Problem 19
Question
Find the quotient \(\frac{z_{1}}{z_{2}}\) and express it in rectangular form. $$z_{1}=45\left[\cos \left(\frac{22 \pi}{15}\right)+i \sin \left(\frac{22 \pi}{15}\right)\right] \text { and } z_{2}=9\left[\cos \left(\frac{2 \pi}{15}\right)+i \sin \left(\frac{2 \pi}{15}\right)\right]$$
Step-by-Step Solution
Verified Answer
The quotient is \(-\frac{5}{2} - \frac{5\sqrt{3}}{2}i\).
1Step 1: Convert to Exponential Form
Convert the given complex numbers to exponential form using Euler's formula. Define the complex numbers as follows:\[ z_1 = 45 \left[ \cos \left(\frac{22 \pi}{15}\right) + i \sin \left(\frac{22 \pi}{15}\right) \right] = 45 e^{i \frac{22 \pi}{15}} \]and \[ z_2 = 9 \left[ \cos \left(\frac{2 \pi}{15}\right) + i \sin \left(\frac{2 \pi}{15}\right) \right] = 9 e^{i \frac{2 \pi}{15}} \]
2Step 2: Apply Division Formula for Complex Numbers
To find the quotient \( \frac{z_1}{z_2} \), divide the magnitudes and subtract the exponents:\[ \frac{z_1}{z_2} = \frac{45}{9} e^{i \left( \frac{22\pi}{15} - \frac{2\pi}{15} \right)} \]Simplify the expression:\[ \frac{z_1}{z_2} = 5 e^{i \frac{20 \pi}{15}} = 5 e^{i \frac{4 \pi}{3}} \]
3Step 3: Convert Back to Rectangular Form
Use Euler's formula again to convert \( 5 e^{i \frac{4\pi}{3}} \) to rectangular form. First, find the cosine and sine:\[ \cos\left(\frac{4\pi}{3}\right) = -\frac{1}{2}, \quad \sin\left(\frac{4\pi}{3}\right) = -\frac{\sqrt{3}}{2} \]Then, substitute back:\[ z = 5 \left[ -\frac{1}{2} + i \left(-\frac{\sqrt{3}}{2}\right) \right] \]Simplify:\[ z = -\frac{5}{2} - \frac{5\sqrt{3}}{2} i \]
4Step 4: Conclusion
Thus, the quotient \( \frac{z_1}{z_2} \) in rectangular form is:\[ -\frac{5}{2} - \frac{5\sqrt{3}}{2}i \]
Key Concepts
Complex Number DivisionPolar to Rectangular ConversionEuler's Formula
Complex Number Division
Complex number division sounds a bit intimidating at first, but it's similar to dividing regular numbers. Only, we deal with both magnitude and direction more consciously. In our original exercise, we are tasked with finding the quotient of two complex numbers, \( z_1 \) and \( z_2 \). These numbers are expressed in what we call the polar form: a form that emphasizes their magnitude and angular component.
Here's the basic strategy we apply when dividing complex numbers in polar form:
Here's the basic strategy we apply when dividing complex numbers in polar form:
- Divide the magnitudes: The magnitudes of the complex numbers are the coefficients. So, for our example, \( \frac{45}{9} = 5 \).
- Subtract the angles: The angles in the exponential terms need to be subtracted. Hence, we compute \( \frac{22\pi}{15} - \frac{2\pi}{15} = \frac{20\pi}{15} = \frac{4\pi}{3} \).
Polar to Rectangular Conversion
After working with the division of complex numbers in their polar form, the next task involves converting back to rectangular form, which is often easier to visualize. The rectangular form is the standard form of a complex number, expressed as \( a + bi \) where \( a \) and \( b \) are real numbers.
To convert from polar (or exponential) form to rectangular form, we make use of Euler's formula. The critical expressions here are \( \cos(\theta) \) and \( \sin(\theta) \) which correspond to the real and imaginary parts, respectively:
To convert from polar (or exponential) form to rectangular form, we make use of Euler's formula. The critical expressions here are \( \cos(\theta) \) and \( \sin(\theta) \) which correspond to the real and imaginary parts, respectively:
- \( 5 \cos\left(\frac{4\pi}{3}\right) = 5 \left(-\frac{1}{2}\right) = -\frac{5}{2} \)
- \( 5 \sin\left(\frac{4\pi}{3}\right) = 5 \left(-\frac{\sqrt{3}}{2}\right) = -\frac{5\sqrt{3}}{2} \)
Euler's Formula
Euler's formula is a wonderful bridge between the trigonometric and exponential form of complex numbers. It's expressed as \( e^{i\theta} = \cos(\theta) + i\sin(\theta) \).
In the exercise solution, we used Euler's formula to switch between forms of complex numbers seamlessly:
In the exercise solution, we used Euler's formula to switch between forms of complex numbers seamlessly:
- While in polar/exponential form, it simplifies calculations such as multiplication and division.
- During the conversion back to rectangular form, it becomes straightforward to identify the cosine and sine components -- perfect for easy calculation of the real and imaginary parts.
Other exercises in this chapter
Problem 19
Find the angle (round to the nearest degree) between each pair of vectors. $$\langle-2,2 \sqrt{3}\rangle \text { and }\langle-\sqrt{3}, 1\rangle$$
View solution Problem 19
Convert each point to exact polar coordinates. Assume that \(0 \leq \theta
View solution Problem 19
Express each complex number in polar form. $$-5+5 i$$
View solution Problem 19
Perform the indicated vector operation, given \(u=(-4,3)\) and \(v=\langle 2,-5\rangle\) $$3 \mathbf{u}$$
View solution