Problem 19
Question
A ray of light is traveling in a glass cube that is totally immersed in water. You find that if the ray is incident on the glass-water interface at an angle to the normal larger than 48.7\(^\circ\), no light is refracted into the water. What is the refractive index of the glass?
Step-by-Step Solution
Verified Answer
The refractive index of the glass is approximately 1.765.
1Step 1: Understand the Problem
The problem involves a ray of light traveling through a glass cube in water. We are asked to find the refractive index of glass when total internal reflection occurs at an angle of 48.7°.
2Step 2: Identify Relevant Concept
The critical angle problem requires using Snell's Law for refraction and the concept of total internal reflection. Total internal reflection occurs when the angle of incidence exceeds the critical angle.
3Step 3: Calculate the Critical Angle
The critical angle \( \theta_c \) is given as 48.7°. The relationship between the refractive indices of glass and water is defined by \( n_{glass} \sin(\theta_c) = n_{water} \sin(90°) \).
4Step 4: Apply Snell's Law
Snell's Law is \( n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \). Since \( \theta_2 = 90° \) at the critical angle, we have \( n_{glass} \sin(48.7°) = n_{water} \).
5Step 5: Rearrange and Solve for the Refractive Index of Glass
Using the known refractive index of water \( n_{water} = 1.33 \), solve for \( n_{glass} \): \[ n_{glass} = \frac{1.33}{\sin(48.7°)}\]Calculate the value using \( \sin(48.7°) \approx 0.7536 \).
6Step 6: Perform Calculation
Substitute \( \sin(48.7°) \) into the equation to find:\[n_{glass} = \frac{1.33}{0.7536} \approx 1.765\]
Key Concepts
Snell's Lawtotal internal reflectioncritical anglerefractive index
Snell's Law
Snell's Law is a fundamental principle in optics that describes how light rays change direction as they pass from one medium to another. It is expressed with the equation \( n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \), where:
- \( n_1 \) and \( n_2 \) are the refractive indices of the two different media.
- \( \theta_1 \) is the angle of incidence, and \( \theta_2 \) is the angle of refraction.
total internal reflection
Total internal reflection is a phenomenon that occurs when a light ray traveling through a medium hits the boundary with a less dense medium at an angle greater than the critical angle. Under these conditions, the ray doesn't exit the medium; instead, it reflects entirely back into the original medium. It only happens when:
- The light is traveling from a denser to a less dense medium.
- The angle of incidence is greater than the medium's critical angle.
critical angle
The critical angle is the minimum angle of incidence at which total internal reflection occurs. It is specific to the pair of media through which the light is traveling and can be calculated using Snell's Law:\[\theta_c = \arcsin\left( \frac{n_2}{n_1} \right)\]Where:
- \(\theta_c\) is the critical angle.
- \(n_1\) is the refractive index of the denser medium.
- \(n_2\) is the refractive index of the less dense medium.
refractive index
The refractive index is a dimensionless number that describes how light propagates through a medium. When light passes from air (refractive index ≈ 1) into another material, like water or glass, it slows down, and its direction changes. The amount of bending or refraction depends on the refractive indices of the involved materials.
- Refractive Index (n): \( n = \frac{c}{v} \)
- \(c\) is the speed of light in a vacuum.
- \(v\) is the speed of light in the material.
Other exercises in this chapter
Problem 17
The critical angle for total internal reflection at a liquid air interface is 42.5\(^\circ\). (a) If a ray of light traveling in the liquid has an angle of inci
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The indexes of refraction for violet light \((\lambda = 400 \, \mathrm{nm})\) and red light \((\lambda = 700 \, \mathrm{nm})\) in diamond are 2.46 and 2.41, res
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