Problem 186
Question
How many moles of methyl magnesium iodide in ether will react with a molecule of ethylchloroformate to form a \(3^{\circ}\) alcohol?
Step-by-Step Solution
Verified Answer
1 mole based on 1:1 molar ratio.
1Step 1: Analyze the Reaction
The reaction between a Grignard reagent such as methyl magnesium iodide (CH₃MgI) and ethyl chloroformate (ClCOOC₂H₅) produces a tertiary alcohol. It involves the nucleophilic attack of the carbon of CH₃MgI on the carbonyl carbon of ethyl chloroformate.
2Step 2: Determine the Molar Ratios
The reaction between methyl magnesium iodide and ethyl chloroformate proceeds in a 1:1 molar ratio. This is based on the stoichiometry of the reaction: each molecule of ethyl chloroformate reacts with one molecule of methyl magnesium iodide to form the alcohol.
3Step 3: Calculate the Number of Moles Required
Given that the reaction is in a 1:1 molar ratio, 1 mole of ethyl chloroformate will require 1 mole of methyl magnesium iodide to complete the reaction and form the tertiary alcohol.
Key Concepts
Methyl Magnesium IodideEthyl Chloroformate ReactionTertiary Alcohol Formation
Methyl Magnesium Iodide
Methyl magnesium iodide is a type of Grignard reagent useful in organic synthesis. Grignard reagents are named after their inventor, Victor Grignard, who was honored with a Nobel Prize for this discovery.
The production of methyl magnesium iodide is sensitive to moisture and should be conducted under anhydrous (without water) conditions to prevent the reagent from reacting with water instead of the intended compound.
- Grignard reagents are made by reacting magnesium metal with alkyl or aryl halides in an ether solvent, such as diethyl ether. This particular reagent, methyl magnesium iodide, is made from methyl iodide and magnesium.
- The structure of methyl magnesium iodide includes a highly reactive magnesium-carbon bond, which characterizes it as a strong nucleophile.
The production of methyl magnesium iodide is sensitive to moisture and should be conducted under anhydrous (without water) conditions to prevent the reagent from reacting with water instead of the intended compound.
Ethyl Chloroformate Reaction
Ethyl chloroformate is an important compound in organic chemistry, often used as a reagent to introduce protective groups or as a building block for larger molecules. This compound consists of a carbonyl group flanked by a chlorine atom and an ethoxy group.
In the context of reactions with Grignard reagents, ethyl chloroformate serves as an electrophile that can be attacked by a nucleophile.
In the context of reactions with Grignard reagents, ethyl chloroformate serves as an electrophile that can be attacked by a nucleophile.
- When exposed to methyl magnesium iodide, the carbonyl carbon of ethyl chloroformate is susceptible to nucleophilic attack. This creates a short-lived intermediate where the new carbon-carbon bond forms.
- The chlorine in ethyl chloroformate acts as a good leaving group, substituting the Grignard reagent into the compound effectively.
Tertiary Alcohol Formation
The formation of tertiary alcohols is one of the major applications of reactions involving Grignard reagents and certain electrophiles, such as ethyl chloroformate. In this reaction, the methyl group from the methyl magnesium iodide bonds with the electrophilic center of ethyl chloroformate.
- This process results in an intermediate compound that, upon hydrolysis, yields a tertiary alcohol.
- The particular reaction between methyl magnesium iodide and ethyl chloroformate follows a 1:1 molar ratio, meaning for every mole of ethyl chloroformate, a mole of methyl magnesium iodide is required to produce a tertiary alcohol.
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