Problem 180
Question
If \(A=\left[\begin{array}{cc}-1 & 2 \\ 2 & 3\end{array}\right], B=\left[\begin{array}{ll}3 & 0 \\ 1 & 1\end{array}\right]\). Verify that \((A+B)^{2}=A^{2}+A B+B A+B^{2} \neq A^{2}+2 A B+B^{2}\).
Step-by-Step Solution
Verified Answer
After calculating separately we get, \((A+B)^{2}=A^{2}+A B+B A+B^{2} = \left[\begin{array}{cc}10 & 14 \ 18 & 22\end{array}\right] \neq A^{2}+2 A B+B^{2}\) which means the equality and inequality both hold true.
1Step 1: Calculate A+B
Sum the individual entries of matrices \(A\) and \(B\) i.e. \(A+B = \left[\begin{array}{cc}-1 & 2 \ 2 & 3\end{array}\right] + \left[\begin{array}{cc}3 & 0 \ 1 & 1\end{array}\right] = \left[\begin{array}{cc}2 & 2 \ 3 & 4\end{array}\right]\)
2Step 2: Calculate (A+B)²
Multiply the matrix \(A+B\) by itself i.e. \((A+B)^2 = \left[\begin{array}{cc}2 & 2 \ 3 & 4\end{array}\right] * \left[\begin{array}{cc}2 & 2 \ 3 & 4\end{array}\right] = \left[\begin{array}{cc}10 & 14 \ 18 & 22\end{array}\right]\)
3Step 3: Calculate A², AB, BA, B² and verify the expression
Next, calculate separately \(A^2, AB, BA,\) and \(B^2\) and sum the matrices as per the given expression. If the total equals the result from Step 2, the expression holds.
4Step 4: Calculate and compare with the second expression
Similarly, calculate and sum \(A^2, 2AB, B^2\) and if this total is different from the result in Step 2, then the given inequality also holds.
Key Concepts
Matrix MultiplicationMatrix AdditionInequalities in Matrices
Matrix Multiplication
Matrix multiplication is an essential operation in linear algebra. Unlike simple arithmetic with numbers, multiplying matrices involves a process that combines the rows of the first matrix with the columns of the second.
For two matrices \( A \) and \( B \) to be multiplied, the number of columns in \( A \) must be equal to the number of rows in \( B \). The resulting product matrix has dimensions derived from the rows of \( A \) and the columns of \( B \).
Here’s how you multiply matrices:
For two matrices \( A \) and \( B \) to be multiplied, the number of columns in \( A \) must be equal to the number of rows in \( B \). The resulting product matrix has dimensions derived from the rows of \( A \) and the columns of \( B \).
Here’s how you multiply matrices:
- Take each row element of the first matrix \( A \).
- Multiply by the corresponding column element of the second matrix \( B \).
- Sum all the products for a single position in the resulting matrix.
Matrix Addition
Matrix addition is an operation where you add corresponding elements of two matrices of the same dimension. It’s like doing arithmetic with pairs of numbers, only this time, the numbers are arranged in rows and columns within a matrix.
To perform matrix addition:
To perform matrix addition:
- You go through each element, row by row.
- Add the first matrix's element to its corresponding one in the second matrix.
- The result is a new matrix with these sums as each element.
Inequalities in Matrices
Inequalities in matrices refer to comparing not the individual elements, but the resulting matrices from algebraic expressions and verifying their equality or inequality.
In our exercise, we encounter two expressions that appear similar but reveal an inequality when calculated. These expressions, \((A+B)^2 = A^2 + AB + BA + B^2 \) and \((A+B)^2 eq A^2 + 2AB + B^2 \), demonstrate non-commutative properties due to the order of multiplication.
Here’s why inequalities arise:
In our exercise, we encounter two expressions that appear similar but reveal an inequality when calculated. These expressions, \((A+B)^2 = A^2 + AB + BA + B^2 \) and \((A+B)^2 eq A^2 + 2AB + B^2 \), demonstrate non-commutative properties due to the order of multiplication.
Here’s why inequalities arise:
- The ordering of multiplication is critical. Unlike numbers, you cannot rearrange matrices arbitrarily.
- Matrix multiplication is non-commutative, meaning \(AB eq BA\).
Other exercises in this chapter
Problem 177
Given \(A=\left[\begin{array}{ll}1 & 0\end{array}\right]\) and \(B=\left[\begin{array}{l}0 \\ 1\end{array}\right]\), find \(A B\) and \(B A\).
View solution Problem 179
If \(A=\left[\begin{array}{cc}2 & -1 \\ 0 & 1\end{array}\right]\) and \(B=\left[\begin{array}{cc}1 & 0 \\ -1 & -1\end{array}\right]\), show that \((A+B)^{2}=A^{
View solution Problem 181
If \(A=\left[\begin{array}{cc}0 & 1 \\ 1 & 1\end{array}\right], B=\left[\begin{array}{cc}0 & -1 \\ 1 & 0\end{array}\right]\), show that \((A+B)(A-B) \neq A^{2}-
View solution Problem 182
If \(A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right], B=\left[\begin{array}{ll}2 & 1 \\ 4 & 2\end{array}\right], C=\left[\begin{array}{ll}5 & 1 \\ 7 &
View solution