Problem 189
Question
Write two conversion factors that express the relationship between: (a) Grams and kilograms, using 1 and 1000 (b) Kilograms and grams, using 1 and \(0.001\) (c) Yards and feet (d) Meters and centimeters, using 1 and 100 (e) Meters and centimeters, using 1 and \(0.01\)
Step-by-Step Solution
Verified Answer
(a) Grams and kilograms: \( \frac{1000 \text{ g}}{1 \text{ kg}} \) and \( \frac{1 \text{ kg}}{1000 \text{ g}}\)
(b) Kilograms and grams: \( \frac{1 \text{ g}}{0.001 \text{ kg}} \) and \( \frac{0.001 \text{ kg}}{1 \text{ g}} \)
(c) Yards and feet: \( \frac{1 \text{ yd}}{3 \text{ ft}} \) and \( \frac{3 \text{ ft}}{1 \text{ yd}} \)
(d) Meters and centimeters: \( \frac{1 \text{ m}}{100 \text{ cm}} \) and \( \frac{100 \text{ cm}}{1 \text{ m}}\)
(e) Meters and centimeters: \( \frac{1 \text{ m}}{0.01 \text{ cm}} \) and \( \frac{0.01 \text{ cm}}{1 \text{ m}} \)
1Step 1: Conversion factor 1 from grams to kilograms
For every 1000 grams, we have 1 kilogram, since 1 kilogram is equal to 1000 grams: \( \frac{1000 \text{ g}}{ 1 \text{ kg}} \)
2Step 2: Conversion factor 2 from kilograms to grams
For each kilogram, there are 1000 grams: \( \frac{1 \text{ kg}}{1000 \text{ g}}\)
(b) Kilograms and grams, using 1 and \(0.001\)
3Step 3: Conversion factor 3 from grams to kilograms
For each gram, there is \(0.001\) kilogram: \( \frac{1 \text{ g}}{0.001 \text{ kg}} \)
4Step 4: Conversion factor 4 from kilograms to grams
For each kilogram, there are 1000 grams, and since \(0.001\) is the reciprocal of 1000: \( \frac{0.001 \text{ kg}}{1 \text{ g}} \)
(c) Yards and feet
5Step 5: Conversion factor 5 from yards to feet
For every yard, there are 3 feet: \( \frac{1 \text{ yd}}{3 \text{ ft}} \)
6Step 6: Conversion factor 6 from feet to yards
For each foot, there is \(\frac{1}{3}\) of a yard: \( \frac{3 \text{ ft}}{1 \text{ yd}} \)
(d) Meters and centimeters, using 1 and 100
7Step 7: Conversion factor 7 from meters to centimeters
For every meter, there are 100 centimeters: \( \frac{1 \text{ m}}{100 \text{ cm}} \)
8Step 8: Conversion factor 8 from centimeters to meters
For each centimeter, there are \(0.01\) meters: \( \frac{100 \text{ cm}}{1 \text{ m}}\)
(e) Meters and centimeters, using 1 and \(0.01\)
9Step 9: Conversion factor 9 from meters to centimeters
For every meter, there are 100 centimeters: \( \frac{1 \text{ m}}{0.01 \text{ cm}} \)
10Step 10: Conversion factor 10 from centimeters to meters
For each centimeter, we have \(0.01\) meters: \( \frac{0.01 \text{ cm}}{1 \text{ m}} \)
Key Concepts
Grams to KilogramsYards to FeetMeters to Centimeters
Grams to Kilograms
When it comes to converting grams to kilograms, knowing the relationship between these two units is essential. Kilograms are the metric unit for measuring mass, commonly used around the world. They are bigger than grams. Therefore, when converting grams to kilograms, we must understand that:
- 1 kilogram is equal to 1000 grams.
- This means for every 1000 grams, you have 1 kilogram.
- The formula for conversion reads: \( \frac{1 \text{ g}}{0.001 \text{ kg}} \)
- This conversion factor makes unit conversion straightforward.
- For reverse conversion, multiply kilograms by 1000 to find the equivalent grams.
Yards to Feet
The conversion between yards and feet is commonly used in the United States, especially in construction and sports fields.
- 1 yard is equal to 3 feet.
- This means for every yard, you have 3 feet.
- If you have a length in yards and want to know it in feet, just apply: \( \frac{1 \text{ yd}}{3 \text{ ft}} \).
- For reverse conversion, divide feet by 3 to get the equivalent yards.
Meters to Centimeters
Meters and centimeters are both metric units of length commonly used worldwide.
- 1 meter is equal to 100 centimeters.
- This means for every meter, there are 100 centimeters.
- Each meter is 100 times larger than a centimeter.
- The formula for conversion is straightforward: \( \frac{1 \text{ m}}{100 \text{ cm}} \).
Other exercises in this chapter
Problem 187
Use a scientific calculator to do the following calculations. Express each answer in scientific notation and to the correct number of significant figures. (a) \
View solution Problem 188
What mass of each substance occupies a volume of \(50.0 \mathrm{~mL} ?\) (Densities are shown in parentheses.) (a) Lead \((11.4 \mathrm{~g} / \mathrm{mL})\) (b)
View solution Problem 190
The recommended tire pressure in a bicycle is 125 pounds \(/ \mathrm{in}^{2}\). What is this tire pressure in atmospheres? \(\left(1 \mathrm{~atm}=14.70\right.\
View solution Problem 191
Do the following calculations and express each answer to the correct number of significant figures. (All values are measurements.) (a) \(\frac{5.03+7.2}{0.003}\
View solution