Problem 19
Question
Find \(\boldsymbol{A}^{-1}\) by forming \([\boldsymbol{A} | \boldsymbol{I}]\) and then using row operations to obtain \([I | B],\) where \(A^{-1}=[B] .\) Check that \(A A^{-1}=I\) and \(A^{-1} A=I\) $$ A=\left[\begin{array}{lll} {2} & {0} & {0} \\ {0} & {4} & {0} \\ {0} & {0} & {6} \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The inverse of the matrix A is \[A^{-1} = \left[\begin{array}{ccc}0.5 & 0 & 0 \ 0 & 0.25 & 0 \ 0 & 0 & 0.1666\end{array}\right]\]
1Step 1: Form the augmented matrix
Start by creating an augmented matrix \([A | I]\). Here, I is the identity matrix.\[\left[\begin{array}{ccc|ccc}2 & 0 & 0 & 1 & 0 & 0\ 0 & 4 & 0 & 0 & 1 & 0\ 0 & 0 & 6 & 0 & 0 & 1\end{array}\right]\]
2Step 2: Perform row operations
Now we are going to transform matrix A into identity matrix I using row operations. Divide the elements of the first row by 2, the second row by 4 and the third row by 6. The resulting matrix is: \[\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 0.5 & 0 & 0\ 0 & 1 & 0 & 0 & 0.25 & 0\ 0 & 0 & 1 & 0 & 0 & 0.1666\end{array}\right]\]
3Step 3: Extracting the inverse matrix
After performing the row operations, the augmented matrix is of the form [I | B]. With B being the result on the right side, it's the inverse of matrix A, i.e., \( A^{-1} = \left[\begin{array}{ccc}0.5 & 0 & 0 \ 0 & 0.25 & 0 \ 0 & 0 & 0.1666\end{array}\right]\)
4Step 4: Verify the inverse
Lastly, we need to verify that our calculated inverse is correct. To do this, we have to multiply matrix A by its inverse, and the inverse by A, and check that both results give the identity matrix:\( AA^{-1} = \left[\begin{array}{ccc}2 & 0 & 0 \ 0 & 4 & 0 \ 0 & 0 & 6\end{array}\right]\cdot\left[\begin{array}{ccc}0.5 & 0 & 0 \ 0 & 0.25 & 0 \ 0 & 0 & 0.1666\end{array}\right]= \left[\begin{array}{ccc}1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1\end{array}\right]= I\) And, similarly,\( A^{-1}A = \left[\begin{array}{ccc}0.5 & 0 & 0 \ 0 & 0.25 & 0 \ 0 & 0 & 0.1666\end{array}\right]\cdot\left[\begin{array}{ccc}2 & 0 & 0 \ 0 & 4 & 0 \ 0 & 0 & 6\end{array}\right]= \left[\begin{array}{ccc}1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1\end{array}\right]= I\)Both the results are equal to the identity matrix, which confirms that the calculated matrix A^{-1} is indeed the inverse of A.
Key Concepts
Matrix AugmentationRow OperationsIdentity MatrixVerify Matrix Inversion
Matrix Augmentation
Matrix augmentation is a useful technique when dealing with inverses and linear transformations. Here, you start with a given matrix, let's call it \( A \), and augment it with the identity matrix \( I \). The augmented matrix looks like this: \([A | I]\). This technique prepares the matrix for row operations, which will ultimately help us find the inverse. It helps by giving a clear path to transform the original matrix \( A \) into the identity matrix, enabling the flip side of the augmentation to transform into \( A^{-1} \), the inverse of our original matrix.
Row Operations
Row operations are central to the process of finding the inverse of a matrix through augmentation. These operations allow us to modify the structure of our matrix methodically. There are three key types of row operations:
- Switching two rows
- Multiplying a row by a nonzero scalar
- Adding or subtracting a multiple of one row to another row
Identity Matrix
The identity matrix \( I \) is a special kind of square matrix that plays a crucial role when dealing with matrix operations, especially inverses. It is a matrix filled with zeros except for ones along its diagonal. The identity matrix serves as the multiplicative identity in matrix algebra. For any matrix \( A \), when you multiply it by \( I \), i.e., \( A \times I \) or \( I \times A \), the result is \( A \) itself. Therefore, when changing \( A \) into \( I \) using row operations on \([A | I]\), the identity matrix helps guide us to correctly transform the identity side into the inverse of \( A \), thus achieving the configuration \([I | B]\), where \( B \) is \( A^{-1} \).
Verify Matrix Inversion
Verifying the matrix inversion is a crucial step to ensure the calculated inverse is correct. This involves multiplying the original matrix \( A \) by the purported inverse \( A^{-1} \) and checking if the product equals the identity matrix. Furthermore, you should also multiply \( A^{-1} \) by \( A \) to confirm that it similarly yields the identity matrix:
- \( A \times A^{-1} = I \)
- \( A^{-1} \times A = I \)
Other exercises in this chapter
Problem 19
A few steps in the process of simplifying the given matrix to row-echelon form, with Is down the diagonal from upper left to lower right, and os below the \(1 s
View solution Problem 19
Use Cramer’s Rule to solve each system. $$\left\\{\begin{array}{l}{3 x-4 y=4} \\\\{2 x+2 y=12}\end{array}\right.$$
View solution Problem 19
Use Gaussian elimination to find the complete solution to each system of equations, or show that none exists. $$ \left\\{\begin{aligned} x+y-2 z &=2 \\ 3 x-y-6
View solution Problem 20
Let $$ A=\left[\begin{array}{rr} {-3} & {-7} \\ {2} & {-9} \\ {5} & {0} \end{array}\right] \text { and } B=\left[\begin{array}{rr} {-5} & {-1} \\ {0} & {0} \\ {
View solution