Problem 1896
Question
Two wires of same length are shaped into a square and a circle. If they carry same current, ratio of the magnetic moment is (a) \(2: \pi\) (b) \(\pi: 2\) (c) \(\pi: 4\) (d) \(4: \pi\)
Step-by-Step Solution
Verified Answer
The ratio of the magnetic moment of the square to the circle is \(\pi: 2\), which corresponds to option (b).
1Step 1: Calculate the magnetic moment of the square wire
Let's denote the length of the wire as L. Since the wire is shaped into a square, each side of the square will have a length of L/4. The area A_s of the square can be calculated as:
\[A_s = (\frac{L}{4})^2\]
Now, let's denote the current passing through the wire as I. The magnetic moment M_s of the square can be calculated as:
\[M_s = I \cdot A_s\]
By substituting the area of the square, we get:
\[M_s = I \cdot (\frac{L}{4})^2\]
2Step 2: Calculate the magnetic moment of the circle wire
To find the magnetic moment of the circle wire, we first need to determine its radius. Since the circumference of the circle is equal to the length of the wire, we have:
\[2\pi r = L\]
Solving for the radius r, we get:
\[r = \frac{L}{2\pi}\]
Now, we can calculate the area A_c of the circle as:
\[A_c = \pi r^2\]
Substituting the radius, we get:
\[A_c = \pi (\frac{L}{2\pi})^2\]
The magnetic moment M_c of the circle can be calculated as:
\[M_c = I \cdot A_c\]
By substituting the area of the circle, we get:
\[M_c = I \cdot \pi (\frac{L}{2\pi})^2\]
3Step 3: Calculate the ratio of the magnetic moments
We need to find the ratio of the magnetic moments of the square and the circle:
\[\frac{M_s}{M_c} = \frac{I \cdot (\frac{L}{4})^2}{I \cdot \pi (\frac{L}{2\pi})^2}\]
We can see that the current I and the length L will cancel out, so the ratio of the magnetic moments simplifies to:
\[\frac{M_s}{M_c} = \frac{(\frac{1}{4})^2}{\pi (\frac{1}{2\pi})^2}\]
After calculating the ratio, we arrive at the following:
\[\frac{M_s}{M_c} = \frac{1}{16} \cdot \frac{4\pi^2}{\pi}\]
This further simplifies to:
\[\frac{M_s}{M_c} = \frac{\pi}{2}\]
So the ratio of the magnetic moment of the square to the circle is \(\pi: 2\), which corresponds to option (b).
Key Concepts
Square WireCircle WireCurrentArea of Shapes
Square Wire
A square wire is formed when a wire is bent to create a four-sided figure with equal sides. When dealing with the magnetic moment, understanding the geometry of the square is crucial. The magnetic moment of a current-carrying wire depends on the area enclosed by the wire.
For a square, each side has the same length. If the total length of the wire is denoted as \( L \), each side of the square will therefore be \( \frac{L}{4} \).
For a square, each side has the same length. If the total length of the wire is denoted as \( L \), each side of the square will therefore be \( \frac{L}{4} \).
- Area of the square, \( A_s = (\frac{L}{4})^2 \)
- Magnetic moment, \( M_s = I \cdot A_s \)
Circle Wire
A circle wire is obtained when a wire is shaped into a circle, forming a closed loop. This shape is vital in magnetic moment calculations as the circular form provides a different area compared to the square.
The circumference of a circle wire equals the total length of the wire, \( L \), giving us \( 2\pi r = L \) where \( r \) is the radius.
The circumference of a circle wire equals the total length of the wire, \( L \), giving us \( 2\pi r = L \) where \( r \) is the radius.
- Solve to find the radius: \( r = \frac{L}{2\pi} \)
- Area of the circle, \( A_c = \pi r^2 \)
- Substituting \( r \), \( A_c = \pi (\frac{L}{2\pi})^2 \)
Current
Current, represented as \( I \), is the flow of electric charge in a wire. It is a fundamental component when determining the magnetic moment of any wire.
The magnetic moment \( M \) is directly proportional to the current and the area encapsulated by the wire.
The magnetic moment \( M \) is directly proportional to the current and the area encapsulated by the wire.
- Square wire: \( M_s = I \cdot (\frac{L}{4})^2 \)
- Circle wire: \( M_c = I \cdot \pi (\frac{L}{2\pi})^2 \)
Area of Shapes
The area of shapes plays a pivotal role in calculating the magnetic moment for wires of different configurations.
For a square wire, the area is simple to compute as the square comprises readily defined straight lines:
For a square wire, the area is simple to compute as the square comprises readily defined straight lines:
- Calculate area, \( A_s = (\frac{L}{4})^2 \)
- Calculate area, \( A_c = \pi (\frac{L}{2\pi})^2 \)
Other exercises in this chapter
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