Problem 184
Question
A black body has maximum wavelength \(\lambda_{m}\) at \(2000 \mathrm{~K}\). Its corresponding wavelength at \(3000 \mathrm{~K}\) will be \(\quad\) [Kerala CET 2005] (a) \(\frac{3}{2} \lambda_{m}\) (b) \(\frac{2}{3} \lambda_{m}\) (c) \(\frac{16}{81} \lambda_{m}\) (d) \(\frac{81}{16} \lambda_{m}\)
Step-by-Step Solution
Verified Answer
The maximum wavelength at 3000 K is \( \frac{2}{3} \lambda_{m} \) (option b).
1Step 1: Understanding Wien's Displacement Law
Wien's displacement law states that the wavelength at which the emission of a black body spectrum is maximized is inversely proportional to the temperature of the body. Mathematically, it is expressed as \( \lambda_{m} = \frac{b}{T} \), where \( b \) is Wien's constant.
2Step 2: Applying Wien's Displacement Law for Both Temperatures
We have two temperatures: 2000 K and 3000 K. From Wien's law, \( \lambda_{m} \propto \frac{1}{T} \). Thus, for two different temperatures, \( \frac{\lambda_{m_1}}{\lambda_{m_2}} = \frac{T_2}{T_1} \).
3Step 3: Substituting the Given Values
Let \( \lambda_{1} \) be the maximum wavelength at 2000 K and \( \lambda_{2} \) be at 3000 K. Using the proportion, \( \frac{\lambda_{1}}{\lambda_{2}} = \frac{3000}{2000} = \frac{3}{2} \).
4Step 4: Solving for the New Wavelength
Rearrange the equation to find \( \lambda_{2} \): \( \lambda_{2} = \frac{2}{3} \lambda_{1} \). Thus, the maximum wavelength at the new temperature 3000 K is \( \frac{2}{3} \lambda_{m} \).
Key Concepts
Black Body RadiationMaximum WavelengthThermal Physics
Black Body Radiation
Black body radiation is an important concept in physics, especially thermal physics. Imagine an ideal "perfect" black body: it absorbs all incident light, regardless of wavelength or angle.
When this black body is heated, it emits radiation that corresponds to its temperature. This emitted radiation covers a wide spectrum of wavelengths, yet not all wavelengths are emitted equally.
- As the temperature of the black body increases, the emitted radiation becomes more intense.
- The distribution of the emitted wavelengths shifts, concentrating more intensity towards shorter wavelengths.
Maximum Wavelength
The maximum wavelength, in the context of black body radiation, refers to the specific wavelength at which the emission of radiation is strongest. Wien's Displacement Law gives us the mathematical relationship to understand this. It states that the maximum wavelength \(\lambda_m\) is inversely proportional to the absolute temperature \(T\) of the black body. This relationship can be expressed with the equation \( \lambda_{m} = \frac{b}{T} \), where \(b\) is Wien's constant.
- When the temperature increases, the maximum wavelength decreases, indicating a shift towards shorter wavelengths such as blue light.
- This shifting of maximum wavelength is why hot objects, like stars, glow differently depending on their temperature.
Thermal Physics
Thermal physics is a branch of physics that deals with heat, temperature, and the energetic properties of systems. It encompasses concepts like thermodynamics, statistical mechanics, and black body radiation.
In the realm of thermal physics, understanding radiation phenomena is crucial. Black body radiation exemplifies how objects transfer energy in the form of electromagnetic waves as a function of their temperature.
- Thermal physics helps explain how energy is distributed in a system and how this affects observable quantities like temperature and pressure.
- It provides insights into the behavior of gases, liquids, and solids at different temperatures.
Other exercises in this chapter
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