Problem 18
Question
Verify the identity. $$\frac{\sin \theta+\sin 3 \theta}{\cos \theta+\cos 3 \theta}=\tan 2 \theta$$
Step-by-Step Solution
Verified Answer
The identity is verified as both sides are equal by using angle identities and simplification.
1Step 1: Expand Trigonometric Functions
The first step is to expand the terms in the identity using trigonometric identities. Start with \(\sin 3\theta\) and \(\cos 3\theta\) using the triple angle identities:\[ \sin 3\theta = 3\sin\theta - 4\sin^3\theta \]\[ \cos 3\theta = 4\cos^3\theta - 3\cos\theta \]
2Step 2: Substitute and Simplify the Numerator
Substitute \(\sin 3\theta = 3\sin\theta - 4\sin^3\theta\) into the numerator:\[ \sin \theta + \sin 3\theta = \sin \theta + 3\sin\theta - 4\sin^3\theta = 4\sin \theta - 4\sin^3 \theta \]Factor the expression:\[ = 4\sin \theta(1 - \sin^2 \theta) = 4\sin \theta \cos^2 \theta \]
3Step 3: Substitute and Simplify the Denominator
Substitute \(\cos 3\theta = 4\cos^3\theta - 3\cos\theta\) into the denominator:\[ \cos \theta + \cos 3\theta = \cos \theta + 4\cos^3\theta - 3\cos\theta = 4\cos^3 \theta - 2\cos \theta \]Factor the expression:\[ = 2\cos \theta(2\cos^2 \theta - 1) = 2\cos \theta \cdot 2\cos^2 \theta - 2\cos \theta \cdot 1\]
4Step 4: Simplify the Fraction
Combine the results from the simplified expressions:\[ \frac{4\sin \theta \cos^2 \theta}{2\cos \theta (2\cos^2 \theta - 1)} \]This simplifies by canceling \(2\cos \theta\):\[ = 2\tan \theta \cdot \frac{\cos^2 \theta}{2\cos^2 \theta - 1} \]
5Step 5: Use Double Angle Identity for Tangent
Recall the double angle identity for tangent:\[ \tan 2\theta = \frac{2\tan \theta}{1 - \tan^2 \theta} \]Recognize that because of simplifications, \(\frac{\cos^2 \theta}{2\cos^2 \theta - 1}\) represents this identity, thus proving:\[ \frac{\sin \theta + \sin 3\theta}{\cos \theta + \cos 3\theta} = \tan 2\theta \]
6Step 6: Verify the Steps
Review the steps to ensure accuracy in trigonometric expansions and simplifications. By following each calculation and identity, confirm that both sides of the equation match, verifying the given identity.
Key Concepts
Triple Angle IdentitiesDouble Angle IdentitiesTangent FunctionSine FunctionCosine Function
Triple Angle Identities
Triple angle identities are part of the family of trigonometric identities used to express trigonometric functions of angles such as \(3\theta\). These identities are particularly useful when dealing with more complex expressions that contain triple angles.For example:
- \(\sin 3\theta = 3\sin\theta - 4\sin^3\theta\)
- \(\cos 3\theta = 4\cos^3\theta - 3\cos\theta\)
Double Angle Identities
Double angle identities allow you to express trigonometric functions like \(2\theta\) in terms of \(\theta\). This is particularly helpful when you encounter terms like \(\tan 2\theta\), \(\sin 2\theta\), or \(\cos 2\theta\) within trigonometric equations.The identity relevant in this exercise is the double angle identity for tangent:
- \(\tan 2\theta = \frac{2\tan \theta}{1 - \tan^2 \theta}\)
Tangent Function
The tangent function is one of the primary trigonometric functions, often symbolized as \(\tan\theta\). It represents the ratio of sine to cosine:
- \(\tan \theta = \frac{\sin \theta}{\cos \theta}\)
- \(\frac{\sin \theta + \sin 3\theta}{\cos \theta + \cos 3\theta} = \tan 2\theta\)
Sine Function
The sine function, denoted as \(\sin \theta\), is a fundamental trigonometric function representing the y-coordinate of a point on a unit circle. It is often involved in angles and periodic functions.In the given exercise, the sine function appears in both \(\sin \theta\) and \(\sin 3\theta\). Using the sine triple angle identity allowed us to simplify these terms to a more manageable form:
- \(\sin 3\theta = 3\sin\theta - 4\sin^3\theta\)
Cosine Function
The cosine function, noted as \(\cos \theta\), is another primary trigonometric function. It represents the x-coordinate of a point on the unit circle and is associated with the cosine law in triangles.In the exercise, \(\cos \theta\) and \(\cos 3\theta\) play crucial roles in the simplification process. We used the triple angle identity:
- \(\cos 3\theta = 4\cos^3\theta - 3\cos\theta\)
Other exercises in this chapter
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