Problem 19
Question
For Problems \(9-20\), find \(A B\) and \(B A\), whenever they exist. $$ A=\left[\begin{array}{r} 3 \\ -4 \\ 2 \end{array}\right], \quad B=\left[\begin{array}{ll} 3 & -4 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
AB exists and is \( \begin{bmatrix} 9 & -12 \\ -12 & 16 \\ 6 & -8 \end{bmatrix} \); BA does not exist.
1Step 1: Understand Matrix Dimensions
For matrix multiplication to be possible between two matrices, the number of columns in the first matrix must equal the number of rows in the second matrix. Matrix A is a 3x1 matrix and matrix B is a 1x2 matrix.
2Step 2: Check for Possibility of Multiplying AB
To multiply matrices A and B, the number of columns in A (which is 1) must match the number of rows in B (which is also 1). Therefore, the product AB is possible and will result in a 3x2 matrix.
3Step 3: Compute AB
Multiply each element of the matrix A by each element in the matrix B: \[AB = \begin{bmatrix} 3 \cdot 3 & 3 \cdot (-4) \ -4 \cdot 3 & -4 \cdot (-4) \ 2 \cdot 3 & 2 \cdot (-4) \end{bmatrix} = \begin{bmatrix} 9 & -12 \ -12 & 16 \ 6 & -8 \end{bmatrix}\]
4Step 4: Check for Possibility of Multiplying BA
To multiply B and A, the number of columns in B (which is 2) must equal the number of rows in A (which is 3). Since this is not the case, the product BA does not exist.
Key Concepts
Matrix DimensionsMatrix ProductScalar Multiplication
Matrix Dimensions
Matrix dimensions are crucial to understanding matrix multiplication because they define the shape and size of a matrix. A matrix is typically written in the format of 'rows by columns.' For example, a matrix with 3 rows and 1 column is described as a 3x1 matrix.
In matrix operations, especially multiplication, matrix dimensions dictate whether two matrices can indeed be multiplied together.
For two matrices, such as A and B, to be multiplicable:
In matrix operations, especially multiplication, matrix dimensions dictate whether two matrices can indeed be multiplied together.
For two matrices, such as A and B, to be multiplicable:
- The number of columns in Matrix A must be equal to the number of rows in Matrix B.
Matrix Product
The matrix product, or matrix multiplication, involves two matrices and combines their elements according to specific rules. Each element from the resulting matrix comes from the sum of the products of elements from the rows of one matrix and the columns of the other.
Here are some essentials about the matrix product:
Here are some essentials about the matrix product:
- The order of multiplication matters. Hence, A multiplied by B (AB) is usually different from B multiplied by A (BA).
- If matrix A is of size m x n and matrix B is of n x p, the resulting AB will be a matrix of size m x p.
Scalar Multiplication
Scalar multiplication is not the same as matrix multiplication, but learning about it can help build intuition around matrix operations. Scalar multiplication involves multiplying every element in a matrix by a single number (the scalar).
This operation scales the entries of the matrix, hence the term 'scalar multiplication.' Here’s a simple way to understand it:
This operation scales the entries of the matrix, hence the term 'scalar multiplication.' Here’s a simple way to understand it:
- Each entry in the matrix is multiplied individually by the scalar value.
- This operation does not change the dimensions of the matrix.
Other exercises in this chapter
Problem 18
For Problems \(13-26\), compute \(A B\) and \(B A\). $$ A=\left[\begin{array}{ll} 1 & 2 \\ 1 & 2 \end{array}\right], \quad B=\left[\begin{array}{rr} 2 & 2 \\ -1
View solution Problem 18
For Problems \(1-24\), indicate the solution set for each system of inequalities by graphing the system and shading the appropriate region. $$ \left(\begin{arra
View solution Problem 19
For Problems \(19-26\), compute \(A B\). $$ A=\left[\begin{array}{ll} 4 & 3 \\ 2 & 5 \end{array}\right], \quad B=\left[\begin{array}{l} 3 \\ 6 \end{array}\right
View solution Problem 19
For Problems \(13-26\), compute \(A B\) and \(B A\). $$ A=\left[\begin{array}{ll} -3 & -2 \\ -4 & -1 \end{array}\right], \quad B=\left[\begin{array}{rr} 2 & -1
View solution