Problem 19
Question
\(17-24=\) Sketch the set in the complex plane. $$ \\{z| | z |=3\\} $$
Step-by-Step Solution
Verified Answer
The set is a circle of radius 3 centered at the origin in the complex plane.
1Step 1: Analyze the Set Notation
The given set \(\{z \ | \ |z| = 3\}\) specifies all complex numbers \(z\) whose modulus is 3.
2Step 2: Understand Modulus in the Complex Plane
In the complex plane, the modulus of a complex number \(z = a + bi\) is given by \(|z| = \sqrt{a^2 + b^2}\). A constant modulus forms a circle centered at the origin.
3Step 3: Sketch the Circle
Since \(|z| = 3\) represents all points at a distance of 3 from the origin, it's a circle with radius 3 centered at the origin in the complex plane. To sketch it, imagine a circle centered at the origin, with every point on the circle having a distance of 3 from (0,0).
Key Concepts
Modulus of Complex NumberCircle in Complex PlaneComplex Numbers
Modulus of Complex Number
When we talk about the modulus of a complex number, we refer to its size or magnitude. A complex number is generally represented as \(z = a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. To find how 'long' this complex number is from the origin on the complex plane, we use the modulus. This can be thought of like finding the length of a vector.The modulus is calculated using the formula:
- \(|z| = \sqrt{a^2 + b^2}\)
Circle in Complex Plane
A circle in the complex plane can be visualized with ease thanks to the modulus of a complex number. When we specify that the modulus of a complex number \(|z|\) is a constant, like 3, we are indicating a particular set of points.
- Each point is at the same distance from the origin.
- That distance is the radius of the circle.
Complex Numbers
Complex numbers are at the core of mathematics and engineering because they give us an advanced, yet understandable way to manage problems involving two dimensions. A standard complex number takes the form \(z = a + bi\), where \(a\) and \(b\) are real numbers.
- \(a\) is called the 'real part'.
- \(b\) is the 'imaginary part', where \(i = \sqrt{-1}\).
- The horizontal axis is the real part.
- The vertical axis is the imaginary part.
Other exercises in this chapter
Problem 19
Find \(2 \mathbf{u},-3 \mathbf{v}, \mathbf{u}+\mathbf{v},\) and \(3 \mathbf{u}-4 \mathbf{v}\) for the given vectors \(\mathbf{u}\) and \(\mathbf{v} .\) $$ \math
View solution Problem 19
19-22 Find the component of \(\mathbf{u}\) along \(\mathbf{v}\). $$\mathbf{u}=\langle 4,6\rangle, \quad \mathbf{v}=\langle 3,-4\rangle$$
View solution Problem 19
15–36 Sketch the graph of the polar equation. $$r=6 \sin \theta$$
View solution Problem 20
Find \(2 \mathbf{u},-3 \mathbf{v}, \mathbf{u}+\mathbf{v},\) and \(3 \mathbf{u}-4 \mathbf{v}\) for the given vectors \(\mathbf{u}\) and \(\mathbf{v} .\) $$ \math
View solution