Problem 180
Question
The roots of the equation \((2+z)^{6}+(2-z)^{6}=0\) are (A) \(\pm 2 i \tan \pi / 12\) (B) \(\pm 2 i \tan 5 \pi^{\prime} 12\) (C) \(\pm 2 i\) (D) \(\pm 2\)
Step-by-Step Solution
Verified Answer
The roots are \(\pm 2i \tan(\frac{\pi}{12})\) from option (A).
1Step 1: Recognize the Trigonometric Identity
Recognize that the expression \((2+z)^6 + (2-z)^6 = 0\) is symmetrical and can be expanded using the identity for sum of sixth powers, particularly using trigonometric expressions involving cosine and sine.
2Step 2: Set the Rational Expression
Set \(u = 2 + z\) and \(v = 2 - z\), noting that the sum of sixth powers, \(u^6 + v^6 = 0\), means that one is the negative of the other.
3Step 3: Use Polar Coordinates and Symmetry
Write each term in polar form. In polar form, using identities, \((2+z)^6\) and \((2-z)^6\) symmetrically reflect around the imaginary axis. Recognize that their symmetry implies these complexes annihilate each other.
4Step 4: Simplify Using Complex Roots
Recognizing that sum leads to zero, implies roots lie on purely imaginary line. Utilize Euler's formula and polynomial properties on symmetry; \(z\) can be found as only imaginary entries solving \((2+z)^{6} = -(2-z)^{6}\).
5Step 5: Solve Using Trigonometric Identities
Apply identities from step 3, letting \(z = 2i \tan(\theta)\), simplifying to \(\tan(2\theta)\) roots for known values at principal angles gives roots as \(\tan(\frac{\pi}{12})\) and equivalently for \(\tan(\frac{5\pi}{12})\).
6Step 6: Verify Roots
Verify the solution. For each potential "angle," calculate the trigonometric output, and ensure it satisfies the setup equation \((2 + z)^6 + (2 - z)^6 = 0\) algebraically.
Key Concepts
Trigonometric IdentitiesSymmetry in Complex NumbersPolar CoordinatesComplex Roots Analysis
Trigonometric Identities
Trigonometric identities play a vital role in simplifying complex equations. For the equation \((2+z)^{6}+(2-z)^{6}=0\), recognizing the symmetry in the expression is crucial. This involves using identities that connect powers and angles, such as the sum of sixth powers. These identities allow us to replace complex trigonometric expressions with simpler values involving sine and cosine. This simplification is especially helpful when dealing with complex roots.
- The identity is especially powerful when expressions appear identical but with different variable signs, such as \((2+z)\) and \((2-z)\).
- These expressions can be expanded or simplified using known trigonometric properties, like cosine or sine rules.
Symmetry in Complex Numbers
Complex numbers often exhibit symmetry, which is a useful property in simplifying equations. For the given problem, recognizing that \((2+z)^6 + (2-z)^6=0\) has symmetry can guide us to an elegant solution. Symmetry in complex numbers usually implies that parts of an equation can reflect or cancel each other out.
- In this case, the parts \((2+z)^6\) and \((2-z)^6\) reflect around the imaginary axis.
- This reflection hints that these terms can potentially cancel out, leading to their annihilation.
Polar Coordinates
Utilizing polar coordinates is a powerful technique in analyzing complex numbers, especially when it involves roots. Each complex number can be represented in polar form, which expresses a number in terms of its modulus and angle. For \((2+z)\) and \((2-z)\), writing these expressions in polar coordinates makes it easier to perceive the symmetry and reflectivity around the imaginary axis.
- Polar coordinates enable us to use Euler's formula effectively, relating complex numbers to exponential forms.
- This approach simplifies calculations and visualizes the rotation and angular displacement involved.
Complex Roots Analysis
Analyzing complex roots involves multiple steps and techniques, including the understanding of symmetry, trigonometric identities, and polar form transformations. Once recognizing the expression's symmetry in \((2+z)^6+(2-z)^6=0\), the task becomes finding roots that satisfy this condition. Trigonometric identities hint at potential angles, such as \(\frac{\pi}{12}\) and its supplementary forms, which lead to the complex roots.
- Using properties of trigonometric functions helps determine angles like \(\tan(\theta)\) involved in finding the roots.
- Finding angles where these tangent values hold true gives the imaginary components of the roots.
Other exercises in this chapter
Problem 177
If \(1, \omega, \omega^{2}, \ldots, \omega^{n-1}\) are the \(n, n\)th roots of unity, then \((1-\omega)(1-\omega)^{2} \ldots\left(1-\omega^{n-1}\right)\) is equ
View solution Problem 179
The roots of the equation \(z^{4}+4 z^{2}+16=0\) are (A) \(\pm 1+i \sqrt{3}\) (B) \(\pm 1-i \sqrt{3}\) (C) \(\pm 2+2 \sqrt{3} i\) (D) \(\pm 2-2 \sqrt{3} i\)
View solution Problem 181
The roots of the equation \(z^{4}-z^{3}+z^{2}-z+1=0\) are \(\cos \left(\frac{p \pi}{5}\right)+i \sin \left(\frac{p \pi}{5}\right)\) where \(p=\) (A) \(1,3,5,7,9
View solution Problem 182
\hline Column-I \begin{tabular}{l} Column-II \\ \hline (A) \(i-1\) \end{tabular} (I) If \(z_{r}=\cos \left(\frac{\pi}{3^{r}}\right)+i \sin \left(\frac{\pi}{3^{r
View solution