtracting 2 from both sides, resulting in \(x^2 - 6x = -2\).
2Step 2: Complete the square
To complete the square, take half of the coefficient of \(x\), which is -6, divide it by 2 to get -3, and then square it to get 9. Add and subtract 9 inside the equation in order to balance it: \(x^2 - 6x + 9 - 9 = -2\). This becomes: \((x - 3)^2 = 7\).
3Step 3: Solve for x by taking the square root
Now solve \((x - 3)^2 = 7\) by taking the square root of both sides: \[ x - 3 = \pm \sqrt{7} \] This results from the property that \(\sqrt{a^2} = \pm a\).
4Step 4: Solve for x
Add 3 to both sides to solve for \(x\): \[ x = 3 \pm \sqrt{7} \] This gives the two solutions: \(x = 3 + \sqrt{7}\) and \(x = 3 - \sqrt{7}\).
Key Concepts
Quadratic EquationSimplest Radical FormSquare Root Property
Quadratic Equation
A quadratic equation is a polynomial equation of degree 2. It typically appears in the form \( ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants and \(x\) represents an unknown variable. Quadratic equations are fundamental in algebra due to their applications and the unique properties of their solutions.
Solving quadratic equations can be done through various methods, including:
Solving quadratic equations can be done through various methods, including:
- Factoring, when the equation can be expressed as the product of two binomials
- Using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
- Completing the square, which restructures a quadratic into a perfect square trinomial
Simplest Radical Form
When solving quadratic equations, the solutions often involve square roots. The simplest radical form means expressing these square roots in a way that is as simplified as possible. This involves:
- Ensuring there are no perfect square factors under the radical sign
- Avoiding any fractions within the radical
- Writing the solution in a clear, concise manner
Square Root Property
The square root property is a valuable technique for solving equations where a variable is squared and isolated. It's based on the principle that if \(a^2 = b\), then \(a = \pm \sqrt{b}\). This allows us to eliminate the square by introducing positive and negative square roots into our solutions.
This property was pivotal in step 3 of solving the original exercise. After rewriting the equation as \((x - 3)^2 = 7\), we applied the square root property to solve:\[x - 3 = \pm \sqrt{7}\]Adding 3 to both sides results in the final solution:\[x = 3 \pm \sqrt{7}\]By using the square root property, we can effectively break down the squared expression and solve for the variable, leading to precise solutions. It is especially useful in problems involving quadratic equations that have been completed as squares.
This property was pivotal in step 3 of solving the original exercise. After rewriting the equation as \((x - 3)^2 = 7\), we applied the square root property to solve:\[x - 3 = \pm \sqrt{7}\]Adding 3 to both sides results in the final solution:\[x = 3 \pm \sqrt{7}\]By using the square root property, we can effectively break down the squared expression and solve for the variable, leading to precise solutions. It is especially useful in problems involving quadratic equations that have been completed as squares.
Other exercises in this chapter
Problem 19
In \(19-34,\) write each sum or difference in terms of \(i\) $$ \sqrt{-100}+\sqrt{-81} $$
View solution Problem 19
In \(19-25,\) express each answer in simplest radical form. Check each answer. The larger of two numbers is 5 more than twice the smaller. The square of the sma
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In \(18-35,\) find each common solution algebraically. Express irrational roots in simplest radical form. $$ \begin{array}{l}{y=x^{2}+2 x+3} \\ {x+y=1}\end{arra
View solution Problem 20
In \(19-28 :\) a. Find \(\mathrm{f}(a)\) for each given function. b. Is \(a\) a root of the function? $$ \mathrm{f}(x)=x^{3}+4 x, \text { and } a=-2 $$
View solution