Problem 19
Question
19 Suppose \(y=m x+b\) for negative \(x\) and \(y=M x+B\) for \(x \geqslant 0 .\) The graphs meet if _________ The two slopes are____________. The slope at \(x=0\) is __________( what is possible? \()\)
Step-by-Step Solution
Verified Answer
The graphs meet when \( b = B \); the slopes are \( m \) and \( M \); the slope at \( x=0 \) can be undefined or a point of non-smooth transition.
1Step 1: Understanding the Problem
The problem involves two linear equations. The first equation is \( y = mx + b \) for negative \( x \), and the second equation is \( y = Mx + B \) for non-negative \( x \). Our task is to determine the conditions under which these two graphs meet and explore details about the slopes.
2Step 2: Finding the Intersection Point
For the graphs of the equations \( y = mx + b \) and \( y = Mx + B \) to meet, they must have a common point. This means their \( y \)-values must be equal at the same \( x \) value. The potential point of intersection is at \( x = 0 \). At this point, both equations must satisfy the equality \( b = B \).
3Step 3: Analyzing the Slopes
The slopes of the equations are given by \( m \) and \( M \) respectively. Even though they are different for \( x < 0 \) and \( x \geq 0 \), at the meeting point, the behavior of the graph may change depending on these slopes.
4Step 4: Calculating the Slope at \( x=0 \)
At \( x=0 \), the slope can be considered as a transition between the two equations. Therefore, the slope at this point would generally not be defined as a single value unless \( m = M \). If the slopes are different, \( x = 0 \) could mark a point of non-smooth transition.
Key Concepts
Intersection PointSlopePiecewise FunctionsCoordinate Geometry
Intersection Point
An intersection point between two graphs is where both equations share the same coordinates, implying that their respective outputs are equal at this specific input. In the given problem, we have the equations:
- \(y = mx + b\) for \(x < 0\)
- \(y = Mx + B\) for \(x \geq 0\)
Slope
The slope of a line represents its steepness and direction. It is generally given as the coefficient of \(x\) when a line is in the form \(y = mx + b\). For the given lines:
- The slope for \(y = mx + b\) (for negative \(x\)) is \(m\).
- The slope for \(y = Mx + B\) (for \(x \geq 0\)) is \(M\).
Piecewise Functions
Piecewise functions are defined by different expressions over various intervals. In this exercise, we see a piecewise scenario with:
- \(y = mx + b\) when \(x < 0\)
- \(y = Mx + B\) when \(x \geq 0\)
Coordinate Geometry
Coordinate geometry is the study of geometric figures through the coordinate plane, using algebraic formulas and graphs. It helps us visualize equations and solutions. In this problem, coordinate geometry involves plotting:
- The line segment \(y = mx + b\) for \(x < 0\)
- The line segment \(y = Mx + B\) for \(x \geq 0\)
Other exercises in this chapter
Problem 19
Determine \(c\) so that the straight line joining (0,3) and (5,-2) is tangent to the curve \(y=c /(x+1)\)
View solution Problem 19
Where does \(y=\sin x+\cos x\) have zero slope?
View solution Problem 20
Find the limits if they exist. An \(\varepsilon-\delta\) test is not required. $$ \lim _{x \rightarrow 2} \frac{\sqrt{4-x}}{\sqrt{6+x}} $$
View solution Problem 20
At a point where \(d y / d x=0\), what is special about the graph of \(y(x)\) ? Test case: \(y=x^{2}\).
View solution