Problem 19
Question
Find the inverse of each matrix, if it exists. $$ \left[\begin{array}{rr}{4} & {-3} \\ {2} & {7}\end{array}\right] $$
Step-by-Step Solution
Verified Answer
The inverse matrix is \( \begin{bmatrix} \frac{7}{34} & \frac{3}{34} \\
\frac{-1}{17} & \frac{2}{17} \end{bmatrix} \).
1Step 1: State the formula for the inverse of a 2x2 matrix
The inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) exists if the determinant is non-zero and is given by the formula \[\begin{bmatrix} a & b \ c & d \end{bmatrix}^{-1} = \frac{1}{ad-bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix}\]
2Step 2: Calculate the determinant
First, calculate the determinant of the matrix \( \begin{bmatrix} 4 & -3 \ 2 & 7 \end{bmatrix} \). The determinant \( \Delta \) is calculated as:\[ \Delta = (4)(7) - (-3)(2)\]\[ \Delta = 28 + 6 = 34\]The determinant is 34.
3Step 3: Verify if the inverse exists
Since the determinant (\( \Delta = 34 \)) is non-zero, the inverse of the matrix exists.
4Step 4: Apply the inverse formula
Using the formula for the inverse of a 2x2 matrix, substitute the values of \( a = 4 \), \( b = -3 \), \( c = 2 \), and \( d = 7 \):\[\begin{bmatrix} 4 & -3 \ 2 & 7 \end{bmatrix}^{-1} = \frac{1}{34} \begin{bmatrix} 7 & 3 \ -2 & 4 \end{bmatrix} = \begin{bmatrix} \frac{7}{34} & \frac{3}{34} \ \frac{-2}{34} & \frac{4}{34} \end{bmatrix}\]Simplify the fractions:\[\begin{bmatrix} \frac{7}{34} & \frac{3}{34} \ \frac{-1}{17} & \frac{2}{17} \end{bmatrix}\]
5Step 5: Present the final inverse matrix
The inverse matrix is:\[\begin{bmatrix} \frac{7}{34} & \frac{3}{34} \ \frac{-1}{17} & \frac{2}{17} \end{bmatrix}\]
Key Concepts
2x2 matrixdeterminantmatrix algebra
2x2 matrix
The 2x2 matrix is one of the simplest types of matrices in mathematics, often used as an introductory example in the study of linear algebra. A matrix is essentially a rectangular array of numbers, and a 2x2 matrix specifically has two rows and two columns.
Its general form is represented as:
In our given problem, the matrix is \( \begin{bmatrix} 4 & -3 \ 2 & 7 \end{bmatrix} \), where \( a = 4 \), \( b = -3 \), \( c = 2 \), and \( d = 7 \). These numbers can represent various things depending on the problem's context, from coefficients in a system of equations to values in graphics transformations. Understanding a 2x2 matrix is crucial, as it forms the foundation for more complex matrix algebra and operations.
Its general form is represented as:
- \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \)
In our given problem, the matrix is \( \begin{bmatrix} 4 & -3 \ 2 & 7 \end{bmatrix} \), where \( a = 4 \), \( b = -3 \), \( c = 2 \), and \( d = 7 \). These numbers can represent various things depending on the problem's context, from coefficients in a system of equations to values in graphics transformations. Understanding a 2x2 matrix is crucial, as it forms the foundation for more complex matrix algebra and operations.
determinant
The determinant is a special number that can be calculated from a square matrix. For a 2x2 matrix, it's a straightforward calculation that provides valuable information about the matrix, such as whether it can be inverted.
The formula for finding the determinant \( \Delta \) of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is:
If the determinant were zero, it would mean the matrix is singular, and no inverse exists.
The formula for finding the determinant \( \Delta \) of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is:
- \( \Delta = ad - bc \)
- \( (4)(7) - (-3)(2) = 28 + 6 = 34 \)
If the determinant were zero, it would mean the matrix is singular, and no inverse exists.
matrix algebra
Matrix algebra involves various operations that can be performed on matrices, such as addition, subtraction, multiplication, and finding the inverse. Finding the inverse of a matrix is particularly useful because it allows us to solve systems of equations and find solutions to linear problems.
To find the inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the formula is:
Using our matrix \( \begin{bmatrix} 4 & -3 \ 2 & 7 \end{bmatrix} \), and given its determinant is 34, the inverse is calculated as:
To find the inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the formula is:
- \( \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \frac{1}{ad-bc} \)
Using our matrix \( \begin{bmatrix} 4 & -3 \ 2 & 7 \end{bmatrix} \), and given its determinant is 34, the inverse is calculated as:
- \( \frac{1}{34} \begin{bmatrix} 7 & 3 \ -2 & 4 \end{bmatrix} = \begin{bmatrix} \frac{7}{34} & \frac{3}{34} \ \frac{-1}{17} & \frac{2}{17} \end{bmatrix} \)
Other exercises in this chapter
Problem 19
Use a matrix equation to solve each system of equations. \(6 x-10 y=7\) \(3 x-5 y=8\)
View solution Problem 19
Use Cramer’s Rule to solve each system of equations. \(a-2 b+c=7\) \(6 a+2 b-2 c=4\) \(4 a+6 b+4 c=14\)
View solution Problem 19
Find the value of each determinant. $$ \left|\begin{array}{rrr}{-2} & {7} & {-2} \\ {4} & {5} & {2} \\ {1} & {0} & {-1}\end{array}\right| $$
View solution Problem 19
Write the vertex matrix and the reflection matrix for each figure. Then find the coordinates of the image after the reflection. Graph the preimage and the image
View solution