Problem 18
Question
Use a graphing utility to graph the equation and approximate any \(x\) - and \(y\) -intercepts. Verify your results algebraically. $$y=4(x+3)-2$$
Step-by-Step Solution
Verified Answer
The y-intercept is (0,10) and the x-intercept is approximately (-2.5, 0), confirmed by both graphical and algebraic means.
1Step 1: Plot the Line Using a Graphing Utility
To plot this function, we need to understand the form \(y=mx+b\), where \(m\) is the slope and \(b\) is the y-intercept. For our equation, \(y=4(x+3)-2\), which can also be written as \(y=4x+12-2\) or \(y=4x+10\), the slope \(m\) is \(4\) and the y-intercept \(b\) is \(10\). This means the line begins at the point (0,10) on the y-axis and rises by 4 units for each unit move to the right on the x-axis. Plug in these values into the graphing utility to generate the line.
2Step 2: Approximate the x and y Intercepts
The y-intercept is the point (0,10), where the line crosses the y-axis. From the graph, the x-intercept (where the line crosses the x-axis) can be approximated as (-2.5, 0).
3Step 3: Verify Intercepts Algebraically
To verify the y-intercept algebraically, set x to 0 in our equation, which gives \(y=4(0+3)-2 = 10\). This confirms the y-intercept. To verify the x-intercept, set y to 0 in the equation and solve for x, giving \(x = -\frac{10}{4} = -2.5\). This confirms our x-intercept.
Key Concepts
Graphing UtilityX-InterceptY-InterceptSlope-Intercept Form
Graphing Utility
Using a graphing utility is an invaluable skill when it comes to visualizing algebraic equations, especially linear ones. A graphing utility, such as a graphing calculator or software, allows you to input an equation and see its graph on a coordinate plane.
When you type in the linear equation, the tool plots it by computing and displaying numerous points that satisfy the equation, then connecting them to form a straight line. This visual representation helps to understand different attributes of the line such as its slope, direction, and intercepts.
A plus of using a graphing utility is that you can quickly approximate the points where the line crosses the axes, known as the x-intercept and y-intercept. Moreover, it serves as an excellent cross-verification tool for any algebraic solutions you arrive at.
When you type in the linear equation, the tool plots it by computing and displaying numerous points that satisfy the equation, then connecting them to form a straight line. This visual representation helps to understand different attributes of the line such as its slope, direction, and intercepts.
A plus of using a graphing utility is that you can quickly approximate the points where the line crosses the axes, known as the x-intercept and y-intercept. Moreover, it serves as an excellent cross-verification tool for any algebraic solutions you arrive at.
X-Intercept
The x-intercept of a graph is the point(s) at which the line crosses the x-axis. At these points, the value of y is zero because they lie on the x-axis. To find the x-intercept algebraically, you set the y variable to zero and solve the given equation for x.
For instance, in our equation from the exercise, setting y to zero, you would solve the equation \(0 = 4(x+3) - 2\) to find the x-intercept. After simplification, the x-intercept is \(-2.5\).
In addition to the algebraic method, you can visually approximate the x-intercept using a graphing utility. This not only simplifies the process but also confirms the algebraic result.
For instance, in our equation from the exercise, setting y to zero, you would solve the equation \(0 = 4(x+3) - 2\) to find the x-intercept. After simplification, the x-intercept is \(-2.5\).
In addition to the algebraic method, you can visually approximate the x-intercept using a graphing utility. This not only simplifies the process but also confirms the algebraic result.
Y-Intercept
The y-intercept is where the line crosses the y-axis, which happens at a point where x is zero. To find this algebraically, simply substitute zero for x in the equation and solve for y.
With the equation from the exercise, plugging in zero for x gives us \( y = 4(0+3) - 2 = 10 \), which indicates that the y-intercept is at the point (0,10). This approach of setting x to zero is always used to find the y-intercept of any line.
Graphing the equation with a graphing utility immediately shows the point on the graph where the line intersects the y-axis, further confirming what we found by calculation.
With the equation from the exercise, plugging in zero for x gives us \( y = 4(0+3) - 2 = 10 \), which indicates that the y-intercept is at the point (0,10). This approach of setting x to zero is always used to find the y-intercept of any line.
Graphing the equation with a graphing utility immediately shows the point on the graph where the line intersects the y-axis, further confirming what we found by calculation.
Slope-Intercept Form
The slope-intercept form of a line, given by \(y = mx + b\), is one of the most straightforward ways to write the equation of a line. In this form, \(m\) represents the slope of the line, and \(b\) is the y-intercept.
From our example, the equation can be rewritten in slope-intercept form as \(y = 4x + 10\), with 4 being the slope and 10 being the y-intercept. This tells us for every unit increase in x, y increases by 4 units, which shows the steepness of the line on the graph. Moreover, the y-intercept being 10 means the line crosses the y-axis at the point (0,10).
The slope-intercept form is especially useful because it directly provides both the slope and y-intercept, allowing for a quick sketch of the graph without needing a graphing utility.
From our example, the equation can be rewritten in slope-intercept form as \(y = 4x + 10\), with 4 being the slope and 10 being the y-intercept. This tells us for every unit increase in x, y increases by 4 units, which shows the steepness of the line on the graph. Moreover, the y-intercept being 10 means the line crosses the y-axis at the point (0,10).
The slope-intercept form is especially useful because it directly provides both the slope and y-intercept, allowing for a quick sketch of the graph without needing a graphing utility.
Other exercises in this chapter
Problem 18
Solve the inequality and sketch the solution on the real number line. Use a graphing utility to verify your solution graphically. $$-10 x \leq 40$$
View solution Problem 18
Solve the quadratic equation by factoring. Check your solutions in the original equation. $$-x^{2}-11 x=30$$
View solution Problem 18
Write the complex number in standard form. $$-i-(\sqrt{-23})^{2}$$
View solution Problem 18
Determine whether the equation is an identity, a conditional equation, or a contradiction. $$\frac{5}{x}+\frac{3}{x}=24$$
View solution