Problem 18
Question
Velocity \(v\) is given by \(v=u+a t\). If \(u=9.86 \mathrm{~m} / \mathrm{s}, a=4.25 \mathrm{~m} / \mathrm{s}^{2}\) and \(t=6.84 \mathrm{~s}\), find \(v\), correct to 3 significant figures.
Step-by-Step Solution
Verified Answer
The velocity \( v \) is \( 38.9 \, \text{m/s} \).
1Step 1: Understand the Equation
The equation given is the formula for velocity in uniform acceleration motion: \( v = u + a t \). This shows the final velocity \( v \) as a combination of the initial velocity \( u \), the acceleration \( a \), and the time \( t \).
2Step 2: Identify Known Values
We're provided with the initial velocity \( u = 9.86 \, \text{m/s} \), acceleration \( a = 4.25 \, \text{m/s}^2 \), and time \( t = 6.84 \, \text{s} \). These values will be substituted into the equation to find \( v \).
3Step 3: Substitute and Calculate
Substitute the known values into the equation: \( v = 9.86 + 4.25 \times 6.84 \). First, calculate \( 4.25 \times 6.84 \) which equals \( 29.07 \). Then add this to \( 9.86 \) to find \( v = 38.93 \).
4Step 4: Round to Significant Figures
The problem requires rounding the result to 3 significant figures. \( 38.93 \) rounded to 3 significant figures is \( 38.9 \).
Key Concepts
Uniform AccelerationInitial VelocityAccelerationSignificant Figures
Uniform Acceleration
Uniform acceleration refers to a constant rate of change of velocity over time. This concept is central in physics, especially when analyzing motion. In situations where acceleration is uniform, the velocity of an object changes by the same amount each second.
This makes the motion predictable, allowing us to use equations like the one in the exercise:
Understanding uniform acceleration helps in solving motion problems efficiently, as you can calculate any of the variables if the others are known.
This makes the motion predictable, allowing us to use equations like the one in the exercise:
- \( v = u + a t \), where
Understanding uniform acceleration helps in solving motion problems efficiently, as you can calculate any of the variables if the others are known.
Initial Velocity
Initial velocity, often symbolized as \( u \) in equations, is the velocity of an object at the start of an observation. This value is crucial because it forms the baseline from which changes in velocity are measured.
- In our exercise, the initial velocity is given as \( u = 9.86 \, \text{m/s} \).
- It is used in the velocity equation to determine how much the object speeds up over time.
Acceleration
Acceleration is the rate at which an object changes its velocity. It is often represented by the letter \( a \) and expressed in \( \text{m/s}^2 \). Acceleration can be positive, meaning an increase in speed, or negative, indicating deceleration.
In uniform motion problems, the constant acceleration simplifies calculations, as seen in the example equation \( v = u + a t \). Here, the acceleration \( a \) is a constant value needed to calculate the change in velocity over a specific time.
In uniform motion problems, the constant acceleration simplifies calculations, as seen in the example equation \( v = u + a t \). Here, the acceleration \( a \) is a constant value needed to calculate the change in velocity over a specific time.
- In our worked example, \( a = 4.25 \, \text{m/s}^2 \).
Significant Figures
Significant figures are the digits in a number that contribute to its precision. These figures include all non-zero digits, any zeros between significant digits, and any trailing zeros in the decimal part.
- When performing calculations, it's vital to follow significant figure rules to ensure precision is maintained and conveyed accurately.
- In the exercise, the final result was rounded to three significant figures to match the precision required.
Other exercises in this chapter
Problem 16
In an electrical circuit the voltage \(V\) is given by Ohm's law, i.e. \(V=I R\). Find, correct to 4 significant figures, the voltage when \(I=5.36 \mathrm{~A}\
View solution Problem 17
The surface area \(A\) of a hollow cone is given by \(A=\pi r l\). Determine, correct to 1 decimal place, the surface area when \(r=3.0 \mathrm{~cm}\) and \(l=8
View solution Problem 19
The area, \(A\), of a circle is given by \(A=\pi r^{2}\). Determine the area correct to 2 decimal places, given radius \(r=5.23 \mathrm{~m}\)
View solution Problem 20
The power \(P\) watts dissipated in an electrical circuit may be expressed by the formula \(P=\frac{V^{2}}{R}\). Evaluate the power, correct to 3 significant fi
View solution