Problem 19
Question
\(15-28=(a)\) Use the discriminant to determine whether the graph of the equation is a parabola, an ellipse, or a hyperbola. (b) Use a rotation of axes to eliminate the \(x y\) -term. (c) Sketch the graph. $$ 11 x^{2}-24 x y+4 y^{2}+20=0 $$
Step-by-Step Solution
Verified Answer
(a) The graph is a hyperbola. (b) Use rotation to eliminate the \(xy\)-term. (c) Sketch the hyperbola.
1Step 1: Identifying the Discriminant
To determine the type of conic section described by the quadratic equation, we first calculate the discriminant. The discriminant for a general conic equation of the form \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\) is given by \(B^2 - 4AC\). For the given equation \(11x^2 - 24xy + 4y^2 + 20 = 0\), identify \(A = 11\), \(B = -24\), and \(C = 4\). Then compute the discriminant: \((-24)^2 - 4(11)(4)\).
2Step 2: Calculating the Discriminant
Now compute \((-24)^2 - 4 \times 11 \times 4\). First, find \((-24)^2 = 576\). Next, calculate \(4 \times 11 \times 4 = 176\). Subtract \(176\) from \(576\) to get \(400\). Since the discriminant \(400\) is greater than zero, the conic section is a hyperbola.
3Step 3: Eliminating the \(xy\)-Term via Rotation
To eliminate the \(xy\)-term, we need to perform a rotation of axes. The angle \(\theta\) for the rotation is given by \(\cot(2\theta) = \frac{A-C}{B}\). Plugging in the values, \(\cot(2\theta) = \frac{11 - 4}{-24} = \frac{7}{-24}\). Solve \(\theta\) using this equation which involves using the inverse cotangent function.
4Step 4: Finding the Angle of Rotation
Solve for \(\theta\) such that \(\tan(2\theta) = \frac{-24}{7}\). Use the identity \(\tan(2\theta) = \frac{2\tan(\theta)}{1 - \tan^2(\theta)}\) to express \(\tan(\theta)\). It results in complex algebraic manipulations or using a calculator to find \(\theta\) approximately.
5Step 5: Rewrite the Equation After Rotation
Use the angle found to substitute \(x = x'\cos(\theta) - y'\sin(\theta)\) and \(y = x'\sin(\theta) + y'\cos(\theta)\) into the original equation. After substitution and simplification, the new equation should be of the form \(A'x'^2 + C'y'^2 + D'x' + E'y' + F' = 0\) with no \(x'y'\)-term.
6Step 6: Sketching the Graph
Once the rotated equation has no \(x'y'\) term, determine the new conic's center, axes, and sketches. Since it's a hyperbola, identify the vertices and asymptotes and sketch the hyperbola on the \(x'y'\)-plane.
Key Concepts
Discriminant of Conic SectionsRotation of AxesHyperbola
Discriminant of Conic Sections
The discriminant is a crucial part of understanding conic sections. It helps us differentiate between different types of conics such as parabolas, ellipses, and hyperbolas. The general form of a conic section equation is given by:\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]To find the discriminant, we use the formula \( B^2 - 4AC \). The values of \( A \), \( B \), and \( C \) are coefficients from the equation. Here's how the discriminant determines the type of conic:
This positive result confirms that our conic section is a hyperbola.
- If \( B^2 - 4AC = 0 \), it's a parabola.
- If \( B^2 - 4AC > 0 \), it's a hyperbola.
- If \( B^2 - 4AC < 0 \), it's an ellipse.
This positive result confirms that our conic section is a hyperbola.
Rotation of Axes
To simplify the equation of a conic section, especially when trying to remove the \(xy\)-term, the rotation of axes technique is employed. The general idea is to rotate the coordinate system to eliminate this term, making the equation easier to analyze.The angle of rotation, \(\theta\), is determined by the formula:\[ \cot(2\theta) = \frac{A - C}{B} \]For our given equation, substituting in the values we find:\[ \cot(2\theta) = \frac{11 - 4}{-24} = \frac{7}{-24} \]Solve for \( \theta \) by calculating the inverse cotangent. Numerical methods or a calculator make this task smoother.
After determining \( \theta \), the substitution:
After determining \( \theta \), the substitution:
- \( x = x'\cos(\theta) - y'\sin(\theta) \)
- \( y = x'\sin(\theta) + y'\cos(\theta) \)
Hyperbola
A hyperbola is a conic section often identified by its characteristic shape with two disconnected curves. This shape appears prominently when the discriminant \(B^2 - 4AC > 0\) for a given equation.Key features of a hyperbola include:
A hyperbola's equation can be written in a more familiar form as:\[ \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \]If the conic has undergone rotation, adjust the coordinates using the rotation angle to fit this standard form.
Understanding hyperbolas in relation to other conic sections broadens the ability to tackle real-world applications, like satellite dish design and radiation patterns.
- Two branches or "wings" opening opposite directions.
- A pair of asymptotes that the branches approach but never touch.
- A center, vertices, and foci that help define its shape.
A hyperbola's equation can be written in a more familiar form as:\[ \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \]If the conic has undergone rotation, adjust the coordinates using the rotation angle to fit this standard form.
Understanding hyperbolas in relation to other conic sections broadens the ability to tackle real-world applications, like satellite dish design and radiation patterns.
Other exercises in this chapter
Problem 19
Find the vertices, foci, and asymptotes of the hyperbola, and sketch its graph. $$ 4 y^{2}-x^{2}=1 $$
View solution Problem 19
A polar equation of a conic is given. (a) Show that the conic is a parabola and sketch its graph. (b) Find the vertex and directrix and indicate them on the gra
View solution Problem 19
Find the vertices, foci, and eccentricity of the ellipse. Determine the lengths of the major and minor axes, and sketch the graph. $$ \frac{1}{2} x^{2}+\frac{1}
View solution Problem 19
\(11-22\) . Find the focus, directrix, and focal diameter of the parabola, and sketch its graph. $$ x^{2}+6 y=0 $$
View solution