Problem 19
Question
Evaluate each of the following determinants. $$ \left|\begin{array}{rr} \frac{3}{2} & -\frac{1}{2} \\ \frac{1}{2} & -\frac{2}{5} \end{array}\right| $$
Step-by-Step Solution
Verified Answer
The determinant is \(-\frac{7}{20}\).
1Step 1: Introduction to the Determinant of a 2x2 Matrix
To find the determinant of a 2x2 matrix \(\begin{pmatrix} a & b \ c & d \end{pmatrix}\), use the formula: \(\text{det} = ad - bc\). This exercise involves calculating the determinant of the matrix given by: $$\begin{pmatrix} \frac{3}{2} & -\frac{1}{2} \ \frac{1}{2} & -\frac{2}{5} \end{pmatrix}$$.
2Step 2: Identify Matrix Components
Identify and assign the components of the matrix to the variables in the formula. In the given matrix, let \(a = \frac{3}{2}\), \(b = -\frac{1}{2}\), \(c = \frac{1}{2}\), and \(d = -\frac{2}{5}\).
3Step 3: Compute \(ad\)
Calculate the product \(ad = \frac{3}{2} \times -\frac{2}{5}\). To do this, multiply the numerators together and the denominators together: \(ad = \frac{3 \times -2}{2 \times 5} = \frac{-6}{10} = -\frac{3}{5}\).
4Step 4: Compute \(bc\)
Calculate the product \(bc = -\frac{1}{2} \times \frac{1}{2}\). Again, multiply the numerators and the denominators: \(bc = \frac{-1 \times 1}{2 \times 2} = \frac{-1}{4}\).
5Step 5: Subtract the Results
Now, find the determinant by calculating \(ad - bc = -\frac{3}{5} - (-\frac{1}{4})\). This simplifies to: \(ad - bc = -\frac{3}{5} + \frac{1}{4}\).
6Step 6: Perform Fraction Subtraction
To subtract these fractions, first convert them to have a common denominator. The least common denominator of 5 and 4 is 20. Convert each fraction: \(-\frac{3}{5} = -\frac{12}{20}\) and \(\frac{1}{4} = \frac{5}{20}\). Subtract: \(-\frac{12}{20} + \frac{5}{20} = -\frac{7}{20}\).
7Step 7: Final Result
The determinant of the matrix is \(-\frac{7}{20}\).
Key Concepts
2x2 matrixmatrix componentsfraction subtraction
2x2 matrix
A matrix is a rectangular array of numbers arranged in rows and columns. In mathematics, matrices are used to organize data and perform calculations that can solve various kinds of problems. The most basic type of matrix is a 2x2 matrix, which has exactly two rows and two columns.
When you're working with a 2x2 matrix, you typically represent it like this:
One of the important computations you can perform on a 2x2 matrix is finding its determinant. The determinant is a special number that is calculated using the formula \(ad - bc\). This number is essential in understanding several matrix properties, including whether a matrix has an inverse. Understanding how to handle a 2x2 matrix lays the foundation for more complex matrix operations in higher dimensions.
When you're working with a 2x2 matrix, you typically represent it like this:
- The first row contains two elements, often labeled as \(a\) and \(b\).
- The second row contains two elements, often labeled as \(c\) and \(d\).
One of the important computations you can perform on a 2x2 matrix is finding its determinant. The determinant is a special number that is calculated using the formula \(ad - bc\). This number is essential in understanding several matrix properties, including whether a matrix has an inverse. Understanding how to handle a 2x2 matrix lays the foundation for more complex matrix operations in higher dimensions.
matrix components
When dealing with matrices, it's essential to properly identify and work with each element or component. In a 2x2 matrix, the components are crucial for various calculations, such as determining the determinant.
Let's revisit the matrix we used earlier: \[\begin{pmatrix} \frac{3}{2} & -\frac{1}{2} \ \frac{1}{2} & -\frac{2}{5} \end{pmatrix}\]To calculate the determinant of this 2x2 matrix using the formula \(ad - bc\), you must first label each component:
Let's revisit the matrix we used earlier: \[\begin{pmatrix} \frac{3}{2} & -\frac{1}{2} \ \frac{1}{2} & -\frac{2}{5} \end{pmatrix}\]To calculate the determinant of this 2x2 matrix using the formula \(ad - bc\), you must first label each component:
- \(a = \frac{3}{2}\)
- \(b = -\frac{1}{2}\)
- \(c = \frac{1}{2}\)
- \(d = -\frac{2}{5}\)
fraction subtraction
Fraction operations are important for many parts of mathematics, including the calculation of determinants in matrices. In our example, the final step to find the determinant involves subtracting two fractions.
Here's a quick overview of the subtraction process:
Here's a quick overview of the subtraction process:
- Determine a common denominator: The least common denominator of fractions with denominators 5 and 4 is 20, making calculation more manageable.
- Convert: Change \(-\frac{3}{5}\) to \(-\frac{12}{20}\) and \(\frac{1}{4}\) to \(\frac{5}{20}\).
- Subtract: Perform \(-\frac{12}{20} + \frac{5}{20} = -\frac{7}{20}\).
Other exercises in this chapter
Problem 18
For Problems \(17-32\), indicate the solution set for each system of inequalities by shading the appropriate region. $$ \left(\begin{array}{l} 3 x+2 y \leq 6 \\
View solution Problem 19
For Problems \(11-30\), use Cramer's rule to find the solution set of each system. (Objective 2) $$ \left(\begin{array}{rr} x-y+2 z= & 4 \\ 3 x-2 y+4 z= & 6 \\
View solution Problem 19
For Problems \(1-22\), solve each of the systems and use matrices as we did in the examples of this section. $$ \left(\begin{array}{rr} -3 x+2 y-z= & 12 \\ 5 x+
View solution Problem 19
Solve each of the following systems. If the solution set is \(\varnothing\) or if it contains infinitely many solutions, then so indicate. $$ \left(\begin{array
View solution