Problem 19
Question
Determine whether the series is convergent, absolutely convergent, conditionally convergent, or divergent. \(\sum_{n=2}^{\infty} \frac{(-1)^{n} \ln n}{2^{n}}\)
Step-by-Step Solution
Verified Answer
The given series \(\sum_{n=2}^{\infty} \frac{(-1)^{n} \ln n}{2^{n}}\) is absolutely convergent, as determined by applying the Ratio Test on its absolute value series and obtaining a limit of \(\frac{1}{2}<1\).
1Step 1: Check for absolute convergence
First, we'll examine absolute convergence by taking the absolute value of the series terms and see if that series converges:
\[\sum_{n=2}^{\infty} \left| \frac{(-1)^{n} \ln n}{2^{n}} \right| = \sum_{n=2}^{\infty} \frac{\ln n}{2^{n}}\]
2Step 2: Ratio Test for Absolute Convergence
To determine the convergence of the absolute value series, we use the Ratio Test. For that, we'll compute the limit of the ratio of the terms:
\[\lim_{n\to\infty} \frac{\left|\frac{\ln (n+1)}{2^{n+1}}\right|}{\left|\frac{\ln n}{2^n}\right|} = \lim_{n\to\infty} \frac{\ln (n+1)}{\ln n} \cdot \frac{2^n}{2^{n+1}}\]
3Step 3: Simplify the Limit Expression
Now, we'll simplify the limit expression:
\[\lim_{n\to\infty} \frac{\ln (n+1)}{\ln n} \cdot \frac{2^n}{2^{n+1}} = \lim_{n\to\infty} \frac{\ln (n+1)}{\ln n} \cdot \frac{1}{2}\]
4Step 4: Evaluate the Limit
Using the rule \(\lim_{n\to\infty} \frac{\ln (n+1)}{\ln n} = 1\), we evaluate the limit:
\[\lim_{n\to\infty} \frac{\ln (n+1)}{\ln n} \cdot \frac{1}{2} = 1 \cdot \frac{1}{2} = \frac{1}{2}\]
Since the limit \(L = \frac{1}{2} < 1\), the absolute value series converges by the Ratio Test.
5Step 5: Conclusion
Since the absolute value series converges, we can conclude that the original series is absolutely convergent. Therefore, there's no need to check for conditional convergence.
6Step 6: Final Answer
The given series \(\sum_{n=2}^{\infty} \frac{(-1)^{n} \ln n}{2^{n}}\) is absolutely convergent.
Key Concepts
Absolute ConvergenceConditional ConvergenceRatio TestLimit of a Sequence
Absolute Convergence
In the realm of series and sequences, absolute convergence plays a pivotal role in understanding the behavior of infinite series. An infinite series \(\sum a_n\) is said to be absolutely convergent if the series of absolute values \(\sum |a_n|\) converges. When dealing with absolute convergence, we disregard the sign of individual terms and focus solely on their magnitudes.
A crucial aspect of absolute convergence is its strength; if a series converges absolutely, then it also converges in the usual sense. This property simplifies the analysis of series, as it allows us to first check whether a series converges absolutely. If it does, no further tests for convergence are necessary. Moreover, an absolutely convergent series can be rearranged in any order without affecting its sum, making it much more manageable mathematically.
A crucial aspect of absolute convergence is its strength; if a series converges absolutely, then it also converges in the usual sense. This property simplifies the analysis of series, as it allows us to first check whether a series converges absolutely. If it does, no further tests for convergence are necessary. Moreover, an absolutely convergent series can be rearranged in any order without affecting its sum, making it much more manageable mathematically.
Conditional Convergence
Contrasting with absolute convergence, conditional convergence occurs when an infinite series \(\sum a_n\) converges, but the series of its absolute values \(\sum |a_n|\) does not. In this scenario, the convergence hinges on the sequence of terms as well as their signs.
Conditionally convergent series are more delicate than their absolutely convergent counterparts. Reordering the terms of a conditionally convergent series can lead to different sums or even make the series diverge. Therefore, understanding whether convergence is absolute or conditional is critical when evaluating the properties and behavior of series.
Conditionally convergent series are more delicate than their absolutely convergent counterparts. Reordering the terms of a conditionally convergent series can lead to different sums or even make the series diverge. Therefore, understanding whether convergence is absolute or conditional is critical when evaluating the properties and behavior of series.
Ratio Test
The Ratio Test is an invaluable tool for determining the convergence of series, especially when the series involves factorials, exponentials, or other functions that grow quickly. To apply the Ratio Test, we calculate the limit of the ratio of consecutive terms in the absolute values series \(\lim_{n\to\infty} \frac{|a_{n+1}|}{|a_n|}\).
If this limit \(L\) is less than 1, the series converges absolutely. If \(L\) is greater than 1, or the limit does not exist, the series diverges. When the limit \(L\) is exactly 1, the test is inconclusive, and we must resort to other methods to determine convergence. The Ratio Test provides a fast and effective way to assess the convergence of series where the ratio of terms follows a discernable pattern.
If this limit \(L\) is less than 1, the series converges absolutely. If \(L\) is greater than 1, or the limit does not exist, the series diverges. When the limit \(L\) is exactly 1, the test is inconclusive, and we must resort to other methods to determine convergence. The Ratio Test provides a fast and effective way to assess the convergence of series where the ratio of terms follows a discernable pattern.
Limit of a Sequence
Understanding the concept of the limit of a sequence is fundamental when working with series and the Ratio Test. The limit of a sequence \(\{a_n\}\) as \(n\) approaches infinity, denoted by \(\lim_{n\to\infty} a_n\), represents the value that the sequence's terms get arbitrarily close to as \(n\) increases. In essence, it describes the long-term behavior of the sequence.
If the limit exists and is a finite number, the sequence is said to converge to that number. This concept is crucial when performing the Ratio Test, as we calculate the limit of the ratio of consecutive terms. A clear understanding of limits allows students to accurately evaluate the behavior of series and use the correct tools to determine convergence or divergence.
If the limit exists and is a finite number, the sequence is said to converge to that number. This concept is crucial when performing the Ratio Test, as we calculate the limit of the ratio of consecutive terms. A clear understanding of limits allows students to accurately evaluate the behavior of series and use the correct tools to determine convergence or divergence.
Other exercises in this chapter
Problem 18
Determine whether the sequence \(\left\\{a_{n}\right\\}\) converges or diverges. If it converges, find its limit. \(a_{n}=\frac{n^{2}-1}{2 n^{2}+1}\)
View solution Problem 19
Use the power series representations of functions established in this section to find the Taylor series of \(f\) at the given value of \(c .\) Then find the rad
View solution Problem 19
Use the Limit Comparison Test to determine whether the series is convergent or divergent. \(\sum_{n=2}^{\infty} \frac{1}{\sqrt{n^{3}-n-1}}\)
View solution Problem 19
Find the radius of convergence and the interval of convergence of the power series. $$ \sum_{n=0}^{\infty} \frac{(-1)^{n}(x+2)^{2 n+1}}{(2 n+1) !} $$
View solution