Problem 19
Question
Evaluate each expression, given that \(a=-2\) \(b=3,\) and \(c=-4\). $$|c|-|b|-|a|$$
Step-by-Step Solution
Verified Answer
-1
1Step 1: Find the Absolute Value of Each Variable
Calculate the absolute values for each variable: 1. Find \(|c|\): Since \(c = -4\), \(|c| = 4\).2. Find \(|b|\): Since \(b = 3\), \(|b| = 3\).3. Find \(|a|\): Since \(a = -2\), \(|a| = 2\).
2Step 2: Substitute the Absolute Values into the Expression
Substitute the absolute values we found in Step 1 into the expression \(|c| - |b| - |a|\):\[|c| - |b| - |a| = 4 - 3 - 2\]
3Step 3: Evaluate the Expression
Perform the subtraction operations:1. Subtract \(3\) from \(4\): \[4 - 3 = 1\]2. Subtract \(2\) from the result: \[1 - 2 = -1\]
4Step 4: Conclusion: Final Answer
The evaluated expression \(|c| - |b| - |a|\) simplifies to \(-1\).
Key Concepts
Evaluating ExpressionsSubstitutionPrecalculus Mathematics
Evaluating Expressions
When we talk about evaluating expressions, it essentially means calculating the value of a mathematical expression. In this context, using given numerical values, we follow specific instructions to arrive at the final result. Evaluating an expression often involves:
Understanding how to evaluate such expressions lays the foundation for solving more complex mathematical problems.
- Substituting known values into the expression.
- Performing arithmetic operations like addition, subtraction, multiplication, and division.
Understanding how to evaluate such expressions lays the foundation for solving more complex mathematical problems.
Substitution
Substitution is a method used to solve expressions where specific values replace variables. This technique simplifies the expression, making it easier to compute. To substitute means to:
- Take the known values associated with variables.
- Plug these values into the equation or expression.
- \(|a|=2\)
- \(|b|=3\)
- \(|c|=4\)
Precalculus Mathematics
Precalculus is a branch of mathematics that prepares students for calculus. It includes concepts like functions, algebra, trigonometry, and complex numbers. One vital component of precalculus is understanding and manipulating absolute values and expressions.
Precalculus teaches us how to handle absolute values, which represent the distance of a number from zero on a number line. This concept is fundamental, as shown in our problem where the absolute values of \( a = -2 \), \( b = 3 \), and \( c = -4 \) were pivotal in forming a solvable expression.
Moreover, precalculus emphasizes:
Precalculus teaches us how to handle absolute values, which represent the distance of a number from zero on a number line. This concept is fundamental, as shown in our problem where the absolute values of \( a = -2 \), \( b = 3 \), and \( c = -4 \) were pivotal in forming a solvable expression.
Moreover, precalculus emphasizes:
- Working with algebraic expressions and equations.
- Utilizing substitution to transform expressions.
- Developing skills for problem-solving, such as addressing the expression \(|c| - |b| - |a|\).
Other exercises in this chapter
Problem 19
The given points Pand Q are the endpoints of a diameter of a circle. Find (a) the center of the circle; (b) the radius of the circle. \(P(-4,-2)\) and \(Q(6,4)\
View solution Problem 19
Solve each equation. $$\frac{4}{x+2}+\frac{1}{x-2}=\frac{4}{x^{2}-4}$$
View solution Problem 20
Write an equation of: (a) a vertical line passing through the given point; (b) a horizontal line passing through the given point. $$(5,8)$$
View solution Problem 20
Determine any \(x\) - or \(y\) -intercepts for the graph of the equation. Note: You're not asked to draw the graph. (a) \(y=6 x^{3}+9 x^{2}+x\) (b) \(y=9 x^{3}+
View solution