Problem 19
Question
A point charge has a charge of \(2.50 \times 10^{-11} \mathrm{C}\) . At what distance from the point charge is the electric potential (a) 90.0 \(\mathrm{V}\) and (b) 30.0 \(\mathrm{V}\) ? Take the potential to be zero at an infinite distance from the charge.
Step-by-Step Solution
Verified Answer
Distances are 0.25 m for 90 V and 0.75 m for 30 V.
1Step 1: Understand the Formula for Electric Potential
The electric potential \( V \) due to a point charge \( q \) at a distance \( r \) is given by the formula:\[V = \frac{k \cdot q}{r}\]where \( k \) is Coulomb's constant, approximately \(8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2\). The problem tells us to find \( r \) for particular values of \( V \).
2Step 2: Solve for Distance When Potential is 90.0 V
Rearrange the formula to solve for \( r \):\[r = \frac{k \cdot q}{V}\]Substitute the given values, \( q = 2.50 \times 10^{-11} \, \text{C} \) and \( V = 90.0 \, \text{V} \):\[r = \frac{8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \times 2.50 \times 10^{-11} \, \text{C}}{90.0 \, \text{V}}\]Calculate \( r \):\[r \approx 0.25 \, \text{m}\]
3Step 3: Solve for Distance When Potential is 30.0 V
Use the same rearranged formula to find \( r \) for \( V = 30.0 \, \text{V} \):\[r = \frac{8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \times 2.50 \times 10^{-11} \, \text{C}}{30.0 \, \text{V}}\]Calculate \( r \):\[r \approx 0.75 \, \text{m}\]
4Step 4: Verify and Conclude
Both distances have been calculated under the assumption that potential decreases with increasing distance, aligning with the physical expectation for an isolated point charge. The calculations are consistent and adhere to the physical principles governing electric potential.
Key Concepts
Point ChargeCoulomb's LawElectric FieldPhysics Education
Point Charge
A point charge is a theoretical concept in physics indicating an electric charge concentrated at a single point in space. Although it doesn't actually exist as a physical entity, it serves as a useful model for understanding electric forces and potential in simpler terms. By thinking of electric charges in this way, complex systems can be broken down and analyzed more easily.
Understanding point charges helps in predicting how electric fields behave around charged objects. Since the charge is concentrated at a specific location, the effects of that charge, like the electric field or potential, can be calculated in a straightforward manner using mathematical formulas. This approach provides a foundation for more complex concepts in electromagnetism.
Understanding point charges helps in predicting how electric fields behave around charged objects. Since the charge is concentrated at a specific location, the effects of that charge, like the electric field or potential, can be calculated in a straightforward manner using mathematical formulas. This approach provides a foundation for more complex concepts in electromagnetism.
Coulomb's Law
Coulomb's Law is central to the study of electric charges and their interactions. It states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The mathematical expression for Coulomb's Law is:
The mathematical expression for Coulomb's Law is:
- Formula: \( F = k \frac{|q_1 q_2|}{r^2} \)
- Where:
- \( F \) is the force between the charges,
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges,
- \( r \) is the distance between the charges,
- \( k \) is Coulomb's constant.
Electric Field
The electric field is a vector field that represents the force a charge would experience at any point in space. It gives a complete picture of how a point charge influences its surrounding environment and defines how other charges will react when placed in an area.
- The formula for the electric field \( E \) due to a point charge \( q \) is:\[ E = \frac{k \, q}{r^2} \]
- This shows that the field strength decreases with the square of the distance \( r \) from the charge causing it.
Physics Education
Physics education focuses on understanding the fundamental principles that govern the natural world. Concepts like electric potential, point charges, and Coulomb's Law form the backbone of classical physics study and pave the way for exploring advanced topics.
- Effective learning strategies include:
- Breaking down complex theories into simpler components.
- Applying real-world problems to theoretical concepts.
- Engaging in hands-on experiments to see theory in action.
- Thinking critically about results and their implications encourages deeper comprehension and retention of material.
Other exercises in this chapter
Problem 17
A charge of 28.0 \(\mathrm{nC}\) is placed in a uniform electric field that is directed vertically upward and has a magnitude of \(4.00 \times 10^{4} \mathrm{V}
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Two charges of equal magnitude \(Q\) are beld a distance \(d\) apart. Consider only points on the line passing through both charges. (a) If the two charges have
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Two positive point charges, each of magnitude \(q,\) are fixed on the \(y\) -axis at the points \(y=+a\) and \(y=-a\) . Take the potential to be zero at an infi
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