Problem 189
Question
Acetylene does not react with \(\quad[\mathbf{2 0 0 2}]\) (a) \(\mathrm{Na}\) (b) ammonical \(\mathrm{AgNO}_{3}\) (c) \(\mathrm{HCl}\) (d) \(\mathrm{NaOH}\)
Step-by-Step Solution
Verified Answer
Acetylene does not react with NaOH.
1Step 1: Understand Acetylene's Reactivity
Acetylene (
C_2H_2
) is a hydrocarbon with a triple bond between two carbon atoms. It is known to react with electrophiles due to its ability to donate electrons.
2Step 2: Assess Each Reagent
We need to check which reagents typically react with compounds like acetylene. Sodium (
Na
) might react with acetylene to form sodium acetylide. Ammoniacal
AgNO_3
can react with terminal alkynes like acetylene to form a precipitate.
HCl
can react with acetylene in the presence of a catalyst to form vinyl chloride. Sodium hydroxide (
NaOH
), a base, does not typically react with acetylene.
3Step 3: Identify the Non-reactive Reagent
From the assessments in Step 2, we noted that sodium hydroxide (
NaOH
) does not typically react with acetylene. This is because
NaOH
doesn't provide the conditions needed for a reaction with a hydrocarbon like acetylene.
Key Concepts
Electrophilic reactionSodium acetylide formationTerminal alkyne precipitationHydrocarbon base interaction
Electrophilic reaction
Electrophilic reactions occur when an electron-rich atom or molecule reacts with an electron-deficient atom or group. In the context of acetylene, which is a simple alkyne (
C_2H_2
), the triple bond between the two carbon atoms is rich in electrons. This electron density attracts electrophiles, which are species that seek additional electrons to achieve a more stable state.
Acetylene’s ability to react with electrophiles stems from this strong electron density around its carbon-carbon triple bond.
For example:
Acetylene’s ability to react with electrophiles stems from this strong electron density around its carbon-carbon triple bond.
For example:
- HCl , when catalyzed, can break the triple bond and add to acetylene, forming a new molecule like vinyl chloride.
Sodium acetylide formation
Sodium acetylide is formed when acetylene reacts with sodium (
Na
). This reaction is significant because sodium can donate its electron to form a stable ion,
Na^+
, leaving the acetylene molecule with an extra electron, giving rise to acetylide ions (
C_2H^-
).
This transformation involves the removal of a hydrogen atom from the acetylene, creating an acetylide ion, which is strong and nucleophilic.
In a nutshell, the process looks like: [ C_2H_2 + 2Na ightarrow 2Na^+ + C_2H^- ] The sodium acetylide formed can further participate in various chemical reactions, particularly as a building block in organic synthesis due to its nucleophilic nature.
This transformation involves the removal of a hydrogen atom from the acetylene, creating an acetylide ion, which is strong and nucleophilic.
In a nutshell, the process looks like: [ C_2H_2 + 2Na ightarrow 2Na^+ + C_2H^- ] The sodium acetylide formed can further participate in various chemical reactions, particularly as a building block in organic synthesis due to its nucleophilic nature.
Terminal alkyne precipitation
Terminal alkynes, such as acetylene, have a hydrogen atom bonded to a carbon atom that participates in the carbon-carbon triple bond. This configuration allows them to react with ammoniacal silver nitrate (
AgNO_3
).
The reaction is distinguished by the formation of a precipitate due to the interaction of the terminal hydrogen, carbon carbon triple bond, and the silver ions.
Notably, the reaction can be represented as:
The reaction is distinguished by the formation of a precipitate due to the interaction of the terminal hydrogen, carbon carbon triple bond, and the silver ions.
Notably, the reaction can be represented as:
- Alkyne + AgNO_3 + NH_3 → Alkyne-Ag + NH_4^+/NO_3^−
Hydrocarbon base interaction
Hydrocarbons can interact with various bases, but this interaction heavily depends on the specific type of base and hydrocarbon involved. In the case of sodium hydroxide (
NaOH
), a strong base, acetylene, a hydrocarbon, typically does not react.
The reason for this is that NaOH does not provide the necessary conditions for stimulating a reaction with acetylene. Without a specific pathway or mechanism activated by the hydroxide ion, there is negligible interaction.
Thus, sodium hydroxide remains unreactive towards acetylene, illustrating its selectivity and the importance of choosing the right conditions and reagents when intending to engage hydrocarbons in reactions.
The reason for this is that NaOH does not provide the necessary conditions for stimulating a reaction with acetylene. Without a specific pathway or mechanism activated by the hydroxide ion, there is negligible interaction.
Thus, sodium hydroxide remains unreactive towards acetylene, illustrating its selectivity and the importance of choosing the right conditions and reagents when intending to engage hydrocarbons in reactions.
Other exercises in this chapter
Problem 187
On vigorous oxidation by permanganate solution, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{CHO}\) gives [2002] (a) \(\left(\mathrm{
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On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloroalkane. This alkane could be [2003] (a) propane
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Which one of the following has the minimum boiling point? (a) \(\mathrm{n}\)-butane (b) 1 -butyne (c) 1 -butene (d) iso-butene
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