Problem 19
Question
Exer. 17-20: Use the theorem on inverse functions to prove that \(f\) and \(g\) are inverse functions of each other, and sketch the graphs of \(f\) and \(g\) on the same coordinate plane. $$ f(x)=-x^{2}+3, x \geq 0 ; \quad g(x)=\sqrt{3-x}, x \leq 3 $$
Step-by-Step Solution
Verified Answer
Functions \( f \) and \( g \) are indeed inverses of each other.
1Step 1: Define the theorem
The theorem on inverse functions states that if a function \( f \) is invertible, then \( f(g(x)) = x \) and \( g(f(x)) = x \) for all \( x \) in the domains of \( g \) and \( f \), respectively. We need to verify these conditions for \( f(x) = -x^2 + 3 \) and \( g(x) = \sqrt{3-x} \).
2Step 2: Verify \(f(g(x)) = x\)
Substitute \( g(x) \) into \( f \):\[ f(g(x)) = f(\sqrt{3-x}) = - (\sqrt{3-x})^2 + 3 \]Simplify:\[ = -(3-x) + 3 \]\[ = x \]The equation \( f(g(x)) = x \) is satisfied for \( x \leq 3 \).
3Step 3: Verify \(g(f(x)) = x\)
Substitute \( f(x) \) into \( g \):\[ g(f(x)) = g(-x^2 + 3) = \sqrt{3 - (-x^2 + 3)} \]Simplify:\[ = \sqrt{x^2} \]\[ = x \quad (\text{since} \; x \geq 0) \]The equation \( g(f(x)) = x \) is satisfied for \( x \geq 0 \).
4Step 4: Graph the functions
Graph \( f(x) = -x^2 + 3 \) and \( g(x) = \sqrt{3-x} \) on the same coordinate plane. Note that \( f \) is a downward-opening parabola with vertex at \( (0, 3) \), restricted to \( x \geq 0 \), and \( g \) is a decreasing half of a horizontal parabola, restricted to \( x \leq 3 \). Both functions will be reflections of each other across the line \( y = x \).
Key Concepts
Graphs of FunctionsTheorem on Inverse FunctionsFunction CompositionDomain and Range
Graphs of Functions
Understanding the graphs of functions provides a visual insight into the relationship between the input and output values of the function. For the given functions, we have:
- Function \( f(x) = -x^2 + 3 \) represents a downward-opening parabola. Since it's restricted to \( x \geq 0 \), only the right side of the parabola is graphed.
- Function \( g(x) = \sqrt{3-x} \) is the inverse, and it represents a curve that forms half of a horizontal parabola, restricted to \( x \leq 3 \).
Theorem on Inverse Functions
The theorem on inverse functions is a foundational concept in determining whether two functions are inverses of one another. It asserts that two functions \( f \) and \( g \) are inverses if they satisfy both \( f(g(x)) = x \) and \( g(f(x)) = x \) for all relevant values of \( x \). These relationships reveal:
- For \( f \) and \( g \) to be inverse, every input \( x \) into \( g \) that is then fed into \( f \) should return \( x \), and vice versa.
- This theorem confirms that the composition of a function and its inverse results in the identity function, denoted by \( x \).
Function Composition
Function composition is when the output from one function becomes the input for another. In the case of inverse functions, composing them simplifies to the identity function \( x \):
- For \( f(g(x)) \), function \( g(x) = \sqrt{3-x} \) is substituted into \( f(x) \), resulting in simplification back to \( x \), given \( x \leq 3 \).
- Similarly, for \( g(f(x)) \), using \( f(x) = -x^2 + 3 \) as input into \( g(x) \) simplifies to \( x \), considering \( x \geq 0 \).
Domain and Range
Domains and ranges play an essential role in understanding and defining functions and their inverses.
- The domain of a function is the set of input values for which the function is defined. For \( f(x) = -x^2 + 3 \), the domain is \( x \geq 0 \), and for \( g(x) = \sqrt{3-x} \), it is \( x \leq 3 \).
- The range is the set of output values; for \( f(x) \), the range is \( y \leq 3 \), while for \( g(x) \), it is \( y \geq 0 \).
Other exercises in this chapter
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