Problem 19
Question
Find the sum, difference, or product. $$8(2 x+5)-7(x-9)$$
Step-by-Step Solution
Verified Answer
\(9x + 103\)
1Step 1: Expand the Expressions
To simplify the expression, start by expanding each bracket. For the first term, multiply 8 by each term inside the parentheses: \[ 8(2x + 5) = 8 \times 2x + 8 \times 5 = 16x + 40. \]For the second term, apply the negative sign and distribute 7: \[ -7(x - 9) = -7 \times x + 7 \times 9 = -7x + 63. \]
2Step 2: Combine Like Terms
Now, combine the like terms from the expanded expression. Start by combining the \(x\) terms:\[ 16x - 7x = 9x. \]Next, combine the constant terms:\[ 40 + 63 = 103. \]So the simplified expression is:\[ 9x + 103. \]
Key Concepts
Expanding BracketsLike TermsSimplifying ExpressionsDistributive Property
Expanding Brackets
In algebra, expanding brackets is an essential skill when dealing with algebraic expressions. It involves eliminating the parentheses by multiplying each term inside the brackets by the factor outside. Let's consider our example:
- The expression is written as: \(8(2x + 5) - 7(x - 9)\).
- When expanding, you start with \(8(2x + 5)\). Multiply 8 by both \(2x\) and 5: \(8 \times 2x = 16x\) and \(8 \times 5 = 40\).
- Apply the same rule to \(-7(x - 9)\): multiply \(-7\) by both \(x\) and \(-9\), resulting in \(-7x\) and \(+63\).
Like Terms
In algebraic expressions, 'like terms' are terms that have the same variables raised to the same power. Identifying and combining these terms is crucial for simplifying expressions. Let's delve into this with our example:
- After expanding the brackets, our expression is \(16x + 40 - 7x + 63\).
- "Like terms" means the terms with the same variable part. Here, \(16x\) and \(-7x\) are like terms as they both contain the variable \(x\) raised to the first power.
- Combine \(16x\) and \(-7x\): \(16x - 7x = 9x\).
- Constant terms like 40 and 63 can be added together: \(40 + 63 = 103\).
Simplifying Expressions
Simplifying expressions involves making them easier to read and work with while maintaining their original value. It's a crucial process for solving algebraic problems efficiently. Let's revisit our simplified expression: \(9x + 103\).
- After expanding brackets and combining like terms, the expression becomes much simpler to handle compared to its original form.
- A simplified expression is less cluttered and provides a clearer picture of what you're working with. Instead of complicated steps, you now have \(9x + 103\), which can easily be used in further calculations or problem-solving contexts.
Distributive Property
The distributive property is a fundamental concept in algebra. It allows you to multiply a term across a sum or difference inside parentheses. Mastering this property is key to understanding how algebraic expressions are manipulated.
- The distributive property states that \(a(b + c) = ab + ac\). You distribute the outside term to each inside term.
- In our example, we applied this when expanding \(8(2x + 5)\) to \(16x + 40\) and \(-7(x - 9)\) to \(-7x + 63\).
- It's important to remember to distribute any negative signs as well, which we demonstrated with \(-7(x - 9)\).
Other exercises in this chapter
Problem 18
Evaluate each expression. (a) \(\left(-\frac{2}{3}\right)^{-3}\) (b) \(\left(\frac{3}{2}\right)^{-2} \cdot \frac{9}{16}\) (c) \(\left(\frac{1}{2}\right)^{4} \cd
View solution Problem 18
Rewrite the expression using the given property of real numbers. Distributive Property, \(5 x+5 y=\) _____
View solution Problem 19
Simplify the rational expression. $$\frac{y^{2}+y}{y^{2}-1}$$
View solution Problem 19
Express the statement as an equation. Use the given information to find the constant of proportionality. \(R\) is inversely proportional to \(s .\) If \(s=4,\)
View solution