Problem 19
Question
Begin by graphing the square root function, \(f(x)=\sqrt{x} .\) Then use transformations of this graph to graph the given function. $$ g(x)=\frac{1}{2} \sqrt{x+2} $$
Step-by-Step Solution
Verified Answer
The graph of the function \(g(x)=\frac{1}{2} \sqrt{x+2}\) is obtained by shifting the graph of the function \(f(x)=\sqrt{x}\) 2 units to the left and scaling vertically by a factor of \(\frac{1}{2}\).
1Step 1: Graph the original function
Begin by graphing the parent function \(f(x)=\sqrt{x}\). The graph should start at the origin and increase slowly, since for every \(x\), \(f(x)\) is the square root of \(x\) which gets bigger more slowly than \(x\) itself.
2Step 2: Apply the horizontal shift
Now apply a horizontal shift to the left by 2 units. This corresponds to the \(+2\) inside the square root in \(g(x)\). This means that the entire graph of \(f(x)\) should be moved 2 units to the left. As a result, instead of the graph starting at the origin, it should now start at \((-2,0)\).
3Step 3: Apply the vertical scaling
Lastly, apply a vertical scaling to the graph. This corresponds to the \(\frac{1}{2}\) multiplier in \(g(x)\). This means every y-value should be halved. So if on \(f(x)\), when \(x=1\), \(y=1\), on \(g(x)\) when \(x=1\), \(y = \frac{1}{2}\).
4Step 4: Draw the new graph
Now, draw the new graph incorporating both transformations. Remember, the graph should start at \(-2, 0\) rather than the origin because of the horizontal shift, and it should rise more slowly than the graph of \(f(x)=\sqrt{x}\) because of the vertical scaling due to the \(\frac{1}{2}\) multiplier.
Key Concepts
Square Root FunctionHorizontal ShiftVertical Scaling
Square Root Function
The square root function is fundamental in mathematics, represented as \( f(x) = \sqrt{x} \). Let's explore its characteristics to understand why it's essential for transformations. This function starts at the origin, \((0,0)\), and progresses slowly upwards. Unlike linear functions where y-values increase consistently with x, here each increase in x results in smaller increases in y. For example:
- When \( x = 0 \): \( f(x) = 0 \)
- When \( x = 1 \): \( f(x) = 1 \)
- When \( x = 4 \): \( f(x) = 2 \)
Horizontal Shift
A horizontal shift adjusts the position of the graph sideways. In our exercise, the function \( g(x) = \frac{1}{2} \sqrt{x+2} \) involves a horizontal shift due to the \(+2\) inside the square root. Here's how it works:
- The expression \( +2 \) means we shift the graph 2 units to the left. It's counterintuitive since one might expect a positive sign to move in the positive direction, but within functions, adding a number inside the argument (inside the square root for this example) moves the graph in the opposite direction.
- This transformation changes the starting point from the origin (\(0,0\)) to \((-2,0\)).
Vertical Scaling
Vertical scaling adjusts how much the graph stretches or compresses vertically. In \( g(x) = \frac{1}{2} \sqrt{x+2} \), the factor \( \frac{1}{2} \) indicates scaling. Understanding vertical scaling:
- The factor \( \frac{1}{2} \) dictates that each y-value in the parent function \( f(x) = \sqrt{x} \) is halved. If \( y \) was originally 2, it will now be \( 1 \).
- This modification influences how steep or flat the graph appears. Each point is moved closer to the x-axis, resulting in a graph that rises less steeply than the original.
Other exercises in this chapter
Problem 18
In Exercises \(9-20,\) determine whether each equation defines \(y\) as a function of \(x .\) $$y=-\sqrt{x+4}$$
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Find: a. \((f \circ g)(x)\) b. \(\left(g^{\circ} f\right)(x)\) c. \((f \circ g)(2)\) $$f(x)=x+4, g(x)=2 x+1$$
View solution