Problem 19
Question
Find the foci for each equation of an ellipse. Then graph the ellipse. $$ \frac{x^{2}}{9}+\frac{y^{2}}{25}=1 $$
Step-by-Step Solution
Verified Answer
The foci of the ellipse are at points (0, 4) and (0, -4). The graph of the ellipse would pass through the points (3, 0) , (-3, 0) , (0, 5) , and (0, -5) with foci at points above and below the origin.
1Step 1: Identify the semimajor and semiminor axes
Looking at the given equation, identify the values for \(a\) and \(b\). The given ellipse equation is in standard form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). Therefore, \(a\) is the square root of denominator of \(y^2\) term (largest denominator) and \(b\) is the square root of the denominator of \(x^2\) term. Hence, \(a = 5\) and \(b = 3\).
2Step 2: Calculate the foci
Substitute the determined \(a\) and \(b\) values in the foci formula \(c = \sqrt{a^2 - b^2}\). So, \(c = \sqrt{5^2 - 3^2} = \sqrt{16} = 4\). The coordinates for the foci would be (0, 4) and (0, -4) since there is a larger denominator under the \(y^2\) term, meaning we're stretching more along the y-axis.
3Step 3: Sketch the Ellipse
Draw the x and y axes. Plot the points (0, 5) and (0, -5) as well as (3, 0) and (-3, 0) to serve as the vertices and co-vertices respectively. Similarly, plot the foci determined in Step 2. Then sketch the ellipse using these points.
Key Concepts
Foci of an EllipseGraphing EllipsesConic Sections
Foci of an Ellipse
Understanding the foci of an ellipse helps to reveal the inherent symmetry and balance of this geometric shape. In any ellipse, there are two fixed points known as the foci (singular: focus). While these might seem complex at first, they are actually quite simple to pinpoint after understanding the underlying principles. To find the foci of an ellipse, the formula used is:
- If the equation is of the form \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) and \(b > a\), then the foci are located along the y-axis at \((0, \pm c)\).
- The formula to calculate \(c\) is \(c = \sqrt{b^2 - a^2}\).
Graphing Ellipses
Visualizing an ellipse through graphing provides invaluable insight into its structure. Firstly, identify the semi-major and semi-minor axes. The semi-major axis is tied to the larger denominator under the variables, and the semi-minor to the smaller one.
- The length of the semi-major axis is \( 2a \) and of the semi-minor axis is \( 2b \).
- Plot the vertices at (0, 5) and (0, -5).
- Plot the co-vertices at (3, 0) and (-3, 0).
Conic Sections
Ellipses are part of a family of curves known as conic sections, which arise from intersecting a plane with a double-napped cone. Conic sections include ellipses, parabolas, and hyperbolas, each defined by the angle of intersection between the cone and the plane.
- If the plane cuts parallel to the base of the cone, we get a circle.
- If the plane intersects at a smaller angle than the parabola but not steep enough for a hyperbola, an ellipse forms.
- Changes in this angle or distance help determine whether conic sections distort into eccentric shapes.
Other exercises in this chapter
Problem 18
Find the foci of each hyperbola. Then draw the graph. $$ 14 y^{2}-28 x^{2}=448 $$
View solution Problem 18
Identify the focus and the directrix of the graph of each equation. $$ y=-\frac{1}{8} x^{2} $$
View solution Problem 19
Identify the focus and the directrix of the graph of each equation. $$ x=\frac{1}{2} y^{2} $$
View solution Problem 19
For each equation, find the center and radius of the circle. $$ (x-1)^{2}+(y-1)^{2}=1 $$
View solution