Problem 182
Question
An article in Chemosphere ["Statistical Evaluations Reflecting the Skewness in
the Distribution of TCDD Levels in Human Adipose Tissue" \((1987,\) Vol.
\(16(8),\) pp. \(2135-\)
2140) ] concluded that the levels of 2,3,7,8 -TCDD (colorless persistent
environmental contaminants with no distinguishable odor at room temperature)
in human adipose tissue has a lognormal distribution (based on empirical
evidence from North America). The mean and variance of this lognormal
distribution in the USA are 8 and \(21,\) respectively. Let \(X\) denote this
lognormal random variable. Determine the following:
(a) \(P(2000
Step-by-Step Solution
Verified Answer
(a) Use calculated \(\mu_Y\) and \(\sigma_Y^2\) to find \(P(2000
1Step 1: Understand the Lognormal Distribution
For a lognormal distribution, if a random variable \( X \) is lognormally distributed, then \( Y = \log(X) \) follows a normal distribution. Given the mean \( \mu \) and variance \( \sigma^2 \) of \( X \), we must first determine the parameters \( \mu_Y \) and \( \sigma_Y^2 \) of the corresponding normal distribution \( Y \).
2Step 2: Calculate Parameters for the Normal Distribution
For a lognormal distribution characterized by the mean \( m \) and variance \( v \) of \( X \), the mean \( \mu_Y \) and variance \( \sigma_Y^2 \) of \( Y \) are given by \( \mu_Y = \log\left(\frac{m^2}{\sqrt{m^2 + v}}\right) \) and \( \sigma_Y^2 = \log\left(1 + \frac{v}{m^2}\right) \). Substituting \( m = 8 \) and \( v = 21 \), we calculate: \( \mu_Y = \log\left(\frac{8^2}{\sqrt{8^2 + 21}}\right) \) and \( \sigma_Y^2 = \log\left(1 + \frac{21}{8^2}\right) \).
3Step 3: Solve for Part (a) - P(2000 < X < 2500)
Knowing \( Y = \log(X) \) follows \( N(\mu_Y, \sigma_Y^2) \), to find \( P(2000 < X < 2500) \), find \( P(\log(2000) < Y < \log(2500)) \). Standardize \( Y \) to calculate the probabilities using the normal distribution table or a calculator with the calculated \( \mu_Y \) and \( \sigma_Y^2 \).
4Step 4: Solve for Part (b) - Value exceeded with Probability 10%
To determine the value exceeded with probability 10%, find the 90th percentile of the lognormal distribution. This requires determining \( z_{0.9} \) from the standard normal distribution, and then calculating \( x = e^{\mu_Y + z_{0.9}\cdot\sigma_Y} \).
5Step 5: Solve for Part (c) - Mean and Variance of X
The mean of a lognormal distribution is given by \( E[X] = e^{\mu_Y + \sigma_Y^2/2} \). The variance is given by \( \text{Var}[X] = (e^{\sigma_Y^2} - 1) e^{2\mu_Y + \sigma_Y^2} \). Use the calculated \( \mu_Y \) and \( \sigma_Y^2 \) to determine the mean and variance.
Key Concepts
Probability CalculationStatistical ParametersRandom VariablesNormal Distribution
Probability Calculation
Calculating probabilities for lognormal distributions involves a few important steps. The lognormal distribution is unique because it represents data whose logarithms are normally distributed. To calculate the probability of a random variable falling within a specific range, we transform it to the normal distribution context.
For example, to determine the probability that a random variable, denoted as \( X \), falls between 2000 and 2500 (\( P(2000 < X < 2500) \)), we first take the natural log of these values. This transforms the bounds into a range applicable for a normal distribution.
For example, to determine the probability that a random variable, denoted as \( X \), falls between 2000 and 2500 (\( P(2000 < X < 2500) \)), we first take the natural log of these values. This transforms the bounds into a range applicable for a normal distribution.
- Transform the bounds: \( Y = \log(X) \)
- Calculate \( \log(2000) \) and \( \log(2500) \)
- Use the parameters of the normal distribution and standardize \( Y \)
Statistical Parameters
In the context of lognormal distributions, understanding the statistical parameters is crucial. These parameters include the mean and variance of the distribution, but for lognormal distributions, they correlate to a transformed normal distribution.
The parameters \( \mu_Y \) and \( \sigma_Y^2 \) for the associated normal distribution are calculated using:
The parameters \( \mu_Y \) and \( \sigma_Y^2 \) for the associated normal distribution are calculated using:
- Mean: \( \mu_Y = \log\left( \frac{m^2}{\sqrt{m^2 + v}} \right) \)
- Variance: \( \sigma_Y^2 = \log\left( 1 + \frac{v}{m^2} \right) \)
Random Variables
The concept of random variables is fundamental in probability and statistics. A random variable represents a function that assigns outcomes from a random phenomenon to numerical values. Here, \( X \) represents a lognormal random variable indicating TCDD levels in human adipose tissue.
Since \( Y = \log(X) \) follows a normal distribution when \( X \) is lognormally distributed, it helps us understand the nature and behavior of \( X \). Therefore:
Since \( Y = \log(X) \) follows a normal distribution when \( X \) is lognormally distributed, it helps us understand the nature and behavior of \( X \). Therefore:
- \( X \) represents the original set of data or variables measured
- \( Y = \log(X) \) transforms \( X \) into a form that simplifies analysis
Normal Distribution
The normal distribution is a cornerstone in statistics and plays a key role in analyzing lognormal distributions. This is because when a variable is lognormally distributed, its logarithm is normally distributed.
A normal distribution has a bell-shaped curve, characterized by two parameters: mean (\( \mu \)) and variance (\( \sigma^2 \)). Each point on this curve represents a possible outcome of the variable, with the curve's shape depicting the likelihood of each.
A normal distribution has a bell-shaped curve, characterized by two parameters: mean (\( \mu \)) and variance (\( \sigma^2 \)). Each point on this curve represents a possible outcome of the variable, with the curve's shape depicting the likelihood of each.
- Transform lognormal to normal: \( Y = \log(X) \)
- Mean becomes \( \mu_Y \)
- Variance becomes \( \sigma_Y^2 \)
Other exercises in this chapter
Problem 180
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Suppose that \(x\) has a beta distribution with parameters \(\alpha=2.5\) and \(\beta=1 .\) Determine the following: (a) \(P(X
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