Problem 189
Question
A liquid in a beaker has temperature \(\theta(t)\) at time \(t\) and \(\theta_{0}\) is temperature of surroundings, then according to Newton's law of cooling the correct graph between \(\log _{e}\left(\theta-\theta_{0}\right)\) and \(t\) is \(\quad\) IAIEEE 2012! (a) (b) (d) (c)
Step-by-Step Solution
Verified Answer
The graph is a straight line with a negative slope.
1Step 1: Understand Newton's Law of Cooling
Newton's Law of Cooling is given by the differential equation \( \frac{d\theta}{dt} = -k(\theta-\theta_{0}) \), where \( \theta \) is the temperature of the object, \( \theta_{0} \) is the ambient temperature, and \( k \) is a positive constant. This describes how the temperature difference \( \theta - \theta_{0} \) changes over time \( t \).
2Step 2: Solve the Differential Equation
Separate variables and integrate: \( \int \frac{1}{\theta-\theta_{0}} \, d\theta = -k \int \, dt \). Upon integrating both sides, we get: \( \ln|\theta-\theta_{0}| = -kt + C \), where \( C \) is the constant of integration.
3Step 3: Express the Log Equation
Rewriting the equation from before, we have: \( \log_{e} |\theta-\theta_{0}| = -kt + C \). This describes a linear relationship between \( \log_{e}(\theta-\theta_{0}) \) and \( t \), where the slope is \(-k\) and the y-intercept is \(C\).
4Step 4: Determine the Graph Type
Since \( \log_{e}(\theta-\theta_{0}) \) against \( t \) forms a straight line with a negative slope, the correct graph should show a linear relationship, sloping downwards.
Key Concepts
Differential EquationsTemperature DecayGraph Interpretation in Physics
Differential Equations
In the world of mathematics and physics, differential equations are fundamental tools used to describe how things change. They involve equations that relate a function to its derivatives. In simpler words, they show how a particular quantity varies with another, often over time.
When dealing with Newton's Law of Cooling, the differential equation is \[\frac{d\theta}{dt} = -k(\theta-\theta_{0})\]Here, \(\theta\) represents the temperature of the object at time \(t\), \(\theta_{0}\) is the temperature of the surroundings, and \(k\) is a constant that varies depending on the material.
When dealing with Newton's Law of Cooling, the differential equation is \[\frac{d\theta}{dt} = -k(\theta-\theta_{0})\]Here, \(\theta\) represents the temperature of the object at time \(t\), \(\theta_{0}\) is the temperature of the surroundings, and \(k\) is a constant that varies depending on the material.
- Separation of Variables: This is a technique often used to solve differential equations. It involves rearranging the equation so that each variable and its derivative or integral term are on opposite sides.
- Integration: Once the equation is separated, integration helps in finding a function that satisfies the original differential equation.
Temperature Decay
Temperature decay refers to the gradual decrease in temperature over time as observed in objects cooling down. According to Newton's Law of Cooling, an object's temperature, \(\theta\), will decrease until it matches the ambient temperature, \(\theta_0\).
This law suggests a predictable pattern:
This law suggests a predictable pattern:
- Exponential Decay: The difference in temperature \(\theta - \theta_0\) decreases exponentially with time. This means that the change is rapid initially but slows down over time.
- Constant Rate: The rate of heat loss is proportional to the temperature difference. The greater the difference, the faster the cooling.
Graph Interpretation in Physics
Graph interpretation is a crucial skill in physics and is all about understanding the story that a graph tells. By analyzing graphs, one can derive significant insights into physical phenomena. In the context of Newton’s Law of Cooling, we interpret the graph of \(\log_{e}(\theta-\theta_0)\) versus time \(t\).
Key points to remember:
Key points to remember:
- Linear Relationship: In this exercise, we establish that \(\log_{e}(\theta-\theta_0)\) against \(t\) forms a straight line, indicating a linear relationship. This suggests that as time increases, the logarithm of the temperature difference decreases.
- Negative Slope: The slope of the line, \(-k\), is negative, representing the decline in temperature difference over time. Higher values of \(k\) mean faster cooling.
- Y-intercept: The constant \(C\) is where the line crosses the y-axis. This value can provide insights into initial conditions, such as the initial temperature difference at time \(t = 0\).
Other exercises in this chapter
Problem 186
A body with area \(A\) at maintained temperature \(T\) and emissivity \(e=0.6\) is kept inside a spherical black body. What will be the maximum energy radiated
View solution Problem 187
In which of the following process, convection does not take place primarily? (a) Sea and land breeze (b) Boiling of water (c) Warming of glass of bulb due to fi
View solution Problem 190
Three very large plates of some area are kept parallel and close to each other. They are considered as ideal black surfaces and have very high thermal conductiv
View solution Problem 192
Assuming the sun to be a spherical body of radius \(R\) at a temperature of \(T \mathrm{~K}\) evaluate the total radiant power incident on the earth at a distan
View solution