Problem 19
Question
Find the derivative of the function. $$ f(x)=4 \sqrt{x} $$
Step-by-Step Solution
Verified Answer
The derivative of the function \(f(x) = 4 \sqrt{x}\) is \(f'(x) = \frac{2}{\sqrt{x}}\).
1Step 1: Rewrite the function
Rewrite the given function \(f(x) = 4 \sqrt{x}\) in the form of \(f(x) = ax^n\). Therefore, the function becomes \(f(x) = 4x^{1/2}\).
2Step 2: Apply the power rule
Use the power rule, which states that \(d/dx[x^n] = nx^{n-1}\) to find the derivative. The rule is applied to every term of the function. Here \(a = 4, n = \frac{1}{2}\). Applying the power rule to our function will result \(f'(x) = \frac{1}{2} \cdot 4x^{(\frac{1}{2}-1)}\).
3Step 3: Simplify the result
Simplify the expression to get the final answer, \(f'(x) = 2x^{-\frac{1}{2}}\). But remembering - a negative exponent means that the term is on the denominator. Therefore, the function can also be written as \(f'(x) = \frac{2}{x^\frac{1}{2}}\). This means for any x in the domain of \(f\), the derivative of the function \(f\) at \(x\) is \(f'(x) = \frac{2}{\sqrt{x}}\).
Other exercises in this chapter
Problem 18
Use the limit definition to find the slope of the tangent line to the graph of \(f\) at the given point. $$ f(x)=6 ;(-2,6) $$
View solution Problem 19
Find the marginal cost for producing \(x\) units. (The cost is measured in dollars.) $$ C=4500+1.47 x $$
View solution Problem 19
Describe the interval(s) on which the function is continuous. Explain why the function is continuous on the interval(s). If the function has a discontinuity, id
View solution Problem 19
Use the limit definition to find the slope of the tangent line to the graph of \(f\) at the given point. $$ f(x)=x^{2}-1 ;(2,3) $$
View solution