Problem 19
Question
Determine convergence or divergence for each of the series. Indicate the test you use. \(\frac{1}{1 \cdot 2}+\frac{1}{2 \cdot 3}+\frac{1}{3 \cdot 4}+\frac{1}{4 \cdot 5}+\cdots\) Hint: \(a_{n}=\frac{1}{n(n+1)}\)
Step-by-Step Solution
Verified Answer
The series converges by the telescoping series test.
1Step 1: Express the General Term
The general term of the series is given by \( a_n = \frac{1}{n(n+1)} \). This will help us determine the behavior of the series as \( n \) goes to infinity.
2Step 2: Simplify the General Term
Notice that \( \frac{1}{n(n+1)} \) can be rewritten using partial fractions: \( \frac{1}{n(n+1)} = \frac{1}{n} - \frac{1}{n+1} \). This telescopic form is useful for determining convergence.
3Step 3: Analyze the Telescoping Series
Write out the terms of the series using the telescoping form: \( \left( \frac{1}{1} - \frac{1}{2} \right) + \left( \frac{1}{2} - \frac{1}{3} \right) + \left( \frac{1}{3} - \frac{1}{4} \right) + \cdots \). Most terms cancel out, leaving only the first term of the first fraction and the limit of the last one.
4Step 4: Determine Series Convergence
Since the series telescopes to \( \sum_{n=1}^{\infty} (\frac{1}{n} - \frac{1}{n+1}) = 1 \), the series converges. The remaining term after cancellation is 1 as \( n \to \infty \), which indicates the series sums to a finite number.
Key Concepts
Telescoping SeriesPartial Fraction DecompositionInfinite Series ConvergenceMathematical Series Analysis
Telescoping Series
A telescoping series is a type of infinite series where consecutive terms cancel each other partially or completely. This results in a simplified expression that makes analyzing the series more straightforward.
To see how it works, let's look at the series from the exercise:
This cancellation drastically simplifies the problem, often leaving just a few terms that don't cancel, helping us quickly find the limit of the series. In this case, the series telescopes to where only the first and a partial piece of the last term remain.
To see how it works, let's look at the series from the exercise:
- Original series term: \( \frac{1}{n(n+1)} \).
- Transformed into telescoping form: \( \frac{1}{n} - \frac{1}{n+1} \).
This cancellation drastically simplifies the problem, often leaving just a few terms that don't cancel, helping us quickly find the limit of the series. In this case, the series telescopes to where only the first and a partial piece of the last term remain.
Partial Fraction Decomposition
Partial Fraction Decomposition is an algebraic technique that involves breaking down complex rational expressions into simpler fractions. This method is crucial for simplifying terms in many series, especially those involving products in the denominator.
In our series, the expression \( \frac{1}{n(n+1)} \) can be decomposed as:
In our series, the expression \( \frac{1}{n(n+1)} \) can be decomposed as:
- Decomposition: \( \frac{1}{n} - \frac{1}{n+1} \).
Infinite Series Convergence
Infinite series convergence refers to whether or not the sum of all terms in a series approaches a finite value as more terms are added. There are various tests to determine convergence, focusing on different properties or behaviors of series.
For our telescoping series, convergence is determined by:
For our telescoping series, convergence is determined by:
- Identifying cancellation of intermediate terms.
- Observing the finite result from the remaining terms.
Mathematical Series Analysis
Mathematical series analysis involves examining the behavior of series to understand their properties, convergence, divergence, and potential applications. Analyzing a series employs various mathematical tools and tests.
Key points to consider:
- Simplification of terms, like partial fraction decomposition.
- Pattern recognition, such as telescoping, to streamline evaluation.
- Utilizing convergence tests to determine if a series sums to a finite number.
Other exercises in this chapter
Problem 19
Classify each series as absolutely convergent, conditionally convergent, or divergent. $$ \sum_{n=1}^{\infty}(-1)^{n+1} \frac{n^{4}}{2^{n}} $$
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Find the convergence set for the given power series. Hint: First find a formula for the nth term; then use the Absolute Ratio Test. $$ 1-\frac{x}{2}+\frac{x^{2}
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Use any test developed so far, including any from Section \(9.2\), to decide about the convergence or divergence of the series. Give a reason for your conclusio
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An explicit formula for \(a_{n}\) is given. Write the first five terms of \(\left\\{a_{n}\right\\}\), determine whether the sequence converges or diverges, and,
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