Problem 19
Question
Find the coordinates of the midpoint of the line segment joining the two points. $$ (-5,-2,5),(6,3,-7) $$
Step-by-Step Solution
Verified Answer
The coordinates of the midpoint of the line segment joining the two points (-5,-2,5) and (6,3,-7) are (1/2, 1/2, -1).
1Step 1: Identify the Coordinates of the Given Points
The coordinates of the first point, (Point A), are (-5, -2, 5). The coordinates of the second point, (Point B), are (6, 3, -7).
2Step 2: Apply the Formula of the Midpoint for All Three Coordinates
Apply the formula of the midpoint: \( ((x1+x2)/2, (y1+y2)/2, (z1+z2)/2) \) for all three coordinates X, Y and Z. This means for X it would be \(((-5+6)/2)\), for Y \(((-2+3)/2)\), and for Z \(( (5+(-7))/2)\).
3Step 3: Simplify the Results
After calculating the previous expressions, the X coordinate is \((1/2)\), Y coordinate is \((1/2)\) and the Z coordinate is \((-1)\).
Key Concepts
Coordinate GeometryThree-Dimensional GeometryLine Segments
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is the study of geometry using a coordinate system. This system often involves the placement of geometric figures in a plane using numbers, known as coordinates. Each point in the plane is represented by an ordered pair \(x, y\). In three-dimensional geometry, this is extended to an ordered triple \(x, y, z\). By using coordinate geometry, we can conduct algebraic representations and calculations involving geometric figures.
This approach enables us to solve problems related to distances and midpoints, like the one given. The midpoint formula specifically allows us to find the exact middle point of a line segment. Applying coordinate geometry to solve such problems offers an efficient and reliable method to explore spatial relations and geometric transformations.
This approach enables us to solve problems related to distances and midpoints, like the one given. The midpoint formula specifically allows us to find the exact middle point of a line segment. Applying coordinate geometry to solve such problems offers an efficient and reliable method to explore spatial relations and geometric transformations.
Three-Dimensional Geometry
In three-dimensional geometry, we expand the principles of two-dimensional geometry into an extra dimension. This is widely applicable in real-world situations. Coordinates in three-dimensional space are written as \(x, y, z\), adding a third number that conveys depth.
In the context of finding the midpoint of a line segment in 3D space, each coordinate of the midpoint is the average of the corresponding coordinates of the endpoints of the line segment. The formula applied is:
In the context of finding the midpoint of a line segment in 3D space, each coordinate of the midpoint is the average of the corresponding coordinates of the endpoints of the line segment. The formula applied is:
- Midpoint for X = \(\frac{x_1 + x_2}{2}\)
- Midpoint for Y = \(\frac{y_1 + y_2}{2}\)
- Midpoint for Z = \(\frac{z_1 + z_2}{2}\)
Line Segments
A line segment is the shortest path connecting two points. It consists of two endpoints and all the points that lie between them. In the context of coordinate geometry, line segments are often analyzed using their endpoints' coordinates.
To find a midpoint of a line segment, we take each coordinate of the endpoints and calculate their average. This gives us the coordinates of the midpoint, which evenly divides the segment into two equal halves.
To find a midpoint of a line segment, we take each coordinate of the endpoints and calculate their average. This gives us the coordinates of the midpoint, which evenly divides the segment into two equal halves.
- In a two-dimensional plane, if endpoints are \(A(x_1, y_1)\) and \(B(x_2, y_2)\), the midpoint, \(M\), has coordinates \((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\).
- Similarly, in three-dimensional space, the formula \(\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}, \frac{z_1 + z_2}{2}\right)\) is used.
Other exercises in this chapter
Problem 19
In Exercises \(19-22,\) use Lagrange multipliers to find the given extremum of \(f\) subject to two constraints. In each case, assume that \(x, y,\) and \(z\) a
View solution Problem 19
Find the distance between the point and the plane (see figure). The distance \(D\) between a point \(\left(x_{0}, y_{0}, z_{0}\right)\) and the plane \(a x+b y+
View solution Problem 20
Examine the function for relative extrema and saddle points. $$ f(x, y)=-\frac{3}{x^{2}+y^{2}+1} $$
View solution Problem 20
Evaluate the double integral. $$ \int_{0}^{4} \int_{0}^{x} \frac{2}{x^{2}+1} d y d x $$
View solution