Problem 18
Question
Which of the following compounds or ions has the strongest conjugate acid? Briefly explain your choice. (a) \(\mathrm{CN}^{-}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{SO}_{4}^{2-}\)
Step-by-Step Solution
Verified Answer
\(\mathrm{HSO}_{4}^{-}\) has the strongest conjugate acid.
1Step 1: Identify Conjugate Acids
The conjugate acid of a base is formed by adding a proton (H\(^+\)) to the base. Let's identify the conjugate acids:(a) \/ \(\mathrm{CN}^{-}\) becomes \(\mathrm{HCN}\) when it gains a proton.(b) \/ \(\mathrm{NH}_{3}\) becomes \(\mathrm{NH}_{4}^{+}\) when it gains a proton.(c) \/ \(\mathrm{SO}_{4}^{2-}\) becomes \(\mathrm{HSO}_{4}^{-}\) when it gains a proton.
2Step 2: Analyze the Strength of Conjugate Acids
The strength of a conjugate acid is inversely related to the strength of its conjugate base. A weaker base forms a stronger conjugate acid.(a) \/ \(\mathrm{CN}^{-}\) is a relatively strong base, so \(\mathrm{HCN}\) is a weak acid.(b) \/ \(\mathrm{NH}_{3}\) is a weak base, so \(\mathrm{NH}_{4}^{+}\) is a relatively strong acid.(c) \/ \(\mathrm{SO}_{4}^{2-}\) is a very weak base, so \(\mathrm{HSO}_{4}^{-}\) is a strong acid.
3Step 3: Compare and Conclude
Compare the strengths of the conjugate acids formed to determine which is the strongest.Among \(\mathrm{HCN}\), \(\mathrm{NH}_{4}^{+}\), and \(\mathrm{HSO}_{4}^{-}\), \(\mathrm{HSO}_{4}^{-}\) is recognized as the strongest conjugate acid due to \(\mathrm{SO}_{4}^{2-}\) being the weakest base.
Key Concepts
Conjugate AcidsStrength of AcidsConjugate Base-Strength Relationship
Conjugate Acids
In acid-base chemistry, a conjugate acid is formed when a base gains a proton (H\(^+\)). This process is like a handoff during a relay race, where the proton is passed from the acid to the base. Understanding conjugate acids is crucial because it helps predict how substances will behave in different chemical reactions.
To illustrate, let's consider the examples from our original exercise:
To illustrate, let's consider the examples from our original exercise:
- The ion \(\mathrm{CN}^{-}\) becomes the conjugate acid \(\mathrm{HCN}\) by gaining a proton.
- Ammonia \(\mathrm{NH}_{3}\) gains a proton to form ammonium \(\mathrm{NH}_{4}^{+}\).
- Sulfate \(\mathrm{SO}_{4}^{2-}\) turns into hydrogen sulfate \(\mathrm{HSO}_{4}^{-}\).
Strength of Acids
Acid strength refers to an acid's ability to donate a proton, which is a fundamental aspect of acid-base chemistry. A stronger acid releases more protons into a solution. Thus, it affects the acidity of a solution significantly. The strength of an acid is often depicted through its dissociation in water, where it splits into ions.
Based on the examples:
Based on the examples:
- \(\mathrm{HCN}\) is a weaker acid because \(\mathrm{CN}^{-}\) holds onto protons tightly, releasing less in solutions.
- \(\mathrm{NH}_{4}^{+}\) is stronger compared to \(\mathrm{HCN}\), as it's more willing to donate protons.
- \(\mathrm{HSO}_{4}^{-}\), being the strongest among the given examples, dissociates more readily, increasing its effectiveness in lowering pH.
Conjugate Base-Strength Relationship
In acid-base equilibria, the relationship between conjugate acids and bases is like a seesaw. Their strengths balance each other with one being strong if the other is weak. This seesaw relationship plays a critical role in predicting reactions and understanding chemical stability.
For the compounds in the exercise:
For the compounds in the exercise:
- \(\mathrm{CN}^{-}\) is a strong base, resulting in a weaker conjugate acid \(\mathrm{HCN}\).
- \(\mathrm{NH}_{3}\) is a weak base, producing a stronger conjugate acid \(\mathrm{NH}_{4}^{+}\).
- \(\mathrm{SO}_{4}^{2-}\) is very weak as a base, so its conjugate acid \(\mathrm{HSO}_{4}^{-}\) is quite strong.
Other exercises in this chapter
Problem 16
Several acids are listed here with their respective equilibrium constants. $$\begin{array}{c} \mathrm{HF}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightlef
View solution Problem 17
State which of the following ions or compounds has the strongest conjugate base and briefly explain your choice. (a) \(\mathrm{HSO}_{4}^{-}\) (b) \(\mathrm{CH}_
View solution Problem 19
Dissolving \(\mathrm{K}_{2} \mathrm{CO}_{3}\) in water gives a basic solution. Write a balanced equation showing how the carbonate ion is responsible for this e
View solution Problem 20
Dissolving ammonium bromide in water gives an acidic solution. Write a balanced equation showing how this reaction can occur.
View solution