Problem 19
Question
Exercises \(17-24\) give equations for ellipses. Put each equation in standard form. Then sketch the ellipse. Include the foci in your sketch. $$ 2 x^{2}+y^{2}=2 $$
Step-by-Step Solution
Verified Answer
The ellipse is in standard form: \(\frac{x^2}{1} + \frac{y^2}{2} = 1\), with foci at \((0, \pm 1)\).
1Step 1: Write the Equation in Standard Form
The given equation of the ellipse is \(2x^2 + y^2 = 2\). To write it in standard form, we need to have the right-hand side equal to 1. To do this, divide the entire equation by 2. This gives us: \[ \frac{x^2}{1} + \frac{y^2}{2} = 1 \] This equation is now in the form of an ellipse: \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\).
2Step 2: Identify Ellipse Parameters
From the standard form equation \(\frac{x^2}{1} + \frac{y^2}{2} = 1\), identify the values: - \(a^2 = 1\), so \(a = 1\) - \(b^2 = 2\), so \(b = \sqrt{2}\) Here, since \(b > a\), the ellipse is vertical.
3Step 3: Find the Foci of the Ellipse
For an ellipse where \(b > a\), the distance to the foci, \(c\), is found using \(c = \sqrt{b^2 - a^2}\). With \(a = 1\) and \(b = \sqrt{2}\), we have: \[ c = \sqrt{2 - 1} = 1 \] So, the foci are located at \((0, \pm 1)\).
4Step 4: Sketch the Ellipse
Draw the ellipse centered at the origin \((0,0)\) with a vertical major axis. - The major semi-axis length \(b = \sqrt{2}\), so it extends \(\pm \sqrt{2}\) units above and below the origin on the y-axis.- The minor semi-axis length \(a = 1\), so it extends \(\pm 1\) units left and right on the x-axis.- Mark the foci at \((0, 1)\) and \((0, -1)\).
Key Concepts
Standard Form of EllipseEllipse ParametersFoci of an EllipseGraphing Ellipses
Standard Form of Ellipse
To express an ellipse equation in its standard form, it must fit the template \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). This template is pivotal as it allows you to directly identify the properties of the ellipse, such as the major and minor axes. Begin by ensuring the right side of your equation equals 1. In our exercise, the original equation is \( 2x^2 + y^2 = 2 \). To transform it, divide every term by 2, resulting in \( \frac{x^2}{1} + \frac{y^2}{2} = 1 \). This now follows the standard form. Here, the coefficients underneath \(x^2\) and \(y^2\) are effectively \(a^2\) and \(b^2\) respectively.
Ellipse Parameters
Identifying the parameters of an ellipse involves determining the lengths of its axes based on the standard form equation \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). From this format, the parameters, \(a\) and \(b\), inform the size of the ellipse's axes.
- Here, \(a^2 = 1\), thus \(a = 1\).
- For \(b^2 = 2\), \(b = \sqrt{2}\).
Foci of an Ellipse
The foci of an ellipse are two special points along the major axis. They play a key role in defining the geometric properties of an ellipse. Determining their position involves using the calculated values for \(a\) and \(b\). When \(b > a\) in a vertical ellipse, use the formula for the foci distance, \(c = \sqrt{b^2 - a^2}\).
- From the earlier calculation, \(a = 1\) and \(b = \sqrt{2}\).
- Calculate \(c\) as \(\sqrt{2 - 1} = 1\).
Graphing Ellipses
Graphing an ellipse involves plotting its shape based on its parameters and foci. Begin by marking the center of the ellipse, which in this case is at the origin \((0, 0)\). From there, use the lengths \(a\) and \(b\) to determine the extremities of the ellipse.
- The major semi-axis length, \(b = \sqrt{2}\), defines the vertical stretch, extending \(\pm \sqrt{2}\) units from the center on the \(y\)-axis.
- The minor semi-axis length, \(a = 1\), describes the horizontal reach, stretching \(\pm 1\) unit on the \(x\)-axis.
Other exercises in this chapter
Problem 18
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